To solve the problem of finding the perimeters of the rectangles, we will use the formula for the perimeter of a rectangle:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width})
\]
Let's solve each rectangle step by step.
---
1)
- Length = \(6 \, \text{cm}\)
- Width = \(2 \frac{1}{2} \, \text{cm} = 2.5 \, \text{cm}\)
\[
\text{Perimeter} = 2 \times (6 + 2.5) = 2 \times 8.5 = 17 \, \text{cm}
\]
Answer: \(17 \, \text{cm}\)
---
2)
- Length = \(3 \frac{1}{2} \, \text{m} = 3.5 \, \text{m}\)
- Width = \(3 \frac{1}{2} \, \text{m} = 3.5 \, \text{m}\)
\[
\text{Perimeter} = 2 \times (3.5 + 3.5) = 2 \times 7 = 14 \, \text{m}
\]
Answer: \(14 \, \text{m}\)
---
3)
- Length = \(80 \, \text{cm}\)
- Width = \(50 \, \text{cm}\)
\[
\text{Perimeter} = 2 \times (80 + 50) = 2 \times 130 = 260 \, \text{cm}
\]
Answer: \(260 \, \text{cm}\)
---
4)
- Length = \(4 \, \text{m}\)
- Width = \(2 \frac{1}{4} \, \text{m} = 2.25 \, \text{m}\)
\[
\text{Perimeter} = 2 \times (4 + 2.25) = 2 \times 6.25 = 12.5 \, \text{m}
\]
Answer: \(12.5 \, \text{m}\)
---
5)
- Length = \(6 \frac{1}{2} \, \text{km} = 6.5 \, \text{km}\)
- Width = \(\frac{1}{2} \, \text{km} = 0.5 \, \text{km}\)
\[
\text{Perimeter} = 2 \times (6.5 + 0.5) = 2 \times 7 = 14 \, \text{km}
\]
Answer: \(14 \, \text{km}\)
---
6)
- Length = \(6 \frac{1}{4} \, \text{m} = 6.25 \, \text{m}\)
- Width = \(4 \frac{1}{4} \, \text{m} = 4.25 \, \text{m}\)
\[
\text{Perimeter} = 2 \times (6.25 + 4.25) = 2 \times 10.5 = 21 \, \text{m}
\]
Answer: \(21 \, \text{m}\)
---
Final Answers:
1. \(17 \, \text{cm}\)
2. \(14 \, \text{m}\)
3. \(260 \, \text{cm}\)
4. \(12.5 \, \text{m}\)
5. \(14 \, \text{km}\)
6. \(21 \, \text{m}\)
\[
\boxed{17 \, \text{cm}, 14 \, \text{m}, 260 \, \text{cm}, 12.5 \, \text{m}, 14 \, \text{km}, 21 \, \text{m}}
\]
Parent Tip: Review the logic above to help your child master the concept of 4th grade perimeter worksheet.
