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Educational worksheet on factor trees for finding factors of numbers, part of the "An Amazing Fact a Day" series.

A worksheet titled "Factor Tree" from "An Amazing Fact a Day" series, featuring a math challenge on finding factors using factor trees, with examples and a section for students to practice.

A worksheet titled "Factor Tree" from "An Amazing Fact a Day" series, featuring a math challenge on finding factors using factor trees, with examples and a section for students to practice.

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Show Answer Key & Explanations Step-by-step solution for: Factor Trees Worksheet | Maths Teaching Resource | Year 5-6
I'll solve this problem step by step, focusing on finding more factors of 42 by starting another factor tree.

First, look closely:
- The image shows a worksheet about "Factor Trees" with an "Amazing Fact" about the tallest tree in the world.
- The challenge is to find more factors of 42 by starting another factor tree for 42.
- The example provided shows one factor tree for 42: 42 breaks down into 6 and 7, then 6 breaks down into 2 and 3. This gives us the prime factors: 2, 3, and 7.
- The question asks if we can find any more factors by starting another factor tree.

The key insight here is that while the prime factorization of a number is unique (in this case, 42 = 2 × 3 × 7), we can create different *factor trees* by choosing different pairs of factors at each step. The goal isn't to find new prime factors (since they are unique) but to demonstrate a different way to break down 42, which will ultimately lead to the same prime factors.

Let me now construct a different factor tree for 42 to answer the question.

I'll start by breaking 42 into a different pair of factors than the example (which used 6 and 7). A good alternative is 2 and 21.

So, my new factor tree would be:
- 42
- 2 (prime)
- 21
- 3 (prime)
- 7 (prime)

This gives us the same prime factors: 2, 3, and 7.

From these prime factors, we can find all the factors of 42 by multiplying them in different combinations:
- 1 (by definition, 1 is a factor of every number)
- 2
- 3
- 7
- 2 × 3 = 6
- 2 × 7 = 14
- 3 × 7 = 21
- 2 × 3 × 7 = 42

Therefore, the complete list of factors of 42 is: 1, 2, 3, 6, 7, 14, 21, and 42.

The original example showed 2, 3, 6, 7, and 21. By creating a different factor tree, I've confirmed the same prime factors and can list all factors, including 1, 14, and 42, which might not have been explicitly listed in the initial example.

Answer:

Yes, we can find more factors of 42 by starting another factor tree. While the prime factors (2, 3, and 7) will always be the same, a different factor tree helps us systematically find all the factors of 42.

Here is another factor tree for 42:
```
42
/ \
2 21
/ \
3 7
```

Using the prime factors from this tree (2, 3, and 7), we can find all the factors of 42:
- 1
- 2
- 3
- 6 (2 × 3)
- 7
- 14 (2 × 7)
- 21 (3 × 7)
- 42 (2 × 3 × 7)

So, the complete set of factors of 42 is {1, 2, 3, 6, 7, 14, 21, 42}. The different factor tree confirms these factors and helps ensure we haven't missed any.
Parent Tip: Review the logic above to help your child master the concept of 5th grade factor trees.
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(view all 5th grade factor trees)

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