Fourth Grade Math Worksheets - Twisty Noodle - Free Printable
Educational worksheet: Fourth Grade Math Worksheets - Twisty Noodle. Download and print for classroom or home learning activities.
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Step-by-step solution for: Fourth Grade Math Worksheets - Twisty Noodle
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Show Answer Key & Explanations
Step-by-step solution for: Fourth Grade Math Worksheets - Twisty Noodle
Let’s solve each fraction subtraction problem step by step. Remember: when subtracting fractions with the same denominator, you just subtract the numerators and keep the denominator the same.
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1. $\frac{2}{5} - \frac{1}{5}$
Subtract numerators: $2 - 1 = 1$
Keep denominator: 5
→ $\frac{1}{5}$
2. $\frac{4}{9} - \frac{1}{9}$
$4 - 1 = 3$, denominator stays 9 → $\frac{3}{9}$
Simplify: divide numerator and denominator by 3 → $\frac{1}{3}$
3. $\frac{5}{7} + \frac{1}{7}$ ← Wait! This is addition, not subtraction. Let me check again — actually, looking at the image, this row says “+”, but all others are “-”. Hmm… maybe it’s a typo? But let’s follow what’s written.
Actually, rechecking the original problem list — in the user’s input, line 3 is:
$\frac{5}{7} + \frac{1}{7}$ — so yes, it’s addition.
But wait — the rest of the problems are subtractions. Maybe it’s meant to be subtraction? Let me double-check the original image description.
Looking back: The user wrote:
> $\frac{2}{5} - \frac{1}{5} =$
> $\frac{4}{9} - \frac{1}{9} =$
> $\frac{5}{7} + \frac{1}{7} =$ ← this one has a plus sign
> $\frac{2}{4} + \frac{1}{4} =$ ← also plus
> ... etc.
Wait — actually, scanning through, some rows have “+” and some have “-”. So we must do exactly as written.
So let’s go carefully:
---
Row 1: $\frac{2}{5} - \frac{1}{5} = \frac{1}{5}$ ✔
Row 2: $\frac{4}{9} - \frac{1}{9} = \frac{3}{9} = \frac{1}{3}$ ✔
Row 3: $\frac{5}{7} + \frac{1}{7} = \frac{6}{7}$ (add numerators) ✔
Row 4: $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$ ✔
Row 5: $\frac{7}{10} - \frac{4}{10} = \frac{3}{10}$ ✔
Row 6: $\frac{4}{6} - \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$ ✔
Row 7: $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$ ✔ (same as row 4)
Row 8: $\frac{2}{11} + \frac{1}{11} = \frac{3}{11}$ ✔
Row 9: $\frac{1}{3} + \frac{1}{3} = \frac{2}{3}$ ✔
Row 10: $\frac{2}{3} - \frac{1}{3} = \frac{1}{3}$ ✔
Row 11: $\frac{3}{8} - \frac{1}{8} = \frac{2}{8} = \frac{1}{4}$ ✔
Row 12: $\frac{4}{12} - \frac{1}{12} = \frac{3}{12} = \frac{1}{4}$ ✔
Row 13: $\frac{3}{6} + \frac{1}{6} = \frac{4}{6} = \frac{2}{3}$ ✔
Row 14: $\frac{3}{5} - \frac{2}{5} = \frac{1}{5}$ ✔
---
Now, let’s write them in order as they appear in the worksheet (left column first, then right column):
Left Column:
1. $\frac{2}{5} - \frac{1}{5} = \frac{1}{5}$
2. $\frac{5}{7} + \frac{1}{7} = \frac{6}{7}$
3. $\frac{7}{10} - \frac{4}{10} = \frac{3}{10}$
4. $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$
5. $\frac{1}{3} + \frac{1}{3} = \frac{2}{3}$
6. $\frac{3}{8} - \frac{1}{8} = \frac{1}{4}$
7. $\frac{3}{6} + \frac{1}{6} = \frac{2}{3}$
Right Column:
1. $\frac{4}{9} - \frac{1}{9} = \frac{1}{3}$
2. $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$
3. $\frac{4}{6} - \frac{1}{6} = \frac{1}{2}$
4. $\frac{2}{11} + \frac{1}{11} = \frac{3}{11}$
5. $\frac{2}{3} - \frac{1}{3} = \frac{1}{3}$
6. $\frac{4}{12} - \frac{1}{12} = \frac{1}{4}$
7. $\frac{3}{5} - \frac{2}{5} = \frac{1}{5}$
Wait — I think I miscounted the rows. Let me recount based on the original layout.
Original has 7 rows, each with two problems (left and right).
So:
Row 1 Left: $\frac{2}{5} - \frac{1}{5} = \frac{1}{5}$
Row 1 Right: $\frac{4}{9} - \frac{1}{9} = \frac{3}{9} = \frac{1}{3}$
Row 2 Left: $\frac{5}{7} + \frac{1}{7} = \frac{6}{7}$
Row 2 Right: $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$
Row 3 Left: $\frac{7}{10} - \frac{4}{10} = \frac{3}{10}$
Row 3 Right: $\frac{4}{6} - \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$
Row 4 Left: $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$
Row 4 Right: $\frac{2}{11} + \frac{1}{11} = \frac{3}{11}$
Row 5 Left: $\frac{1}{3} + \frac{1}{3} = \frac{2}{3}$
Row 5 Right: $\frac{2}{3} - \frac{1}{3} = \frac{1}{3}$
Row 6 Left: $\frac{3}{8} - \frac{1}{8} = \frac{2}{8} = \frac{1}{4}$
Row 6 Right: $\frac{4}{12} - \frac{1}{12} = \frac{3}{12} = \frac{1}{4}$
Row 7 Left: $\frac{3}{6} + \frac{1}{6} = \frac{4}{6} = \frac{2}{3}$
Row 7 Right: $\frac{3}{5} - \frac{2}{5} = \frac{1}{5}$
All calculations checked. Simplified where needed.
Final Answer:
Left Column Answers (top to bottom):
$\frac{1}{5}, \frac{6}{7}, \frac{3}{10}, \frac{3}{4}, \frac{2}{3}, \frac{1}{4}, \frac{2}{3}$
Right Column Answers (top to bottom):
$\frac{1}{3}, \frac{3}{4}, \frac{1}{2}, \frac{3}{11}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}$
---
1. $\frac{2}{5} - \frac{1}{5}$
Subtract numerators: $2 - 1 = 1$
Keep denominator: 5
→ $\frac{1}{5}$
2. $\frac{4}{9} - \frac{1}{9}$
$4 - 1 = 3$, denominator stays 9 → $\frac{3}{9}$
Simplify: divide numerator and denominator by 3 → $\frac{1}{3}$
3. $\frac{5}{7} + \frac{1}{7}$ ← Wait! This is addition, not subtraction. Let me check again — actually, looking at the image, this row says “+”, but all others are “-”. Hmm… maybe it’s a typo? But let’s follow what’s written.
Actually, rechecking the original problem list — in the user’s input, line 3 is:
$\frac{5}{7} + \frac{1}{7}$ — so yes, it’s addition.
But wait — the rest of the problems are subtractions. Maybe it’s meant to be subtraction? Let me double-check the original image description.
Looking back: The user wrote:
> $\frac{2}{5} - \frac{1}{5} =$
> $\frac{4}{9} - \frac{1}{9} =$
> $\frac{5}{7} + \frac{1}{7} =$ ← this one has a plus sign
> $\frac{2}{4} + \frac{1}{4} =$ ← also plus
> ... etc.
Wait — actually, scanning through, some rows have “+” and some have “-”. So we must do exactly as written.
So let’s go carefully:
---
Row 1: $\frac{2}{5} - \frac{1}{5} = \frac{1}{5}$ ✔
Row 2: $\frac{4}{9} - \frac{1}{9} = \frac{3}{9} = \frac{1}{3}$ ✔
Row 3: $\frac{5}{7} + \frac{1}{7} = \frac{6}{7}$ (add numerators) ✔
Row 4: $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$ ✔
Row 5: $\frac{7}{10} - \frac{4}{10} = \frac{3}{10}$ ✔
Row 6: $\frac{4}{6} - \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$ ✔
Row 7: $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$ ✔ (same as row 4)
Row 8: $\frac{2}{11} + \frac{1}{11} = \frac{3}{11}$ ✔
Row 9: $\frac{1}{3} + \frac{1}{3} = \frac{2}{3}$ ✔
Row 10: $\frac{2}{3} - \frac{1}{3} = \frac{1}{3}$ ✔
Row 11: $\frac{3}{8} - \frac{1}{8} = \frac{2}{8} = \frac{1}{4}$ ✔
Row 12: $\frac{4}{12} - \frac{1}{12} = \frac{3}{12} = \frac{1}{4}$ ✔
Row 13: $\frac{3}{6} + \frac{1}{6} = \frac{4}{6} = \frac{2}{3}$ ✔
Row 14: $\frac{3}{5} - \frac{2}{5} = \frac{1}{5}$ ✔
---
Now, let’s write them in order as they appear in the worksheet (left column first, then right column):
Left Column:
1. $\frac{2}{5} - \frac{1}{5} = \frac{1}{5}$
2. $\frac{5}{7} + \frac{1}{7} = \frac{6}{7}$
3. $\frac{7}{10} - \frac{4}{10} = \frac{3}{10}$
4. $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$
5. $\frac{1}{3} + \frac{1}{3} = \frac{2}{3}$
6. $\frac{3}{8} - \frac{1}{8} = \frac{1}{4}$
7. $\frac{3}{6} + \frac{1}{6} = \frac{2}{3}$
Right Column:
1. $\frac{4}{9} - \frac{1}{9} = \frac{1}{3}$
2. $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$
3. $\frac{4}{6} - \frac{1}{6} = \frac{1}{2}$
4. $\frac{2}{11} + \frac{1}{11} = \frac{3}{11}$
5. $\frac{2}{3} - \frac{1}{3} = \frac{1}{3}$
6. $\frac{4}{12} - \frac{1}{12} = \frac{1}{4}$
7. $\frac{3}{5} - \frac{2}{5} = \frac{1}{5}$
Wait — I think I miscounted the rows. Let me recount based on the original layout.
Original has 7 rows, each with two problems (left and right).
So:
Row 1 Left: $\frac{2}{5} - \frac{1}{5} = \frac{1}{5}$
Row 1 Right: $\frac{4}{9} - \frac{1}{9} = \frac{3}{9} = \frac{1}{3}$
Row 2 Left: $\frac{5}{7} + \frac{1}{7} = \frac{6}{7}$
Row 2 Right: $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$
Row 3 Left: $\frac{7}{10} - \frac{4}{10} = \frac{3}{10}$
Row 3 Right: $\frac{4}{6} - \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$
Row 4 Left: $\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$
Row 4 Right: $\frac{2}{11} + \frac{1}{11} = \frac{3}{11}$
Row 5 Left: $\frac{1}{3} + \frac{1}{3} = \frac{2}{3}$
Row 5 Right: $\frac{2}{3} - \frac{1}{3} = \frac{1}{3}$
Row 6 Left: $\frac{3}{8} - \frac{1}{8} = \frac{2}{8} = \frac{1}{4}$
Row 6 Right: $\frac{4}{12} - \frac{1}{12} = \frac{3}{12} = \frac{1}{4}$
Row 7 Left: $\frac{3}{6} + \frac{1}{6} = \frac{4}{6} = \frac{2}{3}$
Row 7 Right: $\frac{3}{5} - \frac{2}{5} = \frac{1}{5}$
All calculations checked. Simplified where needed.
Final Answer:
Left Column Answers (top to bottom):
$\frac{1}{5}, \frac{6}{7}, \frac{3}{10}, \frac{3}{4}, \frac{2}{3}, \frac{1}{4}, \frac{2}{3}$
Right Column Answers (top to bottom):
$\frac{1}{3}, \frac{3}{4}, \frac{1}{2}, \frac{3}{11}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}$
Parent Tip: Review the logic above to help your child master the concept of 4th grade math sheets print out.