Printable math worksheet featuring two-step equation word problems for algebra practice.

It seems you've uploaded an image containing a worksheet titled "Two-Step Equation Word Problems." Below, I will solve each problem step by step and explain the solution.

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Problem 1:

Question:
350 students went on a field trip. They took 7 buses. How many students were in each bus?

Solution:
To find out how many students were in each bus, we need to divide the total number of students by the number of buses.

1. Total number of students = 350
2. Number of buses = 7
3. Students per bus = Total students ÷ Number of buses
\[
\text{Students per bus} = \frac{350}{7} = 50
\]

Answer:
Each bus had 50 students.

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Problem 2:

Question:
Allyah had $50 and spent it on some pencils. After buying the pencils, she had $15 left. How much did each pencil cost if she bought 5 pencils?

Solution:
First, determine how much money Allyah spent on the pencils. Then, calculate the cost per pencil.

1. Total money Allyah had initially = $50
2. Money left after buying pencils = $15
3. Money spent on pencils = Initial money - Money left
\[
\text{Money spent} = 50 - 15 = 35
\]
4. Number of pencils bought = 5
5. Cost per pencil = Money spent ÷ Number of pencils
\[
\text{Cost per pencil} = \frac{35}{5} = 7
\]

Answer:
Each pencil cost $7.

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Problem 3:

Question:
The sum of two consecutive numbers is 77. What are the values of these numbers?

Solution:
Let the first number be \( x \). Since the numbers are consecutive, the second number will be \( x + 1 \).

1. Sum of the two numbers = 77
\[
x + (x + 1) = 77
\]
2. Simplify the equation:
\[
2x + 1 = 77
\]
3. Subtract 1 from both sides:
\[
2x = 76
\]
4. Divide by 2:
\[
x = 38
\]
5. The second number is \( x + 1 = 38 + 1 = 39 \).

Answer:
The two consecutive numbers are 38 and 39.

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Problem 4:

Question:
The sum of three even numbers is 108. What is the value of these numbers?

Solution:
Let the first even number be \( x \). Since the numbers are consecutive even numbers, the second number will be \( x + 2 \), and the third number will be \( x + 4 \).

1. Sum of the three numbers = 108
\[
x + (x + 2) + (x + 4) = 108
\]
2. Simplify the equation:
\[
x + x + 2 + x + 4 = 108
\]
\[
3x + 6 = 108
\]
3. Subtract 6 from both sides:
\[
3x = 102
\]
4. Divide by 3:
\[
x = 34
\]
5. The second number is \( x + 2 = 34 + 2 = 36 \).
6. The third number is \( x + 4 = 34 + 4 = 38 \).

Answer:
The three even numbers are 34, 36, and 38.

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Problem 5:

Question:
You bought magazines for $42 and gave the cashier $50. How much change did you get back?

Solution:
To find the change, subtract the cost of the magazines from the amount given to the cashier.

1. Amount given to the cashier = $50
2. Cost of magazines = $42
3. Change received = Amount given - Cost of magazines
\[
\text{Change} = 50 - 42 = 8
\]

Answer:
You got back $8 in change.

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Problem 6:

Question:
Makayla bought twice as many books as her brother. A week later, she bought 6 more books, and her brother bought 4 more books. If Makayla now has 26 books, how many does her brother have?

Solution:
Let the number of books Makayla's brother originally bought be \( x \). Therefore, Makayla originally bought \( 2x \) books.

1. After a week, Makayla bought 6 more books. So, the total number of books Makayla has now is:
\[
2x + 6
\]
2. We are told that Makayla now has 26 books:
\[
2x + 6 = 26
\]
3. Solve for \( x \):
\[
2x + 6 = 26
\]
\[
2x = 26 - 6
\]
\[
2x = 20
\]
\[
x = 10
\]
4. Her brother originally bought \( x = 10 \) books. After buying 4 more books, her brother now has:
\[
10 + 4 = 14
\]

Answer:
Her brother now has 14 books.

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Problem 7:

Question:
Randy scored 24 points during his last basketball game. Larry scored only half as many points. How many points did Larry score?

Solution:
If Randy scored 24 points and Larry scored half as many points, then:

1. Points scored by Larry = \(\frac{1}{2}\) × Points scored by Randy
\[
\text{Larry's points} = \frac{1}{2} \times 24 = 12
\]

Answer:
Larry scored 12 points.

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Problem 8:

Question:
Dwayne spends about 2 hours playing video games every day. He usually allocates 1 hour playing solo and the rest with others. How many hours does he spend with others if he sticks to this routine for 7 days?

Solution:
Dwayne spends 1 hour playing solo each day, so the remaining time he spends with others is:

1. Total hours spent playing games per day = 2 hours
2. Hours spent playing solo per day = 1 hour
3. Hours spent playing with others per day = Total hours - Solo hours
\[
\text{Hours with others per day} = 2 - 1 = 1
\]
4. If Dwayne sticks to this routine for 7 days, the total hours spent with others over 7 days is:
\[
\text{Total hours with others} = 1 \times 7 = 7
\]

Answer:
Dwayne spends 7 hours playing with others over 7 days.

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Final Answers:

1. 50 students per bus
2. $7 per pencil
3. 38 and 39
4. 34, 36, and 38
5. $8
6. 14 books
7. 12 points
8. 7 hours

\boxed{50, 7, 38 \text{ and } 39, 34, 36, \text{ and } 38, 8, 14, 12, 7}