Area and Perimeter of Rectangles Worksheets - Math Monks - Free Printable

To solve the problem, we need to calculate the area and perimeter of each rectangle. The formulas for these are:

- Area of a rectangle: \( \text{Area} = \text{length} \times \text{width} \)
- Perimeter of a rectangle: \( \text{Perimeter} = 2 \times (\text{length} + \text{width}) \)

Let's solve each rectangle step by step.

---

Rectangle 1

- Dimensions: Length = 6 cm, Width = 1½ cm = 1.5 cm
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 6 \times 1.5 = 9 \, \text{cm}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (6 + 1.5) = 2 \times 7.5 = 15 \, \text{cm}
\]

Answers for Rectangle 1:
- Area = 9 cm²
- Perimeter = 15 cm

---

Rectangle 2

- Dimensions: Length = 5½ m = 5.5 m, Width = 3 m
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 5.5 \times 3 = 16.5 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (5.5 + 3) = 2 \times 8.5 = 17 \, \text{m}
\]

Answers for Rectangle 2:
- Area = 16.5 m²
- Perimeter = 17 m

---

Rectangle 3

- Dimensions: Length = 5 ft, Width = 2½ ft = 2.5 ft
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 5 \times 2.5 = 12.5 \, \text{ft}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (5 + 2.5) = 2 \times 7.5 = 15 \, \text{ft}
\]

Answers for Rectangle 3:
- Area = 12.5 ft²
- Perimeter = 15 ft

---

Rectangle 4

- Dimensions: Length = 20 cm, Width = 7 cm
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 20 \times 7 = 140 \, \text{cm}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (20 + 7) = 2 \times 27 = 54 \, \text{cm}
\]

Answers for Rectangle 4:
- Area = 140 cm²
- Perimeter = 54 cm

---

Rectangle 5

- Dimensions: Length = 8 cm, Width = 3½ cm = 3.5 cm
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 8 \times 3.5 = 28 \, \text{cm}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (8 + 3.5) = 2 \times 11.5 = 23 \, \text{cm}
\]

Answers for Rectangle 5:
- Area = 28 cm²
- Perimeter = 23 cm

---

Rectangle 6

- Dimensions: Length = 30 m, Width = 20 m
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 30 \times 20 = 600 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (30 + 20) = 2 \times 50 = 100 \, \text{m}
\]

Answers for Rectangle 6:
- Area = 600 m²
- Perimeter = 100 m

---

Final Answers

1. Area = 9 cm², Perimeter = 15 cm
2. Area = 16.5 m², Perimeter = 17 m
3. Area = 12.5 ft², Perimeter = 15 ft
4. Area = 140 cm², Perimeter = 54 cm
5. Area = 28 cm², Perimeter = 23 cm
6. Area = 600 m², Perimeter = 100 m

\boxed{
\begin{array}{ll}
1. & \text{Area} = 9 \, \text{cm}^2, \, \text{Perimeter} = 15 \, \text{cm} \\
2. & \text{Area} = 16.5 \, \text{m}^2, \, \text{Perimeter} = 17 \, \text{m} \\
3. & \text{Area} = 12.5 \, \text{ft}^2, \, \text{Perimeter} = 15 \, \text{ft} \\
4. & \text{Area} = 140 \, \text{cm}^2, \, \text{Perimeter} = 54 \, \text{cm} \\
5. & \text{Area} = 28 \, \text{cm}^2, \, \text{Perimeter} = 23 \, \text{cm} \\
6. & \text{Area} = 600 \, \text{m}^2, \, \text{Perimeter} = 100 \, \text{m} \\
\end{array}
}