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Perimeter and Area Practice Worksheet with Rectangles and Measurements.

Worksheet with nine rectangles showing dimensions for calculating perimeter and area.

Worksheet with nine rectangles showing dimensions for calculating perimeter and area.

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Show Answer Key & Explanations Step-by-step solution for: Perimeter and Area Worksheet for 6th Grade | Lesson Planet
The image you uploaded contains a worksheet titled "Perimeter and Area". The task involves calculating the perimeter and area of various rectangles and squares. Below, I will solve each problem step by step.

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Key Formulas:


1. Perimeter of a Rectangle/Square:
- For a rectangle: \( P = 2 \times (\text{length} + \text{width}) \)
- For a square: \( P = 4 \times \text{side length} \)

2. Area of a Rectangle/Square:
- For a rectangle: \( A = \text{length} \times \text{width} \)
- For a square: \( A = \text{side length}^2 \)

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Solutions:



#### Problem 1:
- Dimensions: Length = 27 cm, Width = 8 cm
- Perimeter: \( P = 2 \times (27 + 8) = 2 \times 35 = 70 \) cm
- Area: \( A = 27 \times 8 = 216 \) cm²

#### Problem 2:
- Dimensions: Length = 21 cm, Width = 16 cm
- Perimeter: \( P = 2 \times (21 + 16) = 2 \times 37 = 74 \) cm
- Area: \( A = 21 \times 16 = 336 \) cm²

#### Problem 3:
- Dimensions: Side = 10 cm (square)
- Perimeter: \( P = 4 \times 10 = 40 \) cm
- Area: \( A = 10^2 = 100 \) cm²

#### Problem 4:
- Dimensions: Length = 11 cm, Width = 9 cm
- Perimeter: \( P = 2 \times (11 + 9) = 2 \times 20 = 40 \) cm
- Area: \( A = 11 \times 9 = 99 \) cm²

#### Problem 5:
- Dimensions: Length = 15 cm, Width = 8 cm
- Perimeter: \( P = 2 \times (15 + 8) = 2 \times 23 = 46 \) cm
- Area: \( A = 15 \times 8 = 120 \) cm²

#### Problem 6:
- Dimensions: Length = 15 cm, Width = 15 cm (square)
- Perimeter: \( P = 4 \times 15 = 60 \) cm
- Area: \( A = 15^2 = 225 \) cm²

#### Problem 7:
- Dimensions: Length = 13 cm, Width = 11 cm
- Perimeter: \( P = 2 \times (13 + 11) = 2 \times 24 = 48 \) cm
- Area: \( A = 13 \times 11 = 143 \) cm²

#### Problem 8:
- Dimensions: Length = 20 cm, Width = 19 cm
- Perimeter: \( P = 2 \times (20 + 19) = 2 \times 39 = 78 \) cm
- Area: \( A = 20 \times 19 = 380 \) cm²

#### Problem 9:
- Dimensions: Length = 20 cm, Width = 26 cm
- Perimeter: \( P = 2 \times (20 + 26) = 2 \times 46 = 92 \) cm
- Area: \( A = 20 \times 26 = 520 \) cm²

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Final Answers:



| Problem | Perimeter (cm) | Area (cm²) |
|---------|----------------|------------|
| 1 | 70 | 216 |
| 2 | 74 | 336 |
| 3 | 40 | 100 |
| 4 | 40 | 99 |
| 5 | 46 | 120 |
| 6 | 60 | 225 |
| 7 | 48 | 143 |
| 8 | 78 | 380 |
| 9 | 92 | 520 |

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Boxed Final Answer:


\[
\boxed{
\begin{array}{c|c|c}
\text{Problem} & \text{Perimeter (cm)} & \text{Area (cm²)} \\
\hline
1 & 70 & 216 \\
2 & 74 & 336 \\
3 & 40 & 100 \\
4 & 40 & 99 \\
5 & 46 & 120 \\
6 & 60 & 225 \\
7 & 48 & 143 \\
8 & 78 & 380 \\
9 & 92 & 520 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of 6th grade area and perimeter worksheet.
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