Fun ice cream-themed worksheet for practicing "10 more" and "10 less" math problems.

The task in the image is to determine 10 more and 10 less for each number provided. This involves basic arithmetic operations of addition and subtraction by 10.

Steps to Solve:

1. Identify the given numbers: Each ice cream cone contains a number.
2. Calculate 10 more: Add 10 to the given number.
3. Calculate 10 less: Subtract 10 from the given number.
4. Write the results: For each number, write both the result of adding 10 and subtracting 10.

Solution:

#### First Row:
- 34:
- 10 more: \( 34 + 10 = 44 \)
- 10 less: \( 34 - 10 = 24 \)
- 28:
- 10 more: \( 28 + 10 = 38 \)
- 10 less: \( 28 - 10 = 18 \)
- 76:
- 10 more: \( 76 + 10 = 86 \)
- 10 less: \( 76 - 10 = 66 \)
- 42:
- 10 more: \( 42 + 10 = 52 \)
- 10 less: \( 42 - 10 = 32 \)
- 18:
- 10 more: \( 18 + 10 = 28 \)
- 10 less: \( 18 - 10 = 8 \)

#### Second Row:
- 15:
- 10 more: \( 15 + 10 = 25 \)
- 10 less: \( 15 - 10 = 5 \)
- 61:
- 10 more: \( 61 + 10 = 71 \)
- 10 less: \( 61 - 10 = 51 \)
- 86:
- 10 more: \( 86 + 10 = 96 \)
- 10 less: \( 86 - 10 = 76 \)
- 49:
- 10 more: \( 49 + 10 = 59 \)
- 10 less: \( 49 - 10 = 39 \)
- 99:
- 10 more: \( 99 + 10 = 109 \)
- 10 less: \( 99 - 10 = 89 \)

#### Third Row:
- 83:
- 10 more: \( 83 + 10 = 93 \)
- 10 less: \( 83 - 10 = 73 \)
- 97:
- 10 more: \( 97 + 10 = 107 \)
- 10 less: \( 97 - 10 = 87 \)
- 52:
- 10 more: \( 52 + 10 = 62 \)
- 10 less: \( 52 - 10 = 42 \)
- 39:
- 10 more: \( 39 + 10 = 49 \)
- 10 less: \( 39 - 10 = 29 \)
- 12:
- 10 more: \( 12 + 10 = 22 \)
- 10 less: \( 12 - 10 = 2 \)

Final Answer:

\[
\boxed{
\begin{array}{ccccc}
\text{34} & \text{28} & \text{76} & \text{42} & \text{18} \\
\text{44, 24} & \text{38, 18} & \text{86, 66} & \text{52, 32} & \text{28, 8} \\
\text{15} & \text{61} & \text{86} & \text{49} & \text{99} \\
\text{25, 5} & \text{71, 51} & \text{96, 76} & \text{59, 39} & \text{109, 89} \\
\text{83} & \text{97} & \text{52} & \text{39} & \text{12} \\
\text{93, 73} & \text{107, 87} & \text{62, 42} & \text{49, 29} & \text{22, 2} \\
\end{array}
}
\]