Add and Subtract 5-Digit and 3-Digit Numbers with Regrouping ... - Free Printable

Let’s solve each problem step by step. We’ll go row by row, left to right, and fill in the missing digits using addition or subtraction with regrouping (carrying or borrowing).

---

Problem 1: Addition

```
252□8
+ □79
-------
2□69□
```

Start from the ones place:

- Ones: 8 + 9 = 17 → write 7, carry 1
- Tens: □ + 7 + 1 (carry) = 9 → so □ must be 1 (because 1 + 7 + 1 = 9)
- Hundreds: 2 + □ = 6? Wait — we have a carry from tens? No, tens didn’t carry over because 1+7+1=9 < 10. So hundreds: 2 + □ = 6 → □ = 4
- Thousands: 5 + 0 = ? But result is □ in thousands place. Wait — let’s look again.

Actually, let’s align properly:

```
2 5 2 □ 8
+ □ 7 9
-------------
2 □ 6 9 □
```

Ones: 8 + 9 = 17 → write 7, carry 1
Tens: □ + 7 + 1 = 9 → □ = 1
Hundreds: 2 + □ = 6 → □ = 4
Thousands: 5 + 0 = 5 → but answer has □ in thousands place → should be 5? But wait, the sum starts with “2” in ten-thousands? That doesn’t match.

Wait — maybe I misaligned. Let me rewrite with placeholders:

Top number: 252A8
Bottom number: B79 (so it's actually 0B79 if we think of 5-digit alignment)
Sum: 2C69D

So:

2 5 2 A 8
+ B 7 9
-------------
2 C 6 9 D

Now add column by column from right:

Ones: 8 + 9 = 17 → D = 7, carry 1
Tens: A + 7 + 1 = 9 → A + 8 = 9 → A = 1
Hundreds: 2 + B = 6 → B = 4
Thousands: 5 + 0 = 5 → but sum shows C in thousands place → should be 5? But the sum starts with 2 in ten-thousands? That can't be unless there’s a carry from thousands.

Wait — 5 (thousands) + 0 = 5, but the sum has “2” in ten-thousands and “C” in thousands. That means 5 + 0 must have produced a carry? Impossible unless... Oh! Maybe the bottom number is aligned under the last three digits? Then:

Actually, standard alignment for adding 5-digit and 3-digit numbers: the 3-digit number is aligned to the right.

So:

2 5 2 A 8
+ B 7 9
---------------
2 C 6 9 D

That means:

Ten-thousands: 2 + 0 = 2 → matches
Thousands: 5 + 0 = 5 → but sum has C here → contradiction unless there’s a carry from hundreds.

Wait — hundreds column: 2 + B = 6 or 16? If 2 + B ≥ 10, then carry 1 to thousands.

Try that:

Assume 2 + B = 16 → B = 14? Not possible. Max digit is 9.

Alternatively, maybe 2 + B = 6, no carry → then thousands: 5 + 0 = 5 → so C should be 5.

But the sum is written as “2 C 6 9 D” — so if C=5, then sum is 25697.

Check: 25218 + 479 = ?

25218 + 479:

8+9=17 → 7, carry 1
1+7+1=9
2+4=6
5+0=5
2+0=2 → 25697 ✔

So:

A = 1 (tens place top)
B = 4 (hundreds place bottom)
C = 5 (thousands place sum)
D = 7 (ones place sum)

So first problem filled:

```
25218
+ 479
-------
25697
```

Missing digits: top tens=1, bottom hundreds=4, sum thousands=5, sum ones=7

---

Problem 2: Addition

```
80□95
+ 76□
-------
8□1□2
```

Align:

8 0 A 9 5
+ 7 6 B
---------------
8 C 1 D 2

Ones: 5 + B = 2 or 12? Since ends in 2, must be 12 → B = 7, carry 1
Tens: 9 + 6 + 1 = 16 → D = 6, carry 1
Hundreds: A + 7 + 1 = 1 or 11? Sum has 1 in hundreds → so A + 8 = 11 → A = 3, carry 1
Thousands: 0 + 0 + 1 = 1 → but sum has C in thousands → should be 1? But sum is 8 C 1 D 2 → thousands digit is C.

Wait: thousands column: top has 0, bottom has nothing → 0 + 0 + carry from hundreds (which was 1) → 1 → so C = 1
Ten-thousands: 8 + 0 = 8 → matches

Check: 80395 + 767 = ?

5+7=12 → 2, carry 1
9+6+1=16 → 6, carry 1
3+7+1=11 → 1, carry 1
0+0+1=1
8 → 81162 ✔

So:

A = 3 (top hundreds)
B = 7 (bottom ones)
C = 1 (sum thousands)
D = 6 (sum tens)

Filled:

```
80395
+ 767
-------
81162
```

---

Problem 3: Addition

```
3□□43
+ 18□
-------
390□2
```

Align:

3 A B 4 3
+ 1 8 C
---------------
3 9 0 D 2

Ones: 3 + C = 2 or 12 → must be 12 → C = 9, carry 1
Tens: 4 + 8 + 1 = 13 → D = 3, carry 1
Hundreds: B + 1 + 1 = 0 or 10? Sum has 0 → so B + 2 = 10 → B = 8, carry 1
Thousands: A + 0 + 1 = 9 → A = 8
Ten-thousands: 3 + 0 = 3 → matches

Check: 38843 + 189 = ?

3+9=12 → 2, carry 1
4+8+1=13 → 3, carry 1
8+1+1=10 → 0, carry 1
8+0+1=9
3 → 39032 ✔

So:

A = 8 (top thousands)
B = 8 (top hundreds)
C = 9 (bottom ones)
D = 3 (sum tens)

Filled:

```
38843
+ 189
-------
39032
```

---

Problem 4: Addition

```
□94□6
+ 67□
-------
60□51
```

Align:

A 9 4 B 6
+ 6 7 C
---------------
6 0 D 5 1

Ones: 6 + C = 1 or 11 → must be 11 → C = 5, carry 1
Tens: B + 7 + 1 = 5 or 15? Sum has 5 → so B + 8 = 15 → B = 7, carry 1
Hundreds: 4 + 6 + 1 = 11 → D = 1, carry 1
Thousands: 9 + 0 + 1 = 10 → write 0, carry 1 → matches sum’s 0 in thousands
Ten-thousands: A + 0 + 1 = 6 → A = 5

Check: 59476 + 675 = ?

6+5=11 → 1, carry 1
7+7+1=15 → 5, carry 1
4+6+1=11 → 1, carry 1
9+0+1=10 → 0, carry 1
5+0+1=6 → 60151 ✔

So:

A = 5 (top ten-thousands)
B = 7 (top tens)
C = 5 (bottom ones)
D = 1 (sum hundreds)

Filled:

```
59476
+ 675
-------
60151
```

---

Problem 5: Subtraction

```
□□570
- 45□
-------
291□6
```

Align:

A B 5 7 0
- 4 5 C
---------------
2 9 1 D 6

Start from ones: 0 - C = 6 → can’t do, so borrow. 10 - C = 6 → C = 4, and we borrowed from tens.

Tens: 7 became 6 after borrow. 6 - 5 = 1 → matches sum’s D? Wait, sum has D in tens place? Let’s see:

Sum is 291D6 → so:

Ones: 6 → we got that
Tens: D
Hundreds: 1
Thousands: 9
Ten-thousands: 2

After borrowing for ones:

Tens column: 7 - 1 (borrowed) = 6; then 6 - 5 = 1 → so D = 1

Hundreds: 5 - 4 = 1 → matches

Thousands: B - 0 = 9 → B = 9

Ten-thousands: A - 0 = 2 → A = 2

But wait — did we need to borrow anywhere else? In hundreds: 5 - 4 = 1, fine. Thousands: B - 0 = 9 → B=9. Ten-thousands: A=2.

Check: 29570 - 454 = ?

0-4 → borrow: 10-4=6
7 becomes 6; 6-5=1
5-4=1
9-0=9
2-0=2 → 29116 ✔

So:

A = 2 (top ten-thousands)
B = 9 (top thousands)
C = 4 (bottom ones)
D = 1 (sum tens)

Filled:

```
29570
- 454
-------
29116
```

---

Problem 6: Subtraction

```
3□40□
- 616
-------
□1□89
```

Align:

3 A 4 0 B
- 6 1 6
---------------
C 1 D 8 9

Ones: B - 6 = 9 → can’t, so borrow. 10 + B - 6 = 9 → B + 4 = 9 → B = 5? Wait: 10 + B - 6 = 9 → B = 5? 10+5-6=9 yes. But we borrowed from tens.

Tens: 0 became 9 after borrow (since we borrowed for ones). Now 9 - 1 = 8 → matches sum’s 8 in tens.

Hundreds: 4 - 6 → can’t, so borrow from thousands. 14 - 6 = 8 → but sum has D in hundreds? Wait, sum is C1D89 → hundreds digit is D.

Wait, let’s map:

After borrowing for ones:

Tens: 0 → borrowed, so becomes 9 (after lending to ones), then 9 - 1 = 8 → good.

Hundreds: 4 → now we need to subtract 6, so borrow from thousands. So 14 - 6 = 8 → so D = 8

Thousands: A → we borrowed 1, so becomes A-1. Then (A-1) - 0 = 1? Because sum has 1 in thousands place? Sum is C1D89 → thousands digit is 1.

So A - 1 = 1 → A = 2

Ten-thousands: 3 - 0 = C → but we didn’t borrow from ten-thousands? When we borrowed for hundreds, we took from thousands, which came from ten-thousands? Let’s trace.

Original: 3 A 4 0 B

We borrowed for ones: from tens (0), but tens was 0, so had to borrow from hundreds.

Standard borrowing chain:

To subtract ones: B - 6 = 9 → need to borrow. Tens is 0, so borrow from hundreds.

Hundreds is 4 → becomes 3, tens becomes 10.

Then tens lends to ones: tens becomes 9, ones becomes 10 + B.

Then ones: 10 + B - 6 = 9 → B = 5

Tens: 9 - 1 = 8 → good

Hundreds: now 3 (after lending) - 6 → can’t, so borrow from thousands.

Thousands is A → becomes A-1, hundreds becomes 13.

13 - 6 = 7 → but earlier I said 8? Mistake.

Wait: after borrowing for tens, hundreds was reduced to 3.

Then for hundreds column: 3 - 6 → need to borrow from thousands.

So hundreds becomes 13, thousands becomes A-1.

13 - 6 = 7 → so D = 7

Thousands: (A - 1) - 0 = 1 → A - 1 = 1 → A = 2

Ten-thousands: 3 - 0 = C, but did we borrow from ten-thousands? When we borrowed for thousands, we took from ten-thousands only if thousands was 0, but here thousands is A=2, so when we borrow, thousands becomes 1, ten-thousands remains 3? No.

When we borrow for hundreds, we take from thousands. Thousands was A, becomes A-1. If A-1 >=0, no further borrow. Here A=2, so thousands becomes 1, which is fine.

Then thousands column: 1 - 0 = 1 → matches sum’s 1 in thousands.

Ten-thousands: 3 - 0 = 3 → so C = 3

But sum is C1D89 → so 3 1 7 8 9? Let’s check.

Number: 3 2 4 0 5 minus 616

Compute: 32405 - 616

5-6 → borrow: 15-6=9
0 becomes 9 (after borrow from 4? Let's do step by step.

32405
- 616
------

Ones: 5<6, borrow from tens. Tens is 0, so borrow from hundreds.

Hundreds is 4 → becomes 3, tens becomes 10.

Tens lends to ones: tens becomes 9, ones becomes 15.

15-6=9

Tens: 9-1=8

Hundreds: 3-6 → can't, borrow from thousands.

Thousands is 2 → becomes 1, hundreds becomes 13.

13-6=7

Thousands: 1-0=1

Ten-thousands: 3-0=3

So 31789 ✔

Thus:

A = 2 (top thousands)
B = 5 (top ones)
C = 3 (sum ten-thousands)
D = 7 (sum hundreds)

Filled:

```
32405
- 616
-------
31789
```

---

Problem 7: Subtraction

```
□□511
- 6□6
-------
70□45
```

Align:

A B 5 1 1
- 6 C 6
---------------
7 0 D 4 5

Ones: 1 - 6 = 5 → can’t, borrow. 11 - 6 = 5 → good, borrowed from tens.

Tens: 1 became 0 after borrow. 0 - C = 4 → can’t, so borrow from hundreds.

Hundreds is 5 → becomes 4, tens becomes 10.

Then tens: 10 - C = 4 → C = 6

Hundreds: 4 (after lend) - 6 → can’t, borrow from thousands.

Thousands is B → becomes B-1, hundreds becomes 14.

14 - 6 = 8 → so D = 8

Thousands: (B - 1) - 0 = 0 → B - 1 = 0 → B = 1

Ten-thousands: A - 0 = 7 → A = 7

Check: 71511 - 666 = ?

1-6 → borrow: 11-6=5
1 becomes 0; 0-6 → borrow: 10-6=4
5 becomes 4; 4-6 → borrow: 14-6=8
1 becomes 0; 0-0=0
7 → 70845 ✔

So:

A = 7 (top ten-thousands)
B = 1 (top thousands)
C = 6 (bottom tens)
D = 8 (sum hundreds)

Filled:

```
71511
- 666
-------
70845
```

---

Problem 8: Subtraction

```
6□58□
- 585
-------
□09□9
```

Align:

6 A 5 8 B
- 5 8 5
---------------
C 0 9 D 9

Ones: B - 5 = 9 → can’t, borrow. 10 + B - 5 = 9 → B + 5 = 9 → B = 4? 10+4-5=9 yes. Borrowed from tens.

Tens: 8 became 7 after borrow. 7 - 8 → can’t, borrow from hundreds.

Hundreds is 5 → becomes 4, tens becomes 17.

17 - 8 = 9 → so D = 9

Hundreds: 4 (after lend) - 5 → can’t, borrow from thousands.

Thousands is A → becomes A-1, hundreds becomes 14.

14 - 5 = 9 → matches sum’s 9 in hundreds.

Thousands: (A - 1) - 0 = 0 → A - 1 = 0 → A = 1

Ten-thousands: 6 - 0 = C, but did we borrow? When we borrowed for hundreds, we took from thousands, which came from ten-thousands? Thousands was A=1, became 0 after borrow, so ten-thousands remains 6? But sum has C in ten-thousands.

After borrowing for hundreds: thousands was A, became A-1. If A=1, then thousands becomes 0.

Then thousands column: 0 - 0 = 0 → matches sum’s 0 in thousands.

Ten-thousands: 6 - 0 = 6 → so C = 6

Check: 61584 - 585 = ?

4-5 → borrow: 14-5=9
8 becomes 7; 7-8 → borrow: 17-8=9
5 becomes 4; 4-5 → borrow: 14-5=9
1 becomes 0; 0-0=0
6 → 60999 ✔

So:

A = 1 (top thousands)
B = 4 (top ones)
C = 6 (sum ten-thousands)
D = 9 (sum tens)

Filled:

```
61584
- 585
-------
60999
```

---

Now, compiling all missing digits in order as they appear in the worksheet (left to right, top to bottom):

First problem (addition):
Top tens: 1
Bottom hundreds: 4
Sum thousands: 5
Sum ones: 7

Second problem:
Top hundreds: 3
Bottom ones: 7
Sum thousands: 1
Sum tens: 6

Third problem:
Top thousands: 8
Top hundreds: 8
Bottom ones: 9
Sum tens: 3

Fourth problem:
Top ten-thousands: 5
Top tens: 7
Bottom ones: 5
Sum hundreds: 1

Fifth problem (subtraction):
Top ten-thousands: 2
Top thousands: 9
Bottom ones: 4
Sum tens: 1

Sixth problem:
Top thousands: 2
Top ones: 5
Sum ten-thousands: 3
Sum hundreds: 7

Seventh problem:
Top ten-thousands: 7
Top thousands: 1
Bottom tens: 6
Sum hundreds: 8

Eighth problem:
Top thousands: 1
Top ones: 4
Sum ten-thousands: 6
Sum tens: 9

But the question is to "fill in the missing digits" — probably list them in the order they appear in the boxes.

Looking at the worksheet layout:

Left column, first problem:
252_8 → missing digit in tens place: 1
+_79 → missing digit in hundreds place: 4
2_69_ → missing digits: thousands=5, ones=7

Similarly, we can list all missing digits in sequence as per the boxes.

Since the user likely wants the completed problems or just the digits, but instruction says "solve the problem accurately" and "final answer", probably list the filled numbers or the digits.

But to be precise, let's output the completed equations with missing digits filled.

However, the format might expect just the digits in order.

Given the complexity, perhaps list each problem's missing digits.

But since the final answer should be concise, and the task is to fill missing digits, I'll provide the completed sums/subtractions.

Alternatively, since it's a worksheet, maybe list the digits in the order of the blanks.

Let me count the blanks:

Each problem has 4 blanks? Let's see:

Problem 1: 4 blanks
Problem 2: 4 blanks
... up to 8 problems → 32 blanks.

But that's messy.

Perhaps the expected answer is the set of filled numbers.

Given the instructions, I think providing the completed arithmetic statements is best.

But to save space, I'll list the missing digits in order as they appear in the worksheet from top to bottom, left to right.

Worksheet order:

Row 1, left:
252□8 → □ = 1 (tens)
+ □79 → □ = 4 (hundreds)
2□69□ → □ = 5 (thousands), □ = 7 (ones)

Row 1, right:
80□95 → □ = 3 (hundreds)
+ 76□ → □ = 7 (ones)
8□1□2 → □ = 1 (thousands), □ = 6 (tens)

Row 2, left:
3□□43 → □ = 8 (thousands), □ = 8 (hundreds)
+ 18□ → □ = 9 (ones)
390□2 → □ = 3 (tens)

Row 2, right:
□94□6 → □ = 5 (ten-thousands), □ = 7 (tens)
+ 67□ → □ = 5 (ones)
60□51 → □ = 1 (hundreds)

Row 3, left:
□□570 → □ = 2 (ten-thousands), □ = 9 (thousands)
- 45□ → □ = 4 (ones)
291□6 → □ = 1 (tens)

Row 3, right:
3□40□ → □ = 2 (thousands), □ = 5 (ones)
- 616
□1□89 → □ = 3 (ten-thousands), □ = 7 (hundreds)

Row 4, left:
□□511 → □ = 7 (ten-thousands), □ = 1 (thousands)
- 6□6 → □ = 6 (tens)
70□45 → □ = 8 (hundreds)

Row 4, right:
6□58□ → □ = 1 (thousands), □ = 4 (ones)
- 585
□09□9 → □ = 6 (ten-thousands), □ = 9 (tens)

So the missing digits in order are:

1,4,5,7, 3,7,1,6, 8,8,9,3, 5,7,5,1, 2,9,4,1, 2,5,3,7, 7,1,6,8, 1,4,6,9

But that's 32 digits.

Perhaps group by problem.

Since the user may want the answers filled, I'll present the completed problems.

Final Answer:

Completed problems:

1. 25218 + 479 = 25697
2. 80395 + 767 = 81162
3. 38843 + 189 = 39032
4. 59476 + 675 = 60151
5. 29570 - 454 = 29116
6. 32405 - 616 = 31789
7. 71511 - 666 = 70845
8. 61584 - 585 = 60999

This is accurate and clear.