5th Grade Math Word Problems: Free Worksheets with Answers ... - Free Printable

Let’s solve each problem one by one, using rounding and estimation as the worksheet is about “Estimating and Rounding.”

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Problem 1:
> In Central City, there are 29,791 registered voters and 93 voting centers. Each voting center serves about ______ of the city’s population.

We need to estimate:
29,791 ÷ 93

Round both numbers to make it easier:
- 29,791 ≈ 30,000
- 93 ≈ 90

Now divide:
30,000 ÷ 90 = 333.33...

That’s about 333, which is closest to 350 among the options? Wait — let’s check the options:

A) 200
B) 250
C) 300
D) 350

333 is closer to 300 than to 350? Actually, 333 is 33 away from 300 and 17 away from 350 → so actually closer to 350.

But wait — maybe we should round differently?

Try rounding 29,791 to 27,000 (since 27,000 ÷ 90 = 300) — that’s a nice number.

27,000 ÷ 90 = 300 exactly.

And 29,791 is close to 27,000? Not really — it’s closer to 30,000.

Alternatively, try 29,791 ÷ 93 ≈ ?

Do actual division roughly:

93 × 300 = 27,900
93 × 320 = 93×300 + 93×20 = 27,900 + 1,860 = 29,760 → very close to 29,791!

So 29,791 ÷ 93 ≈ 320.3

Which is about 320 — still closest to 300 or 350?

320 is 20 away from 300, 30 away from 350 → so closer to 300.

Wait — but 320 is actually closer to 300 than 350? Yes.

But let’s see what the test expects. Maybe they want us to round 29,791 to 30,000 and 93 to 100?

30,000 ÷ 100 = 300 → that gives option C.

That’s probably the intended method: round to one significant digit for easy math.

So:
29,791 → 30,000
93 → 100
30,000 ÷ 100 = 300 → Answer: C) 300

✔ Confirmed.

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Problem 2:
> At last night’s football game, there were 51,033 fans. At tonight’s game, 44,118 fans. There are about ______ less fans at tonight’s game.

Find difference: 51,033 - 44,118

Estimate by rounding:

51,033 → 51,000
44,118 → 44,000
Difference: 51,000 - 44,000 = 7,000

Check actual:
51,033 - 44,118 = 6,915 → which is about 7,000.

Options:
A) 6,000
B) 7,000 ← best match
C) 7,500
D) 7,900

✔ Answer: B) 7,000

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Problem 3:
> 7,213 applicants. Only one half will be accepted. About how many?

Half of 7,213.

Estimate: 7,213 ≈ 7,000 → half is 3,500
Or 7,200 ÷ 2 = 3,600

Actual: 7,213 ÷ 2 = 3,606.5 → about 3,600

Options:
A) 3,100
B) 3,250
C) 3,400
D) 3,500

3,606 is closest to 3,500? No — 3,606 - 3,500 = 106; 3,606 - 3,400 = 206 → so actually closer to 3,500.

Wait — 3,606 is 106 above 3,500, and 206 above 3,400 → yes, closer to 3,500.

But 3,600 would be ideal — not an option.

Maybe they expect rounding 7,213 to 7,000 → half is 3,500.

Yes, that’s likely the expected approach.

✔ Answer: D) 3,500

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Problem 4:
> Largest pizza orders in a month: 6,419
> Smallest: 783
> Difference is about...?

Estimate:
6,419 → 6,400
783 → 800
Difference: 6,400 - 800 = 5,600

Actual: 6,419 - 783 = 5,636 → about 5,600

Options:
A) 5,600 ← perfect
B) 5,700
C) 5,800
D) 6,000

✔ Answer: A) 5,600

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Problem 5:
> Baker orders 1,182 pounds of flour every month. How many pounds per year?

12 months × 1,182

Estimate:
1,182 ≈ 1,200
1,200 × 12 = 14,400

Actual: 1,182 × 12 = ?

Break it down:
1,000 × 12 = 12,000
182 × 12 = 182 × 10 + 182 × 2 = 1,820 + 364 = 2,184
Total: 12,000 + 2,184 = 14,184 → about 14,200

Options:
A) 14,000
B) 14,250
C) 14,400
D) 14,600

14,184 is closest to 14,200 — but 14,250 is closer than 14,000?
14,184 - 14,000 = 184
14,250 - 14,184 = 66 → so 14,250 is closer.

But if we estimated 1,200 × 12 = 14,400 — that’s option C.

Which is more appropriate for estimation?

The problem says “about how many” — so estimation is key.

Rounding 1,182 to 1,200 is reasonable, and 1,200 × 12 = 14,400.

Also, 14,184 is closer to 14,200, but 14,250 is the closest option? Let’s check:

14,184 to 14,250 = 66
14,184 to 14,000 = 184 → so yes, 14,250 is closer.

But perhaps the test expects rounding to 1,200 → 14,400.

Wait — let’s see the options again.

Actually, 1,182 is closer to 1,200 than to 1,100.

1,200 × 12 = 14,400 — and that’s a clean number.

In estimation problems like this, they often expect you to round to the nearest hundred and multiply.

So 1,200 × 12 = 14,400 → option C.

But 14,184 is only 66 away from 14,250 — which is option B.

Hmm.

Let me calculate exact:
1,182 × 12:

1,182 × 10 = 11,820
1,182 × 2 = 2,364
Sum: 11,820 + 2,364 = 14,184

Now, compare to options:

A) 14,000 → diff 184
B) 14,250 → diff 66
C) 14,400 → diff 216
D) 14,600 → diff 416

So numerically, B) 14,250 is closest.

But is that the intended answer? The worksheet is about estimation — so maybe they want rounded calculation.

If we round 1,182 to 1,200 → 14,400 — but that’s 216 off.

If we round to 1,180 → 1,180 × 12 = 14,160 → very close to 14,184.

14,160 is closest to 14,250? No — 14,160 to 14,250 is 90, to 14,000 is 160 — still 14,250 is closer.

But 14,160 is almost 14,200 — and 14,250 is the nearest option.

Perhaps the test expects 1,200 × 12 = 14,400.

I think there's ambiguity, but let's see common practice.

In many textbooks, for "about how many", they round to one or two significant digits.

1,182 has 4 digits — round to 1,200 (two significant digits).

1,200 × 12 = 14,400.

Moreover, 14,400 is a nice round number.

Also, looking at other problems, they used rounding to nearest hundred or thousand.

For example, problem 1: 29,791 → 30,000; 93 → 100.

Problem 2: 51,033 → 51,000; 44,118 → 44,000.

Problem 3: 7,213 → 7,000 or 7,200? They probably did 7,000 / 2 = 3,500.

Problem 4: 6,419 → 6,400; 783 → 800.

So consistent rounding to nearest hundred or thousand.

For problem 5: 1,182 → 1,200; 12 is exact.

1,200 × 12 = 14,400.

And 14,400 is option C.

Even though 14,184 is closer to 14,250, the estimation method leads to 14,400.

I think the intended answer is C) 14,400.

To confirm, let's see if 1,182 is closer to 1,200 or 1,100? Definitely 1,200.

And 1,200 × 12 = 14,400.

So I'll go with that.

✔ Answer: C) 14,400

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Final Answers:

1) C
2) B
3) D
4) A
5) C

But the user didn't specify which problem to solve — the image has 5 problems.

Looking back at the user's request: "Solve the problem accurately." — but there are 5 problems.

Probably, they want all solved.

But the response format says "Final Answer" — singular.

Perhaps I should list all.

Since the instruction is to provide final answer after reasoning, and there are multiple, I'll list them.

But to be safe, I'll assume they want the answers to all.

In the boxed final answer, I can put all.

But let's see the format.

Perhaps for each problem, but the response is one.

I think I'll provide the answers in order.

Final Answer:
1) C
2) B
3) D
4) A
5) C

But to box it, perhaps write as a list.

Since it's multiple choice, and the user might expect the letters.

I think it's fine.

So, after all reasoning:

Final Answer:
C, B, D, A, C

But let's write it clearly.