Math puzzles designed for grades 3-8 with interactive problems using symbols and numbers.

Problem Analysis and Solution

The image contains three sets of math puzzles, each targeted at different grade levels. Below, I will solve each puzzle step by step.

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#### Grades 1-3 Puzzle
Puzzle:
1. \( 26 - \text{(flower)} = \text{(lime)} \)
2. \( \text{(lime)} + \text{(lime)} = 2 \)
3. \( \text{(apple)} + \text{(strawberry)} = \text{(lime)} + 9 \)
4. \( ? \)

Solution:

1. From the second equation:
\[
\text{(lime)} + \text{(lime)} = 2 \implies 2 \times \text{(lime)} = 2 \implies \text{(lime)} = 1
\]

2. Substitute \(\text{(lime)} = 1\) into the first equation:
\[
26 - \text{(flower)} = 1 \implies \text{(flower)} = 26 - 1 = 25
\]

3. Substitute \(\text{(lime)} = 1\) into the third equation:
\[
\text{(apple)} + \text{(strawberry)} = \text{(lime)} + 9 \implies \text{(apple)} + \text{(strawberry)} = 1 + 9 = 10
\]

4. The fourth equation is missing, but we can infer it might ask for the value of another fruit or symbol. Since no additional information is provided, we assume the task is to find the values of the symbols we have determined so far:
- \(\text{(flower)} = 25\)
- \(\text{(lime)} = 1\)
- \(\text{(apple)} + \text{(strawberry)} = 10\)

Thus, the solution for Grades 1-3 is:
\[
\boxed{25, 1, 10}
\]

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#### Grades 4-5 Puzzle
Puzzle:
1. \( \text{(book)} \times \text{(pencil)} = 121 \)
2. \( 12 \times \text{(book)} = 132 \)
3. \( \text{(calculator)} = 20 - \text{(pencil)} \)
4. \( \text{(game controller)} - \text{(pencil)} = 7 \)
5. \( ? \)

Solution:

1. From the second equation:
\[
12 \times \text{(book)} = 132 \implies \text{(book)} = \frac{132}{12} = 11
\]

2. Substitute \(\text{(book)} = 11\) into the first equation:
\[
\text{(book)} \times \text{(pencil)} = 121 \implies 11 \times \text{(pencil)} = 121 \implies \text{(pencil)} = \frac{121}{11} = 11
\]

3. Substitute \(\text{(pencil)} = 11\) into the third equation:
\[
\text{(calculator)} = 20 - \text{(pencil)} \implies \text{(calculator)} = 20 - 11 = 9
\]

4. Substitute \(\text{(pencil)} = 11\) into the fourth equation:
\[
\text{(game controller)} - \text{(pencil)} = 7 \implies \text{(game controller)} - 11 = 7 \implies \text{(game controller)} = 7 + 11 = 18
\]

5. The fifth equation is missing, but we can infer it might ask for the value of another object or symbol. Since no additional information is provided, we assume the task is to find the values of the symbols we have determined so far:
- \(\text{(book)} = 11\)
- \(\text{(pencil)} = 11\)
- \(\text{(calculator)} = 9\)
- \(\text{(game controller)} = 18\)

Thus, the solution for Grades 4-5 is:
\[
\boxed{11, 11, 9, 18}
\]

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#### Grades 6-8 Puzzle
Puzzle:
1. \( 48 = \text{(cupcake)} + \text{(spoon)} + \text{(spoon)} \)
2. \( \text{(lemon)} \times \text{(cookie)} = 0 \)
3. \( \text{(teddy bear)} = \text{(spoon)} + \text{(cookie)} \)
4. \( \text{(teddy bear)} = \text{(spoon)} + \text{(cookie)} \)
5. \( \text{(cupcake)} + \text{(teddy bear)} + \text{(spoon)} = ? \)

Solution:

1. From the second equation:
\[
\text{(lemon)} \times \text{(cookie)} = 0
\]
Since the product is zero, either \(\text{(lemon)} = 0\) or \(\text{(cookie)} = 0\). Without loss of generality, let \(\text{(cookie)} = 0\).

2. Substitute \(\text{(cookie)} = 0\) into the third equation:
\[
\text{(teddy bear)} = \text{(spoon)} + \text{(cookie)} \implies \text{(teddy bear)} = \text{(spoon)} + 0 \implies \text{(teddy bear)} = \text{(spoon)}
\]

3. From the first equation:
\[
48 = \text{(cupcake)} + \text{(spoon)} + \text{(spoon)} \implies 48 = \text{(cupcake)} + 2 \times \text{(spoon)}
\]

4. Let \(\text{(spoon)} = x\). Then:
\[
48 = \text{(cupcake)} + 2x \implies \text{(cupcake)} = 48 - 2x
\]

5. From the fifth equation:
\[
\text{(cupcake)} + \text{(teddy bear)} + \text{(spoon)} = ?
\]
Substitute \(\text{(teddy bear)} = x\) and \(\text{(cupcake)} = 48 - 2x\):
\[
\text{(cupcake)} + \text{(teddy bear)} + \text{(spoon)} = (48 - 2x) + x + x = 48
\]

Thus, the solution for Grades 6-8 is:
\[
\boxed{48}
\]

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Final Answers:

1. Grades 1-3: \(\boxed{25, 1, 10}\)
2. Grades 4-5: \(\boxed{11, 11, 9, 18}\)
3. Grades 6-8: \(\boxed{48}\)