Sunshine Math - 3 worksheet featuring math exercises for third-grade students.
A worksheet titled "Sunshine Math - 3" with math problems, including number sequences, a grid puzzle, and a question about the sum of numbers in a grid.
JPG
228×295
6.5 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #805153
⭐
Show Answer Key & Explanations
Step-by-step solution for: Mixed Problems- Logical Reasoning Worksheet for 3rd Grade | Lesson ...
▼
Show Answer Key & Explanations
Step-by-step solution for: Mixed Problems- Logical Reasoning Worksheet for 3rd Grade | Lesson ...
Problem Analysis:
The image contains a math worksheet with several problems. Let's solve each problem step by step.
---
#### Problem 1:
Task: Find the missing number in the following sequence using the given pattern:
$$
28 : 7 \quad 20 : 5 \quad 16 : 4 \quad 12 : ?
$$
Solution:
1. Analyze the given pairs:
- $ 28 : 7 $: Here, $ 28 \div 7 = 4 $.
- $ 20 : 5 $: Here, $ 20 \div 5 = 4 $.
- $ 16 : 4 $: Here, $ 16 \div 4 = 4 $.
2. Identify the pattern:
- In each pair, the first number is divided by the second number to get the result $ 4 $.
3. Apply the pattern to the last pair:
- For $ 12 : ? $, we need $ 12 \div ? = 4 $.
- Solving for $ ? $:
$$
? = \frac{12}{4} = 3
$$
Answer:
$$
\boxed{3}
$$
---
#### Problem 2:
Task: John is buying fish from a local market. Each fish costs $ ₹ 5 $. If he has $ ₹ 20 $, how many fish can he buy?
Solution:
1. Determine the cost of one fish:
- Each fish costs $ ₹ 5 $.
2. Calculate how many fish John can buy with $ ₹ 20 $:
- Number of fish = Total money / Cost per fish
- Number of fish = $ \frac{20}{5} = 4 $
Answer:
$$
\boxed{4}
$$
---
#### Problem 3:
Task: Fill in the blanks in the table below using the given pattern:
$$
\begin{array}{|c|c|c|}
\hline
1 & 6 & 12 \\
\hline
2 & 3 & 11 \\
\hline
& & 10 \\
\hline
\end{array}
$$
Solution:
1. Analyze the given rows:
- Row 1: $ 1, 6, 12 $
- Row 2: $ 2, 3, 11 $
2. Identify the pattern:
- In Row 1:
- The first number is $ 1 $.
- The second number is $ 6 $.
- The third number is $ 12 $.
- In Row 2:
- The first number is $ 2 $.
- The second number is $ 3 $.
- The third number is $ 11 $.
3. Look for relationships:
- Notice that the third number in each row seems to be related to the first two numbers.
- For Row 1: $ 1 + 6 + 5 = 12 $.
- For Row 2: $ 2 + 3 + 6 = 11 $.
4. Generalize the pattern:
- The third number in each row is the sum of the first two numbers plus an incrementing value ($ 5, 6, \ldots $).
5. Apply the pattern to the third row:
- Let the first number be $ x $ and the second number be $ y $.
- The third number is $ x + y + 7 $ (since the increment increases by 1 each time).
- Given the third number is $ 10 $:
$$
x + y + 7 = 10
$$
$$
x + y = 3
$$
6. Choose values for $ x $ and $ y $ that satisfy $ x + y = 3 $:
- One possible solution is $ x = 1 $ and $ y = 2 $.
Answer:
$$
\boxed{1, 2}
$$
---
#### Problem 4:
Task: Raviya is 7 years older than her sister. If their ages are added together, they are 19 years old. How old is Raviya? How old is her sister?
Solution:
1. Define variables:
- Let Raviya's age be $ R $.
- Let her sister's age be $ S $.
2. Set up equations based on the problem:
- Equation 1: Raviya is 7 years older than her sister:
$$
R = S + 7
$$
- Equation 2: The sum of their ages is 19:
$$
R + S = 19
$$
3. Substitute $ R = S + 7 $ into the second equation:
$$
(S + 7) + S = 19
$$
$$
2S + 7 = 19
$$
4. Solve for $ S $:
$$
2S = 19 - 7
$$
$$
2S = 12
$$
$$
S = 6
$$
5. Find Raviya's age:
$$
R = S + 7 = 6 + 7 = 13
$$
Answer:
- Raviya is $ \boxed{13} $ years old.
- Her sister is $ \boxed{6} $ years old.
---
Final Answers:
1. $ \boxed{3} $
2. $ \boxed{4} $
3. $ \boxed{1, 2} $
4. Raviya: $ \boxed{13} $, Sister: $ \boxed{6} $
Parent Tip: Review the logic above to help your child master the concept of 3rd grade math reasoning worksheet.