Problem Description:
The task is to find the missing addend in each equation. The equations are structured as follows:
- Each equation has the form: `a + ? = b`, where `a` and `b` are given, and the missing addend (`?`) needs to be determined.
- The goal is to solve for the missing addend in each equation.
Solution Approach:
To find the missing addend, we use the basic property of addition:
\[
\text{Missing Addend} = \text{Total} - \text{Known Addend}
\]
In other words, for an equation `a + ? = b`, the missing addend is calculated as:
\[
? = b - a
\]
Step-by-Step Solution:
We will solve each equation one by one using the formula `? = b - a`.
#### First Row:
1. \( 8 + ? = 11 \)
\[
? = 11 - 8 = 3
\]
2. \( 4 + ? = 9 \)
\[
? = 9 - 4 = 5
\]
#### Second Row:
3. \( 5 + ? = 12 \)
\[
? = 12 - 5 = 7
\]
4. \( 6 + ? = 10 \)
\[
? = 10 - 6 = 4
\]
#### Third Row:
5. \( 6 + ? = 11 \)
\[
? = 11 - 6 = 5
\]
6. \( 2 + ? = 12 \)
\[
? = 12 - 2 = 10
\]
#### Fourth Row:
7. \( 7 + ? = 10 \)
\[
? = 10 - 7 = 3
\]
8. \( 5 + ? = 11 \)
\[
? = 11 - 5 = 6
\]
#### Fifth Row:
9. \( 3 + ? = 9 \)
\[
? = 9 - 3 = 6
\]
10. \( 7 + ? = 9 \)
\[
? = 9 - 7 = 2
\]
#### Sixth Row:
11. \( 4 + ? = 8 \)
\[
? = 8 - 4 = 4
\]
12. \( 3 + ? = 10 \)
\[
? = 10 - 3 = 7
\]
#### Seventh Row:
13. \( 2 + ? = 11 \)
\[
? = 11 - 2 = 9
\]
14. \( 9 + ? = 10 \)
\[
? = 10 - 9 = 1
\]
#### Eighth Row:
15. \( 9 + ? = 12 \)
\[
? = 12 - 9 = 3
\]
16. \( 8 + ? = 12 \)
\[
? = 12 - 8 = 4
\]
#### Ninth Row:
17. \( 1 + ? = 7 \)
\[
? = 7 - 1 = 6
\]
18. \( 0 + ? = 7 \)
\[
? = 7 - 0 = 7
\]
#### Tenth Row:
19. \( 0 + ? = 6 \)
\[
? = 6 - 0 = 6
\]
20. \( 1 + ? = 8 \)
\[
? = 8 - 1 = 7
\]
Final Answer:
The missing addends for each equation are:
\[
\boxed{
\begin{array}{cc}
3 & 5 \\
7 & 4 \\
5 & 10 \\
3 & 6 \\
6 & 2 \\
4 & 7 \\
9 & 1 \\
3 & 4 \\
6 & 7 \\
6 & 7 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of 1st grade math facts worksheet.