1st Grade Math Review Worksheet with Place Value, Expanded Form, and Number Bonds Exercises.

Let's solve the problems step by step.

Part 1: Find the answer

#### Question 1: Place value (tens and ones)
We need to break down each number into its tens and ones components.

1. 54 = _ tens _ ones
- The digit in the tens place is 5, and the digit in the ones place is 4.
- So, \( 54 = 5 \) tens and \( 4 \) ones.

2. 32 = _ tens _ ones
- The digit in the tens place is 3, and the digit in the ones place is 2.
- So, \( 32 = 3 \) tens and \( 2 \) ones.

3. 23 = _ tens _ ones
- The digit in the tens place is 2, and the digit in the ones place is 3.
- So, \( 23 = 2 \) tens and \( 3 \) ones.

#### Answer:
\[
\begin{aligned}
54 &= 5 \text{ tens } 4 \text{ ones} \\
32 &= 3 \text{ tens } 2 \text{ ones} \\
23 &= 2 \text{ tens } 3 \text{ ones}
\end{aligned}
\]

---

Part 2: Count

Count the blocks shown in the image:
- There are 4 large blocks (each representing 10) and 6 small blocks (each representing 1).
- Total: \( 4 \times 10 + 6 \times 1 = 40 + 6 = 46 \).

#### Answer:
\[
46
\]

---

Part 3: Expanded form

#### Question 1: Fill in the blanks for \( _ + _ = 65 \)
- We need two numbers that add up to 65.
- A common way is to split it into tens and ones: \( 60 + 5 = 65 \).

#### Question 2: Solve \( _ + 8 = 88 \)
- Let \( x \) be the missing number.
- \( x + 8 = 88 \)
- Subtract 8 from both sides: \( x = 88 - 8 = 80 \).

#### Question 3: Solve \( 80 + 3 = _ \)
- Add 80 and 3: \( 80 + 3 = 83 \).

#### Question 4: Solve \( 60 + _ = 68 \)
- Let \( y \) be the missing number.
- \( 60 + y = 68 \)
- Subtract 60 from both sides: \( y = 68 - 60 = 8 \).

#### Answer:
\[
\begin{aligned}
&60 + 5 = 65 \\
&80 + 8 = 88 \\
&80 + 3 = 83 \\
&60 + 8 = 68
\end{aligned}
\]

---

Part 4: Find the number bonds

#### Number bond 1:
- Top circle: 9
- Bottom circles: 4 and another number.
- The sum of the bottom circles must equal the top circle: \( 4 + ? = 9 \).
- Solve: \( ? = 9 - 4 = 5 \).

#### Number bond 2:
- Top circle: 2
- Bottom circles: 1 and another number.
- The sum of the bottom circles must equal the top circle: \( 1 + ? = 2 \).
- Solve: \( ? = 2 - 1 = 1 \).

#### Answer:
\[
\begin{aligned}
&\text{For the first number bond: } 9 = 4 + 5 \\
&\text{For the second number bond: } 2 = 1 + 1
\end{aligned}
\]

---

Final Answer:

\[
\boxed{
\begin{aligned}
&54 = 5 \text{ tens } 4 \text{ ones} \\
&32 = 3 \text{ tens } 2 \text{ ones} \\
&23 = 2 \text{ tens } 3 \text{ ones} \\
&46 \\
&60 + 5 = 65 \\
&80 + 8 = 88 \\
&80 + 3 = 83 \\
&60 + 8 = 68 \\
&9 = 4 + 5 \\
&2 = 1 + 1
\end{aligned}
}
\]