20+ Learning Activities and Printables for 2 Year Olds - Free Printable
Educational worksheet: 20+ Learning Activities and Printables for 2 Year Olds. Download and print for classroom or home learning activities.
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Step-by-step solution for: 20+ Learning Activities and Printables for 2 Year Olds
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Show Answer Key & Explanations
Step-by-step solution for: 20+ Learning Activities and Printables for 2 Year Olds
Let’s look at the image. It shows a large letter “K” made up of circles inside it. The task is likely to count how many circles are in the letter “K”.
Step 1: Look at the left vertical part of the K.
There are 7 circles stacked vertically.
Step 2: Look at the top diagonal part (going up to the right).
There are 3 circles there.
Step 3: Look at the bottom diagonal part (going down to the right).
There are 4 circles there.
Wait — let’s double-check by counting all circles one by one, going from top to bottom, left to right.
Left column (vertical):
Top to bottom — 1, 2, 3, 4, 5, 6, 7 → that’s 7.
Top-right diagonal (from center outward):
Starting from the middle circle (which we already counted? No — wait, let’s avoid double-counting).
Actually, better approach: Count every circle without skipping or repeating.
List them:
Left column:
- Top circle
- Second
- Third
- Fourth (center)
- Fifth
- Sixth
- Bottom → 7 total
Now the top-right arm:
- One above center (not in left column)
- One above that
- One at the very top → 3 more
Bottom-right arm:
- One below center (not in left column)
- One below that
- One below that
- One at the very bottom → 4 more
But wait — the center circle is shared? Actually, looking again — the center circle is part of the left column and also connects to both diagonals. But in the image, each circle is separate and not overlapping.
Let me recount visually as if I’m pointing:
Left side: 7 circles in a straight line.
Top-right branch: starts from the third circle from top on left? No — actually, the top-right diagonal has 3 circles: one near the top, one middle, one near the junction.
Similarly, bottom-right diagonal has 4 circles: one near junction, then three going down-right.
But the circle at the junction (where the two diagonals meet the left column) is already counted in the left column.
So:
Left column: 7 circles.
Top-right diagonal: adds 2 new circles (since the first one is already in left column? Wait no — looking at the image, the top-right diagonal does NOT include the center circle — it starts after.
Actually, let’s just count all visible circles:
I’ll number them mentally:
Left column (top to bottom):
1. Top-left
2. Below that
3. Below that
4. Center (middle of K)
5. Below center
6. Below that
7. Bottom-left → 7
Top-right diagonal (from center outward, not including center):
8. First circle on top-right
9. Second circle on top-right
10. Third circle at tip → 3 more
Bottom-right diagonal (from center outward, not including center):
11. First circle on bottom-right
12. Second
13. Third
14. Fourth at tip → 4 more
Total: 7 + 3 + 4 = 14
Wait — but is the center circle counted only once? Yes, because it’s only one circle.
In the left column, position 4 is the center.
The top-right diagonal starts with a circle that is NOT the center — it’s adjacent.
Same for bottom-right.
So total circles: 14.
Let me verify by another method: group them.
Group 1: Left vertical — 7 circles.
Group 2: Top-right arm — 3 circles (all distinct from left column).
Group 3: Bottom-right arm — 4 circles (all distinct from left column and top-right).
No overlaps — so 7 + 3 + 4 = 14.
Yes.
Final Answer:
14
Step 1: Look at the left vertical part of the K.
There are 7 circles stacked vertically.
Step 2: Look at the top diagonal part (going up to the right).
There are 3 circles there.
Step 3: Look at the bottom diagonal part (going down to the right).
There are 4 circles there.
Wait — let’s double-check by counting all circles one by one, going from top to bottom, left to right.
Left column (vertical):
Top to bottom — 1, 2, 3, 4, 5, 6, 7 → that’s 7.
Top-right diagonal (from center outward):
Starting from the middle circle (which we already counted? No — wait, let’s avoid double-counting).
Actually, better approach: Count every circle without skipping or repeating.
List them:
Left column:
- Top circle
- Second
- Third
- Fourth (center)
- Fifth
- Sixth
- Bottom → 7 total
Now the top-right arm:
- One above center (not in left column)
- One above that
- One at the very top → 3 more
Bottom-right arm:
- One below center (not in left column)
- One below that
- One below that
- One at the very bottom → 4 more
But wait — the center circle is shared? Actually, looking again — the center circle is part of the left column and also connects to both diagonals. But in the image, each circle is separate and not overlapping.
Let me recount visually as if I’m pointing:
Left side: 7 circles in a straight line.
Top-right branch: starts from the third circle from top on left? No — actually, the top-right diagonal has 3 circles: one near the top, one middle, one near the junction.
Similarly, bottom-right diagonal has 4 circles: one near junction, then three going down-right.
But the circle at the junction (where the two diagonals meet the left column) is already counted in the left column.
So:
Left column: 7 circles.
Top-right diagonal: adds 2 new circles (since the first one is already in left column? Wait no — looking at the image, the top-right diagonal does NOT include the center circle — it starts after.
Actually, let’s just count all visible circles:
I’ll number them mentally:
Left column (top to bottom):
1. Top-left
2. Below that
3. Below that
4. Center (middle of K)
5. Below center
6. Below that
7. Bottom-left → 7
Top-right diagonal (from center outward, not including center):
8. First circle on top-right
9. Second circle on top-right
10. Third circle at tip → 3 more
Bottom-right diagonal (from center outward, not including center):
11. First circle on bottom-right
12. Second
13. Third
14. Fourth at tip → 4 more
Total: 7 + 3 + 4 = 14
Wait — but is the center circle counted only once? Yes, because it’s only one circle.
In the left column, position 4 is the center.
The top-right diagonal starts with a circle that is NOT the center — it’s adjacent.
Same for bottom-right.
So total circles: 14.
Let me verify by another method: group them.
Group 1: Left vertical — 7 circles.
Group 2: Top-right arm — 3 circles (all distinct from left column).
Group 3: Bottom-right arm — 4 circles (all distinct from left column and top-right).
No overlaps — so 7 + 3 + 4 = 14.
Yes.
Final Answer:
14
Parent Tip: Review the logic above to help your child master the concept of 2 year old worksheets.