Challenge students with multi-step arithmetic using this farm-themed worksheet featuring scenarios about harvest yields and equipment costs.

Let’s solve each problem one by one, step by step. We’ll check our math carefully before giving the final answers.

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Problem 1:

Last year’s harvest = 177,124 tons
This year’s harvest = double last year’s → so we multiply by 2.

177,124 × 2 = ?

Let’s break it down:

177,000 × 2 = 354,000
124 × 2 = 248
Add them: 354,000 + 248 = 354,248

✔ So this year’s harvest is 354,248 tons

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Problem 2:

Total land = 1,684 acres
Each acre needs 16 bags of fertilizer.

First, find total bags needed for all land:

1,684 × 16

Break it down:

1,684 × 10 = 16,840
1,684 × 6 = let’s calculate:
1,600 × 6 = 9,600
84 × 6 = 504
So 9,600 + 504 = 10,104

Now add: 16,840 + 10,104 = 26,944 bags used

Storage has 142,518 bags.

Bags left = 142,518 - 26,944

Subtract:

142,518
-26,944
= ?

Start from right:

8 - 4 = 4
1 - 4 → can’t do, borrow → 11 - 4 = 7 (but the 5 becomes 4)
4 (was 5) - 9 → can’t do, borrow → 14 - 9 = 5 (the 2 becomes 1)
1 (was 2) - 6 → can’t do, borrow → 11 - 6 = 5 (the 4 becomes 3)
3 (was 4) - 2 = 1
1 - 0 = 1

Wait — let me write it properly:

 142,518
– 26,944
__________
Start from right:

8 - 4 = 4
1 - 4 → borrow → 11 - 4 = 7 (tens place; hundreds digit was 5, now 4)
4 - 9 → borrow → 14 - 9 = 5 (hundreds; thousands digit was 2, now 1)
1 - 6 → borrow → 11 - 6 = 5 (thousands; ten-thousands digit was 4, now 3)
3 - 2 = 1
1 - 0 = 1

So result is 115,574

✔ Bags left = 115,574

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Problem 3:

Cost per tractor to buy = $5,672
Maintenance per month per tractor = $89
Number of tractors = 12
Time = 18 months

First, cost to buy all tractors:

5,672 × 12

Calculate:

5,672 × 10 = 56,720
5,672 × 2 = 11,344
Add: 56,720 + 11,344 = 68,064

Now maintenance cost:

Per tractor per month = $89
For 12 tractors per month: 89 × 12

89 × 10 = 890
89 × 2 = 178
Total = 890 + 178 = 1,068 per month

For 18 months: 1,068 × 18

Break it down:

1,068 × 10 = 10,680
1,068 × 8 = ?

1,000 × 8 = 8,000
68 × 8 = 544
So 8,000 + 544 = 8,544

Now add: 10,680 + 8,544 = 19,224

Total cost = buying + maintenance = 68,064 + 19,224

68,064 + 19,000 = 87,064
87,064 + 224 = 87,288

✔ Total cost = $87,288

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Problem 4:

Time to plow 1 acre = 45 minutes
Total land = 1,684 acres

Total time in minutes = 1,684 × 45

Let’s compute:

1,684 × 40 = 67,360
1,684 × 5 = 8,420
Add: 67,360 + 8,420 = 75,780 minutes

Convert to hours: divide by 60

75,780 ÷ 60

Divide step by step:

60 × 1,000 = 60,000 → subtract: 75,780 - 60,000 = 15,780
60 × 200 = 12,000 → subtract: 15,780 - 12,000 = 3,780
60 × 60 = 3,600 → subtract: 3,780 - 3,600 = 180
60 × 3 = 180 → subtract: 0

So total hours = 1,000 + 200 + 60 + 3 = 1,263 hours

✔ Time needed = 1,263 hours

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Problem 5:

Total produce = 479,800 pounds
A fifth is rotten → so 1/5 is bad, meaning 4/5 is good.

We need to find how much is left → that’s 4/5 of total.

So: 479,800 × 4/5

First, divide by 5, then multiply by 4.

479,800 ÷ 5 = ?

5 × 95,000 = 475,000
Subtract: 479,800 - 475,000 = 4,800
4,800 ÷ 5 = 960
So total = 95,000 + 960 = 95,960

That’s 1/5. Now multiply by 4 to get what’s left:

95,960 × 4

90,000 × 4 = 360,000
5,000 × 4 = 20,000 → total 380,000
960 × 4 = 3,840
Add: 380,000 + 3,840 = 383,840

Alternatively: 479,800 × 4 = 1,919,200 → then divide by 5 → same thing.

But we did it correctly above.

✔ Produce left = 383,840 pounds

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Final Answer:

1. 354,248 tons
2. 115,574 bags
3. $87,288
4. 1,263 hours
5. 383,840 pounds