Final Answer:
1. $\frac{1}{6}$
2. $\frac{2}{6} = \frac{1}{3}$
3. $\frac{1}{6}$
4. Even number — because there are 3 even numbers (2, 4, 4) and only 2 odd numbers (1, 1, 3 → actually 3 odds? Wait—let’s count carefully: sections show: 1, 1, 2, 3, 4, 4 → that’s six sections: odds = 1, 1, 3 → 3 odds; evens = 2, 4, 4 → 3 evens. So equally likely. Correct answer: Neither — they are equally likely.
5. $\frac{2}{4} = \frac{1}{2}$
6. $\frac{1}{4}$
7. Primary colors are red and blue (orange is not primary), so red + blue = 2 out of 4 → $\frac{2}{4} = \frac{1}{2}$
Wait — let me double-check the spinner details from the problem:
First spinner (6 sections): labeled 1, 1, 2, 3, 4, 4 — yes, 6 equal sections.
Second spinner (4 sections): red, blue, orange, red — so colors: red (2), blue (1), orange (1).
Primary colors: red, blue, yellow — but yellow isn’t present. So only red and blue count.
So:
1. P(3) = 1 section out of 6 → $\frac{1}{6}$
2. P(1) = 2 sections → $\frac{2}{6} = \frac{1}{3}$
3. P(2) = 1 section → $\frac{1}{6}$
4. Odd numbers: 1, 1, 3 → 3 sections; Even: 2, 4, 4 → 3 sections → equally likely → answer: *Neither — they are equally likely.*
5. P(red) = 2 out of 4 → $\frac{1}{2}$
6. P(orange) = 1 out of 4 → $\frac{1}{4}$
7. Primary colors on spinner: red and blue → 2 out of 4 → $\frac{1}{2}$
Final Answer:
1. $\frac{1}{6}$
2. $\frac{1}{3}$
3. $\frac{1}{6}$
4. Neither — there are 3 odd and 3 even numbers, so they are equally likely.
5. $\frac{1}{2}$
6. $\frac{1}{4}$
7. $\frac{1}{2}$
Parent Tip: Review the logic above to help your child master the concept of 6th grade math probability worksheet.
