50+ Math Word Problems worksheets for 6th Grade on Quizizz | Free ... - Free Printable

Let's solve each problem step by step.

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Problem 1:

Mario has room for 15 more minutes of songs on his iPod. He is going to upload three songs that are 5.15, 44, and 4.8 minutes long. About how many minutes will he have room for after he uploads these three songs?

#### Solution:
1. Calculate the total length of the three songs:
\[
5.15 + 44 + 4.8 = 53.95 \text{ minutes}
\]

2. Mario initially has room for 15 minutes. After uploading the songs, the remaining space is:
\[
15 - 53.95 = -38.95 \text{ minutes}
\]

Since the result is negative, Mario does not have enough space to upload all three songs. However, if we interpret the question as asking how much space he would have left if he could somehow fit the songs, the answer would be approximately 0 minutes (since he exceeds the capacity).

Given the options, the closest reasonable answer is:
\[
\boxed{A} \text{ (1 minute)}
\]

---

Problem 2:

A banner measures 2.8 feet long and 1.2 feet wide. Which is a good estimate for the area of the banner?

#### Solution:
1. The area of a rectangle is given by:
\[
\text{Area} = \text{length} \times \text{width}
\]

2. Substitute the given dimensions:
\[
\text{Area} = 2.8 \times 1.2
\]

3. Perform the multiplication:
\[
2.8 \times 1.2 = 3.36 \text{ square feet}
\]

4. Among the given options, the closest estimate is:
\[
\boxed{A} \text{ (7 square feet)}
\]

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Problem 3:

Barb is making a brick border around her patio. The distance around her patio measures approximately 553 inches. Each brick is about 8 inches long. About how many bricks will Barb need to make the border?

#### Solution:
1. To find the number of bricks needed, divide the total perimeter of the patio by the length of one brick:
\[
\text{Number of bricks} = \frac{\text{Perimeter}}{\text{Length of one brick}}
\]

2. Substitute the given values:
\[
\text{Number of bricks} = \frac{553}{8}
\]

3. Perform the division:
\[
\frac{553}{8} = 69.125
\]

4. Since Barb cannot use a fraction of a brick, round up to the nearest whole number:
\[
69.125 \approx 70
\]

5. Among the given options, the closest estimate is:
\[
\boxed{C} \text{ (70)}
\]

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Problem 4:

Juanita made a fruit salad. She put 3 7/8 cups of cantaloupe and 2 2/4 cups of honeydew melon in the salad. About how many cups of melon did she put in the fruit salad?

#### Solution:
1. Convert the mixed numbers to improper fractions:
\[
3 \frac{7}{8} = \frac{3 \times 8 + 7}{8} = \frac{24 + 7}{8} = \frac{31}{8}
\]
\[
2 \frac{2}{4} = \frac{2 \times 4 + 2}{4} = \frac{8 + 2}{4} = \frac{10}{4} = \frac{5}{2}
\]

2. Add the two fractions. First, find a common denominator. The least common multiple of 8 and 2 is 8:
\[
\frac{5}{2} = \frac{5 \times 4}{2 \times 4} = \frac{20}{8}
\]

3. Now add the fractions:
\[
\frac{31}{8} + \frac{20}{8} = \frac{31 + 20}{8} = \frac{51}{8}
\]

4. Convert the improper fraction back to a mixed number:
\[
\frac{51}{8} = 6 \frac{3}{8}
\]

5. Among the given options, the closest estimate is:
\[
\boxed{A} \text{ (6 cups)}
\]

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Problem 5:

Last week a professional hockey team sold 3,626 season tickets. This week it sold 889 season tickets on Monday, 2,677 on Tuesday, and 1,892 on Wednesday. Which is the best estimate for the total number of season tickets the team sold during last week and during these three days?

#### Solution:
1. Calculate the total number of tickets sold this week:
\[
889 + 2,677 + 1,892
\]

2. Perform the addition:
\[
889 + 2,677 = 3,566
\]
\[
3,566 + 1,892 = 5,458
\]

3. Add the tickets sold last week to the tickets sold this week:
\[
3,626 + 5,458 = 9,084
\]

4. Among the given options, the closest estimate is:
\[
\boxed{C} \text{ (9,100)}
\]

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Final Answers:

1. \(\boxed{A}\)
2. \(\boxed{A}\)
3. \(\boxed{C}\)
4. \(\boxed{A}\)
5. \(\boxed{C}\)