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Area and perimeter practice worksheet with six problems involving rectangles and triangles.

A math worksheet titled "Area & Perimeter" with six geometry problems involving rectangles and triangles, each with given dimensions and spaces to calculate area and perimeter.

A math worksheet titled "Area & Perimeter" with six geometry problems involving rectangles and triangles, each with given dimensions and spaces to calculate area and perimeter.

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Show Answer Key & Explanations Step-by-step solution for: Grade 5 Area and Perimeter Worksheets | Free Math Worksheets
Let's solve each problem step by step using the formulas for area and perimeter of different shapes.

---

🔷 1. Rectangle (5m × 4m)


- Area = length × width
$$
\text{Area} = 5\, \text{m} \times 4\, \text{m} = 20\, \text{m}^2
$$

- Perimeter = 2 × (length + width)
$$
\text{Perimeter} = 2 \times (5 + 4) = 2 \times 9 = 18\, \text{m}
$$

Answer:
- Area: 20 m²
- Perimeter: 18 m

---

🔷 2. Triangle (Base = 7m, Height = 5m)


This is a triangle with base and height given.

- Area = $ \frac{1}{2} \times \text{base} \times \text{height} $
$$
\text{Area} = \frac{1}{2} \times 7\, \text{m} \times 5\, \text{m} = \frac{35}{2} = 17.5\, \text{m}^2
$$

⚠️ Note: We can't find perimeter without side lengths — only base and height are given. So we cannot calculate perimeter from this info.

Answer:
- Area: 17.5 m²
- Perimeter: Not enough information

---

🔷 3. Rectangle (12m × 11m)


- Area = length × width
$$
\text{Area} = 12\, \text{m} \times 11\, \text{m} = 132\, \text{m}^2
$$

- Perimeter = 2 × (length + width)
$$
\text{Perimeter} = 2 \times (12 + 11) = 2 \times 23 = 46\, \text{m}
$$

Answer:
- Area: 132 m²
- Perimeter: 46 m

---

🔷 4. Square (Side = 9m)


All sides are equal in a square.

- Area = side²
$$
\text{Area} = 9\, \text{m} \times 9\, \text{m} = 81\, \text{m}^2
$$

- Perimeter = 4 × side
$$
\text{Perimeter} = 4 \times 9 = 36\, \text{m}
$$

Answer:
- Area: 81 m²
- Perimeter: 36 m

---

🔷 5. Triangle (Base = 6m, Height = 15m)


Again, base and height are given.

- Area = $ \frac{1}{2} \times \text{base} \times \text{height} $
$$
\text{Area} = \frac{1}{2} \times 6\, \text{m} \times 15\, \text{m} = 3 \times 15 = 45\, \text{m}^2
$$

⚠️ Again, no side lengths → cannot compute perimeter.

Answer:
- Area: 45 m²
- Perimeter: Not enough information

---

🔷 6. Triangle (Base = 20m, Height = 10m)


- Area = $ \frac{1}{2} \times \text{base} \times \text{height} $
$$
\text{Area} = \frac{1}{2} \times 20\, \text{m} \times 10\, \text{m} = 10 \times 10 = 100\, \text{m}^2
$$

⚠️ No side lengths → cannot find perimeter

Answer:
- Area: 100 m²
- Perimeter: Not enough information

---

Final Answers Summary:



| Problem | Shape | Area | Perimeter |
|--------|-------------|-------------|---------------|
| 1 | Rectangle | 20 m² | 18 m |
| 2 | Triangle | 17.5 m² | Not enough info |
| 3 | Rectangle | 132 m² | 46 m |
| 4 | Square | 81 m² | 36 m |
| 5 | Triangle | 45 m² | Not enough info |
| 6 | Triangle | 100 m² | Not enough info |

---

📝 Notes:


- For triangles, if only base and height are given, we can only find area, not perimeter.
- For rectangles and squares, both area and perimeter can be found with the given dimensions.

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