Explanation:
We need to find the fraction of the shaded area in each shape. A fraction means:
shaded parts / total equal parts
Let’s go one by one:
1) Octagon divided into 8 equal triangles. 4 are shaded (teal).
→ 4/8 =
1/2
2) Circle divided into 8 equal slices. 1 slice is shaded green.
→ 1/8
3) Circle divided into 4 equal quadrants. 1 is shaded gray.
→ 1/4
4) Hexagon divided into 6 equal triangles. 2 are shaded green.
→ 2/6 =
1/3
5) Cube-like net? Wait — it's a hexagon made of 6 small equilateral triangles (like a regular hexagon split from center). Two triangles are shaded (orange and white? No — look: only 1 triangle is orange, 1 is white, rest are unshaded? Actually, the figure shows a hexagon divided into 6 small triangles, with
1 orange triangle shaded, and the rest are white or gray (unshaded). So only 1 out of 6 is shaded.
→ 1/6
6) Rectangle divided into 4 equal vertical strips. 2 are shaded purple.
→ 2/4 =
1/2
7) Pentagon divided into 5 equal triangles (from center). 2 are shaded teal.
→ 2/5
8) Circle divided into 6 equal slices. 2 are shaded yellow.
→ 2/6 =
1/3
9) Triangle divided into 4 smaller congruent triangles (by connecting midpoints). Only 1 is shaded red.
→ 1/4
10) Square divided into 4 equal right triangles (by both diagonals). 2 are shaded blue.
→ 2/4 =
1/2
Let me double-check each carefully:
1) 8 parts, 4 shaded → 4/8 = 1/2
✔
2) 8 slices, 1 green → 1/8
✔
3) 4 quadrants, 1 gray → 1/4
✔
4) Hexagon: yes, 6 triangles, 2 green → 2/6 = 1/3
✔
5) Hexagon split into 6 triangles: only 1 orange shaded → 1/6
✔
6) 4 bars, 2 purple → 2/4 = 1/2
✔
7) Pentagon: 5 triangles, 2 teal → 2/5
✔
8) Circle: 6 slices, 2 yellow → 2/6 = 1/3
✔
9) Large triangle split into 4 small ones (like Sierpinski step 1), 1 red → 1/4
✔
10) Square with X-diagonals → 4 triangles, 2 blue → 2/4 = 1/2
✔
All correct.
Final Answer:
1) 1/2
2) 1/8
3) 1/4
4) 1/3
5) 1/6
6) 1/2
7) 2/5
8) 1/3
9) 1/4
10) 1/2
Parent Tip: Review the logic above to help your child master the concept of 3rd grade fraction problems.
