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Division Word Problems for Grade 3 | Grade1to6.com - Free Printable

Division Word Problems for Grade 3 | Grade1to6.com

Educational worksheet: Division Word Problems for Grade 3 | Grade1to6.com. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Division Word Problems for Grade 3 | Grade1to6.com
Let's solve each problem step by step:

---

Problem 1:


A farmer has 40 apple seeds. He wants to plant them in rows of 4. How many rows can he plant?

- Given:
Total apple seeds = 40
Seeds per row = 4

- To find:
Number of rows

- Solution:
We need to divide the total number of apple seeds by the number of seeds per row:
\[
\text{Number of rows} = \frac{\text{Total apple seeds}}{\text{Seeds per row}} = \frac{40}{4} = 10
\]

- Answer:
\[
\boxed{10}
\]

---

Problem 2:


A mobile shop gets 50 new mobile phones which he has to arrange in 10 rows. How many rows he needs to ensure every row has the same number of mobile phones?

- Given:
Total mobile phones = 50
Number of rows = 10

- To find:
Number of mobile phones per row

- Solution:
We need to divide the total number of mobile phones by the number of rows:
\[
\text{Mobile phones per row} = \frac{\text{Total mobile phones}}{\text{Number of rows}} = \frac{50}{10} = 5
\]

- Answer:
\[
\boxed{5}
\]

---

Problem 3:


Jack has 51 chocolates. His mum asked him to divide them equally amongst his 8 friends and keep the rest for himself. How many will he have for himself?

- Given:
Total chocolates = 51
Number of friends = 8

- To find:
Number of chocolates Jack keeps for himself

- Solution:
First, we divide the total chocolates by the number of friends to find out how many chocolates each friend gets and how many are left over:
\[
\text{Chocolates per friend} = \frac{\text{Total chocolates}}{\text{Number of friends}} = \frac{51}{8}
\]
Performing the division:
\[
51 \div 8 = 6 \text{ R } 3
\]
This means each friend gets 6 chocolates, and there are 3 chocolates left over.

- Answer:
\[
\boxed{3}
\]

---

Problem 4:


A commercial goods train consists of an engine and a number of bogies. Each bogie is 24 metres long. The total length of the good train is 264 metres. How many bogies does the engine pull?

- Given:
Total length of the train = 264 metres
Length of each bogie = 24 metres

- To find:
Number of bogies

- Solution:
To find the number of bogies, we divide the total length of the train by the length of each bogie:
\[
\text{Number of bogies} = \frac{\text{Total length of the train}}{\text{Length of each bogie}} = \frac{264}{24}
\]
Performing the division:
\[
264 \div 24 = 11
\]

- Answer:
\[
\boxed{11}
\]

---

Problem 5:


The polar bear eats fish. Each polar bear needs 12 fish. You have 36 fish. How many bears can you feed?

- Given:
Total fish = 36
Fish needed per bear = 12

- To find:
Number of bears that can be fed

- Solution:
We need to divide the total number of fish by the number of fish needed per bear:
\[
\text{Number of bears} = \frac{\text{Total fish}}{\text{Fish needed per bear}} = \frac{36}{12} = 3
\]

- Answer:
\[
\boxed{3}
\]

---

Final Answers:


1. \(\boxed{10}\)
2. \(\boxed{5}\)
3. \(\boxed{3}\)
4. \(\boxed{11}\)
5. \(\boxed{3}\)
Parent Tip: Review the logic above to help your child master the concept of 3rd grade division word problems.
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