Let's solve each problem step by step using the formulas for
area and
perimeter of rectangles.
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🔷 Formulas:
-
Area of a rectangle = length × width
-
Perimeter of a rectangle = 2 × (length + width)
We’ll apply these to each rectangle.
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🔹 Problem 1:
- Length = 9 ft, Width = 6 ft
-
Area = 9 × 6 =
54 sq ft
-
Perimeter = 2 × (9 + 6) = 2 × 15 =
30 ft
✔ Area =
54 ft², Perimeter =
30 ft
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🔹 Problem 2:
- Length = 11 ft, Width = 3 ft
-
Area = 11 × 3 =
33 sq ft
-
Perimeter = 2 × (11 + 3) = 2 × 14 =
28 ft
✔ Area =
33 ft², Perimeter =
28 ft
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🔹 Problem 3:
- Length = 13 cm, Width = 7 cm
-
Area = 13 × 7 =
91 sq cm
-
Perimeter = 2 × (13 + 7) = 2 × 20 =
40 cm
✔ Area =
91 cm², Perimeter =
40 cm
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🔹 Problem 4:
- Length = 22 in, Width = 19 in
-
Area = 22 × 19 =
418 sq in
-
Perimeter = 2 × (22 + 19) = 2 × 41 =
82 in
✔ Area =
418 in², Perimeter =
82 in
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🔹 Problem 5:
- Length = 25 m, Width = 16 m
-
Area = 25 × 16 =
400 sq m
-
Perimeter = 2 × (25 + 16) = 2 × 41 =
82 m
✔ Area =
400 m², Perimeter =
82 m
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🔹 Problem 6:
- Length = 10 yd, Width = 2 yd
-
Area = 10 × 2 =
20 sq yd
-
Perimeter = 2 × (10 + 2) = 2 × 12 =
24 yd
✔ Area =
20 yd², Perimeter =
24 yd
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🔹 Problem 7:
- Length = 6 mm, Width = 1 mm
-
Area = 6 × 1 =
6 sq mm
-
Perimeter = 2 × (6 + 1) = 2 × 7 =
14 mm
✔ Area =
6 mm², Perimeter =
14 mm
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🔹 Problem 8:
- Length = 44 km, Width = 21 km
-
Area = 44 × 21 =
924 sq km
-
Perimeter = 2 × (44 + 21) = 2 × 65 =
130 km
✔ Area =
924 km², Perimeter =
130 km
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✔ Final Answers:
| Problem | Area | Perimeter |
|--------|----------------|------------------|
| 1 | 54 ft² | 30 ft |
| 2 | 33 ft² | 28 ft |
| 3 | 91 cm² | 40 cm |
| 4 | 418 in² | 82 in |
| 5 | 400 m² | 82 m |
| 6 | 20 yd² | 24 yd |
| 7 | 6 mm² | 14 mm |
| 8 | 924 km² | 130 km |
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Parent Tip: Review the logic above to help your child master the concept of 4th grade perimeter and area worksheet.