6th Grade Percent Word Problems - Free Printable

Let's solve each problem step by step.

---

Problem 1:

A pie shop sells 32 apple pies, 33 pumpkin pies, 20 cherry pies, and 15 chocolate pies. What percentage of pies sold were apple or cherry?

#### Solution:
1. Calculate the total number of pies sold:
\[
32 + 33 + 20 + 15 = 90
\]

2. Calculate the number of apple or cherry pies sold:
\[
32 + 20 = 52
\]

3. Calculate the percentage of apple or cherry pies:
\[
\text{Percentage} = \left( \frac{\text{Number of apple or cherry pies}}{\text{Total number of pies}} \right) \times 100
\]
\[
\text{Percentage} = \left( \frac{52}{90} \right) \times 100 \approx 57.78\%
\]

4. Round to the nearest whole number:
\[
57.78\% \approx 58\%
\]

Answer:
\[
\boxed{58}
\]

---

Problem 2:

Newton watches a movie with his friends. They watch 50% of the movie and then take a break. They then watch the remaining 65 minutes. How long was the movie?

#### Solution:
1. Let the total length of the movie be \( x \) minutes.

2. They watched 50% of the movie initially:
\[
0.5x
\]

3. They watched the remaining 65 minutes after the break:
\[
x - 0.5x = 0.5x
\]
So, \( 0.5x = 65 \).

4. Solve for \( x \):
\[
x = \frac{65}{0.5} = 130
\]

Answer:
\[
\boxed{130}
\]

---

Problem 3:

Captain’s Autos sells 22 used cars on Monday and 18 cars on Tuesday. This was 25% of the number of sales for the week. How many cars did they sell altogether that week?

#### Solution:
1. Calculate the total number of cars sold on Monday and Tuesday:
\[
22 + 18 = 40
\]

2. Let the total number of cars sold in the week be \( x \).

3. According to the problem, 40 cars represent 25% of the total sales:
\[
0.25x = 40
\]

4. Solve for \( x \):
\[
x = \frac{40}{0.25} = 160
\]

Answer:
\[
\boxed{160}
\]

---

Problem 4:

Sally spends 15% of her weekly budget on food and 35% on rent. She has $350 left over. How much was her budget?

#### Solution:
1. Let Sally's weekly budget be \( x \).

2. She spends 15% on food and 35% on rent:
\[
\text{Spent on food} = 0.15x
\]
\[
\text{Spent on rent} = 0.35x
\]

3. The remaining amount is $350:
\[
x - (0.15x + 0.35x) = 350
\]
\[
x - 0.50x = 350
\]
\[
0.50x = 350
\]

4. Solve for \( x \):
\[
x = \frac{350}{0.50} = 700
\]

Answer:
\[
\boxed{700}
\]

---

Problem 5:

There are 30 6th graders and 40 7th graders in a group. 10% of the 6th graders and 25% of the 7th graders are vegan. How many vegans are in the group altogether?

#### Solution:
1. Calculate the number of vegan 6th graders:
\[
10\% \text{ of } 30 = 0.10 \times 30 = 3
\]

2. Calculate the number of vegan 7th graders:
\[
25\% \text{ of } 40 = 0.25 \times 40 = 10
\]

3. Calculate the total number of vegans:
\[
3 + 10 = 13
\]

Answer:
\[
\boxed{13}
\]

---

Problem 6:

Tyger and Newton have a long jump competition. Tyger jumps 20% further than Newton. If Newton jumps 400 cm, how far does Tyger jump?

#### Solution:
1. Let Newton's jump distance be \( 400 \) cm.

2. Tyger jumps 20% further than Newton:
\[
\text{Tyger's jump} = 400 + (0.20 \times 400)
\]
\[
\text{Tyger's jump} = 400 + 80 = 480 \text{ cm}
\]

Answer:
\[
\boxed{480}
\]

---

Final Answers:

1. \(\boxed{58}\)
2. \(\boxed{130}\)
3. \(\boxed{160}\)
4. \(\boxed{700}\)
5. \(\boxed{13}\)
6. \(\boxed{480}\)