To solve the perimeter problems, we need to calculate the total length of the boundary of each shape. The perimeter is found by adding up all the side lengths of the shape. Let's go through each problem step by step.
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Problem 1: Square
- Side length = 23 mm
- Perimeter of a square = \(4 \times \text{side length}\)
- Perimeter = \(4 \times 23 = 92\) mm
Answer: 92 mm
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Problem 2: Pentagon
- Side lengths: 11 in, 12 in, 13 in, 14 in, 14 in
- Perimeter = Sum of all side lengths
- Perimeter = \(11 + 12 + 13 + 14 + 14 = 64\) in
Answer: 64 in
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Problem 3: Triangle
- Side lengths: 27 ft (all sides are equal, as it is an equilateral triangle)
- Perimeter = \(3 \times \text{side length}\)
- Perimeter = \(3 \times 27 = 81\) ft
Answer: 81 ft
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Problem 4: Rectangle
- Length = 145 m
- Width = 72 m
- Perimeter of a rectangle = \(2 \times (\text{length} + \text{width})\)
- Perimeter = \(2 \times (145 + 72) = 2 \times 217 = 434\) m
Answer: 434 m
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Problem 5: Irregular Pentagon
- Side lengths: 30 cm, 35 cm, 37 cm, 46 cm, 26 cm
- Perimeter = Sum of all side lengths
- Perimeter = \(30 + 35 + 37 + 46 + 26 = 174\) cm
Answer: 174 cm
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Problem 6: Triangle
- Side lengths: 95 yds, 206 yds, 246 yds
- Perimeter = Sum of all side lengths
- Perimeter = \(95 + 206 + 246 = 547\) yds
Answer: 547 yds
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Problem 7: Rhombus
- Side length = 3.5 km (all sides are equal)
- Perimeter of a rhombus = \(4 \times \text{side length}\)
- Perimeter = \(4 \times 3.5 = 14\) km
Answer: 14 km
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Problem 8: Irregular Hexagon
- Side lengths: 45 mi, 45 mi, 56 mi, 63 mi, 82 mi, 56 mi
- Perimeter = Sum of all side lengths
- Perimeter = \(45 + 45 + 56 + 63 + 82 + 56 = 347\) mi
Answer: 347 mi
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Problem 9: Irregular Shape
- Side lengths: 1,200 mm, 750 mm, 400 mm, 750 mm, 1,200 mm
- Perimeter = Sum of all side lengths
- Perimeter = \(1,200 + 750 + 400 + 750 + 1,200 = 4,300\) mm
Answer: 4,300 mm
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Problem 10: Rectangle
- Length = 140 in
- Width = 66 in
- Perimeter of a rectangle = \(2 \times (\text{length} + \text{width})\)
- Perimeter = \(2 \times (140 + 66) = 2 \times 206 = 412\) in
Answer: 412 in
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Final Answers:
1. 92 mm
2. 64 in
3. 81 ft
4. 434 m
5. 174 cm
6. 547 yds
7. 14 km
8. 347 mi
9. 4,300 mm
10. 412 in
Boxed Final Answer:
\[
\boxed{92, 64, 81, 434, 174, 547, 14, 347, 4300, 412}
\]
Parent Tip: Review the logic above to help your child master the concept of 6th grade area and perimeter worksheet.