Chance Worksheets Year 5 | PDF | Probability | Probability And ... - Free Printable

Let's solve the probability questions step by step based on the spinner shown in the image.

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Spinner Analysis

The spinner is divided into 8 equal sections, each labeled with a letter:

- B
- a
- D
- C
- A
- b
- D
- A

So, we have 8 total outcomes (equal-sized sections).

Let’s list all the labels:

1. B
2. a
3. D
4. C
5. A
6. b
7. D
8. A

Now, let’s answer each part.

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## Question 1: Probability Outcomes Using Fractions

a) What is the chance, as a fraction, of the spinner landing on:

#### i) B or b?
- B appears once
- b appears once
- So, total favorable outcomes = 1 + 1 = 2
- Total possible outcomes = 8
- Probability = $ \frac{2}{8} = \frac{1}{4} $

✔ Answer: $ \frac{1}{4} $

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#### ii) A or a?
- A appears twice (in two separate sections)
- a appears once
- So, total favorable outcomes = 2 + 1 = 3
- Probability = $ \frac{3}{8} $

✔ Answer: $ \frac{3}{8} $

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#### iii) C?
- C appears once
- Probability = $ \frac{1}{8} $

✔ Answer: $ \frac{1}{8} $

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#### iv) D?
- D appears twice
- Probability = $ \frac{2}{8} = \frac{1}{4} $

✔ Answer: $ \frac{1}{4} $

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b) What is the chance of the spinner not landing on:

> Remember:
> P(not X) = 1 - P(X)

#### i) b or B?
- From earlier, P(B or b) = $ \frac{2}{8} = \frac{1}{4} $
- So, P(not B or b) = $ 1 - \frac{1}{4} = \frac{3}{4} $

✔ Answer: $ \frac{3}{4} $

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#### ii) C?
- P(C) = $ \frac{1}{8} $
- So, P(not C) = $ 1 - \frac{1}{8} = \frac{7}{8} $

✔ Answer: $ \frac{7}{8} $

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c) What is the chance of the spinner landing on:

#### i) a capital letter?
- Capital letters: B, C, A, A, D, D → count them:
- B → 1
- C → 1
- A → 2
- D → 2
- Total capital letters = 1 + 1 + 2 + 2 = 6
- So, P(capital) = $ \frac{6}{8} = \frac{3}{4} $

✔ Answer: $ \frac{3}{4} $

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#### ii) a lower-case letter?
- Lower-case letters: a, b
- a → 1
- b → 1
- Total = 2
- P(lower-case) = $ \frac{2}{8} = \frac{1}{4} $

✔ Answer: $ \frac{1}{4} $

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d) What is the chance of the spinner landing on a vowel?

Vowels are: A, E, I, O, U

In our spinner, only A and a are vowels.

- A (capital) appears twice
- a (lowercase) appears once
- So, total vowel outcomes = 2 + 1 = 3
- P(vowel) = $ \frac{3}{8} $

✔ Answer: $ \frac{3}{8} $

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## Question 2: Colour the rectangles to represent the probability shown

We have a grid of 6 rectangles (2 rows × 3 columns), so total = 6 parts.

We need to color according to the given probabilities.

Let’s go one by one:

a) $ \frac{1}{3} $ chance of blue

- $ \frac{1}{3} $ of 6 = $ 6 \div 3 = 2 $
- So, color 2 rectangles blue

✔ Color 2 rectangles blue

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b) $ \frac{1}{3} $ chance of green

- Same as above: $ \frac{1}{3} \times 6 = 2 $
- So, color 2 rectangles green

✔ Color 2 rectangles green

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c) $ \frac{1}{6} $ chance of red

- $ \frac{1}{6} \times 6 = 1 $
- So, color 1 rectangle red

✔ Color 1 rectangle red

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d) $ \frac{2}{12} $ chance of yellow

- Simplify: $ \frac{2}{12} = \frac{1}{6} $
- So, same as above: $ \frac{1}{6} \times 6 = 1 $
- Color 1 rectangle yellow

✔ Color 1 rectangle yellow

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🔍 Final Check: Total colored rectangles?

- Blue: 2
- Green: 2
- Red: 1
- Yellow: 1
→ Total = 2+2+1+1 = 6 → Perfect, all rectangles are used.

Note: You can assign colors to any rectangles, but ensure:
- 2 blue
- 2 green
- 1 red
- 1 yellow

(No overlap; you could use different shades or just label.)

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## ✔ Final Answers Summary

Question 1:

a)
i) $ \frac{1}{4} $
ii) $ \frac{3}{8} $
iii) $ \frac{1}{8} $
iv) $ \frac{1}{4} $

b)
i) $ \frac{3}{4} $
ii) $ \frac{7}{8} $

c)
i) $ \frac{3}{4} $
ii) $ \frac{1}{4} $

d) $ \frac{3}{8} $

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Question 2:

- Color 2 rectangles blue
- Color 2 rectangles green
- Color 1 rectangle red
- Color 1 rectangle yellow

You're done! Let me know if you'd like a visual sketch or explanation for coloring.