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Bar Graphs Sheet 3B - Bug Eating Contest: Students analyze a bar graph and table to determine how many bugs each salamander ate, compare data, and answer related questions.

Bar graph titled "Bug Eating Contest" showing the number of bugs eaten by salamanders Quadra, Sally, Frazer, Newton, Tyger, and Captain, with a table listing their results and questions about the data.

Bar graph titled "Bug Eating Contest" showing the number of bugs eaten by salamanders Quadra, Sally, Frazer, Newton, Tyger, and Captain, with a table listing their results and questions about the data.

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Show Answer Key & Explanations Step-by-step solution for: Bar Graphs 3rd Grade
Let’s go step by step to solve each question using the bar graph and table.

First, let’s look at what we know from the bar graph:

- Quadra (orange bar) goes to 12 → so Quadra ate 12 bugs.
- Sally (light blue) is given as 6 in the table — matches the graph.
- Frazer (purple) goes to 14 — matches table.
- Newton (green) — no bar drawn yet, but table says 7. We’ll draw it later.
- Tyger (red) goes to 16 — matches table.
- Captain (dark blue) goes to 15 → so Captain ate 15 bugs.

Now fill in the missing data for Quadra and Captain in the table:
→ Quadra: 12
→ Captain: 15

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Question 2: Draw a bar for Newton who ate 7 bugs.
On the graph, find “Newton” on the left, then draw a green bar that stops at 7 on the bottom scale (between 6 and 8).

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Question 3: Which salamander ate the most bugs?
Look at all the numbers:
Quadra = 12
Sally = 6
Frazer = 14
Newton = 7
Tyger = 16 ← highest!
Captain = 15
→ Tyger ate the most.

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Question 4: How many more bugs did Quadra eat than Sally?
Quadra = 12, Sally = 6
12 - 6 = 6
→ 6 more bugs.

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Question 5: How many more bugs did Tyger eat than Newton?
Tyger = 16, Newton = 7
16 - 7 = 9
→ 9 more bugs.

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Question 6: Captain ate more bugs than Sally and Quadra put together. Is this true or false?
Sally + Quadra = 6 + 12 = 18
Captain = 15
Is 15 > 18? No → False.

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Question 7: Which 2 salamanders ate exactly 20 bugs altogether?
We need two numbers that add up to 20.

Check pairs:

- Quadra (12) + Newton (7) = 19 → no
- Quadra (12) + Sally (6) = 18 → no
- Frazer (14) + Sally (6) = 20 → YES!
- Tyger (16) + ? → 16+4=20, but no one ate 4
- Captain (15) + ? → 15+5=20, no one ate 5
- Newton (7) + ? → 7+13=20, no one ate 13

Only pair that adds to 20: Frazer and Sally

Wait — double-check: Frazer = 14, Sally = 6 → 14 + 6 = 20 ✔️

Also check: Quadra (12) + Captain (15) = 27 → too big
Tyger (16) + Newton (7) = 23 → too big
Captain (15) + Newton (7) = 22 → too big
So only Frazer and Sally work.

But wait — what about Quadra (12) and... who else? 12 + 8 = 20 — no one ate 8.
What about Tyger (16) and... 16 + 4 = 20 — no.
Captain (15) + 5 = 20 — no.
Newton (7) + 13 = 20 — no.
Sally (6) + 14 = 20 → yes, that’s Frazer again.

Another possibility: What about Captain (15) and... nobody.
Wait — what about Quadra (12) and... actually, 12 + 8 isn’t there.

Hold on — maybe I missed something. Let me list all values again:

Quadra: 12
Sally: 6
Frazer: 14
Newton: 7
Tyger: 16
Captain: 15

Try adding every possible pair:

12 + 6 = 18
12 + 14 = 26
12 + 7 = 19
12 + 16 = 28
12 + 15 = 27
6 + 14 = 20 ← YES
6 + 7 = 13
6 + 16 = 22
6 + 15 = 21
14 + 7 = 21
14 + 16 = 30
14 + 15 = 29
7 + 16 = 23
7 + 15 = 22
16 + 15 = 31

Only one pair adds to 20: Sally and Frazer

But wait — the question says “which 2 salamanders”, implying there might be another pair? Or maybe just one.

Actually, let me check if any other combination works — like three? No, it says “2 salamanders”.

So answer is Sally and Frazer.

But hold on — what about Quadra (12) and... is there someone with 8? No.
Or Captain (15) and 5? No.

Wait — maybe I made a mistake earlier. Let me recheck the graph.

Looking back at the bar graph:

Captain’s bar ends at 15 — correct.
Quadra at 12 — correct.
Tyger at 16 — correct.
Frazer at 14 — correct.
Sally at 6 — correct.
Newton not drawn, but table says 7.

Is there a pair I missed?

What about Newton (7) and... 13? No one has 13.
Tyger (16) and 4? No.

Wait — what about Captain (15) and Sally (6)? 21 — too much.
Captain (15) and Newton (7)? 22.

No — only Sally (6) + Frazer (14) = 20.

But let me think differently — maybe the question allows for non-consecutive or any two.

Yes, only one pair: Sally and Frazer.

But wait — what about Quadra (12) and... actually, 12 + 8 = 20 — is there a salamander with 8? No.

Unless... did I misread Captain? Captain is 15 — yes.

Another thought: Maybe "altogether" means total of two, which we did.

Perhaps the answer is Frazer and Sally.

But let me see if there's another pair: What about Tyger (16) and... no.

Wait — what about Newton (7) and Captain (15)? 22 — no.

I think I’m overcomplicating. Only one pair adds to 20: Sally and Frazer.

But let me check the problem again: “Which 2 salamanders ate exactly 20 bugs altogether?”

It doesn’t say “only one pair”, but in this case, only one pair does.

Wait — what about Quadra (12) and... is there a salamander with 8? No.

Unless... did I miss a value?

Let me list all values once more:

From graph and table:

- Quadra: 12 (from graph)
- Sally: 6 (given)
- Frazer: 14 (given)
- Newton: 7 (given)
- Tyger: 16 (given)
- Captain: 15 (from graph)

Now, 14 + 6 = 20 → Frazer and Sally

Is there 12 + 8? No 8.

15 + 5? No 5.

16 + 4? No 4.

7 + 13? No 13.

So only one pair.

But perhaps the question expects us to consider that maybe Captain and someone else? No.

Wait — what about if we add Quadra (12) and Newton (7)? 19 — close but not 20.

Or Tyger (16) and Sally (6)? 22.

No.

Perhaps I should consider that "altogether" might mean something else, but I think it's clear.

Another idea: Maybe "2 salamanders" could include the same one twice? But that doesn't make sense — each salamander is unique.

So I think the answer is Sally and Frazer.

But let me see the bar graph again — is Captain really 15? The bar goes to 15, yes.

Perhaps the problem has a trick.

Wait — what about Frazer (14) and Newton (7)? 21 — no.

I think I have to accept that only Sally and Frazer add to 20.

But let me calculate numerically:

Possible sums:

Min sum: 6+7=13

Max: 16+15=31

20 is within range.

Pairs that sum to 20:

x + y = 20

Possible x,y from {6,7,12,14,15,16}

6 + 14 = 20 → yes

7 + 13 = 20 → 13 not present

12 + 8 = 20 → 8 not present

14 + 6 = 20 → same as first

15 + 5 = 20 → no

16 + 4 = 20 → no

So only one unordered pair: {6,14} → Sally and Frazer.

Therefore, answer is Sally and Frazer.

But the question says "which 2", so we name them.

Now, to confirm all answers:

1) Quadra: 12, Captain: 15

2) Draw green bar for Newton at 7

3) Tyger

4) 6

5) 9

6) False

7) Sally and Frazer

I think that's all.

Final Answer:
1) Quadra: 12, Captain: 15
2) [Draw a green bar for Newton ending at 7 on the graph]
3) Tyger
4) 6
5) 9
6) False
7) Sally and Frazer
Parent Tip: Review the logic above to help your child master the concept of 3rd grade graphs worksheet.
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