Two-step equations worksheet with fractions and decimals word problems.

Let’s solve each problem one by one. I’ll work through the math carefully and check my answers before giving the final result.

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Problem 1:

Marion has saved $239.06. Each week, she gets $14.50 allowance. She wants to buy a $299.04 camera. How many more weeks does she need to save?

Step 1: Find how much more money she needs.
$299.04 - $239.06 = $59.98

Step 2: Divide that by her weekly allowance to find how many weeks.
$59.98 ÷ $14.50 ≈ 4.136...

Since she can’t save for part of a week (and she needs *at least* enough), we round up to the next whole week.

→ 5 weeks

Check: 4 weeks × $14.50 = $58.00 → Total saved = $239.06 + $58.00 = $297.06 → Not enough!
5 weeks × $14.50 = $72.50 → Total saved = $239.06 + $72.50 = $311.56 → Enough!

✔ So, 5 weeks is correct.

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Problem 2:

Jonas spent $14 on entry tickets for himself and his 3 children → total 4 people.
Adult ticket = $3.50 → Jonas paid $3.50 for himself.
So, children’s tickets cost: $14 - $3.50 = $10.50
There are 3 children → $10.50 ÷ 3 = $3.50 per child

Wait — that’s the same as adult? Let me double-check.

Total paid: $14
Adult: $3.50
Remaining for 3 kids: $14 - $3.50 = $10.50
Per kid: $10.50 ÷ 3 = $3.50

Hmm, that seems odd but mathematically correct based on given numbers.

But let’s re-read: “Jonas spent $14 on entry tickets for himself and his 3 children.” So 4 tickets total.

If adult is $3.50, then 3 kids cost $10.50 → $3.50 each.

Maybe it’s a trick? Or maybe the problem meant something else? But based on what’s written, that’s the math.

Alternatively, perhaps “$14” includes something else? No, it says “on entry tickets”.

So answer is $3.50 per child.

Wait — let me check if I misread.

“Jonas spent $14 on entry tickets for himself and his 3 children. If the adult ticket is $3.50, how much did the entry fee for each child cost?”

Yes → 1 adult + 3 children = 4 tickets.

Adult: $3.50
Total: $14
Children total: $10.50
Per child: $3.50

It’s correct, even if surprising.

✔ Answer: $3.50

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Problem 3:

Girls in first grade account for one-third of the class. 3 girls are absent today. Today, only half the class attended. How many girls are in the class?

Let total class size = T

Girls = (1/3)T

Today, half the class attended → (1/2)T students present.

Of those present, 3 girls were absent → so girls present = (1/3)T - 3

But we don’t know how many boys attended. The problem doesn’t say anything about boys being absent or present.

Wait — maybe we need to assume that only girls were absent? But it doesn’t say that.

Actually, rereading: “3 girls are absent today. Find the total strength of the class, if 4 girls attended class today.”

Oh! Wait — I missed that part!

The problem says: “3 girls are absent today. Find the total strength of the class, if 4 girls attended class today.”

That changes everything!

So:

Girls present today = 4
Girls absent = 3
→ Total girls = 4 + 3 = 7

And girls are one-third of the class → so total class = 7 × 3 = 21

Check: 1/3 of 21 = 7 girls → 4 attended, 3 absent → matches.

Also, half the class attended → 21 ÷ 2 = 10.5 → not possible!

Wait — contradiction.

If total class is 21, half would be 10.5 — impossible.

So maybe “half the class attended” refers to something else?

Let me read again:

“Girls in the first grade account for one-third of the total strength of the class. 3 girls are absent today. Find the total strength of the class, if 4 girls attended class today.”

It doesn’t mention “half the class attended” in the version I have? Wait — looking back at original image text:

In the user’s image transcription, problem 3 says:

“3) Girls in the first grade account for one-third of the total strength of the class. 3 girls are absent today. Find the total strength of the class, if 4 girls attended class today.”

No mention of “half the class attended” — I must have misread earlier.

In my initial thought, I added “half the class attended” — but that’s not in the problem.

Looking back at the user’s input:

In the image description, problem 3 is:

“3) Girls in the first grade account for one-third of the total strength of the class. 3 girls are absent today. Find the total strength of the class, if 4 girls attended class today.”

So no “half” mentioned. My mistake.

So:

Girls present = 4
Girls absent = 3
Total girls = 7

Girls = 1/3 of class → class size = 7 × 3 = 21

✔ Final answer: 21

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Problem 4:

Monday: $99.55 collected
Tuesday: 40 students ate lunch, each paid $1.50 → 40 × $1.50 = $60.00
Total lunch money = $99.55 + $60.00 = $159.55

✔ Answer: $159.55

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Problem 5:

Zoe worked 40 hours in July → entitled to $600.65
She also worked 5 hours overtime.
She received a paycheck of $1180.45 for the month.
How much is she paid per hour of overtime work?

First, regular pay for 40 hours = $600.65
Overtime pay = total pay - regular pay = $1180.45 - $600.65 = $579.80
This is for 5 hours of overtime.

So, overtime rate per hour = $579.80 ÷ 5 = $115.96

Check: 5 × $115.96 = $579.80 → yes.

Total pay: $600.65 + $579.80 = $1180.45 → matches.

✔ Answer: $115.96

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Now, compiling all final answers:

Problem 1: 5 weeks
Problem 2: $3.50
Problem 3: 21
Problem 4: $159.55
Problem 5: $115.96

Final Answer:
5 weeks, $3.50, 21, $159.55, $115.96