Math Problem Solving Worksheets For Grade 6 - Free Printable

Let's solve each problem step by step:

---

Problem 1:

Lucas is making cookies for a school field trip. Lucas had 50 kids in his 8th grade class. If Lucas wanted to ensure each child got 5 cookies, how many cookies should he make?

#### Solution:
- Number of kids = 50
- Cookies per kid = 5
- Total cookies needed = Number of kids × Cookies per kid
- Total cookies needed = \( 50 \times 5 = 250 \)

#### Answer:
\[
\boxed{250}
\]

---

Problem 2:

Sarah noticed that \( \frac{1}{4} \) of her clothes were sitting on the ground. She also noticed that \( \frac{1}{2} \) of her clothes were laying in the bathroom. How many items of clothes did Sarah have that weren't in her closet?

#### Solution:
- Let the total number of clothes Sarah has be \( x \).
- Clothes on the ground = \( \frac{1}{4}x \)
- Clothes in the bathroom = \( \frac{1}{2}x \)
- Clothes not in the closet = Clothes on the ground + Clothes in the bathroom
- Clothes not in the closet = \( \frac{1}{4}x + \frac{1}{2}x \)
- To add these fractions, find a common denominator (which is 4):
\[
\frac{1}{4}x + \frac{1}{2}x = \frac{1}{4}x + \frac{2}{4}x = \frac{3}{4}x
\]
- Therefore, \( \frac{3}{4} \) of her clothes are not in the closet.

#### Answer:
\[
\boxed{\frac{3}{4}}
\]

---

Problem 3:

Mitsy the cat loved to eat tuna. He wanted to make sure that he had enough tuna for the whole week. If Mitsy ate \( \frac{1}{2} \) a can of tuna a day, how many cans would he need for a whole week?

#### Solution:
- Tuna eaten per day = \( \frac{1}{2} \) can
- Number of days in a week = 7
- Total cans needed = Tuna eaten per day × Number of days
- Total cans needed = \( \frac{1}{2} \times 7 = \frac{7}{2} = 3.5 \)

#### Answer:
\[
\boxed{3.5}
\]

---

Problem 4:

There are 90 kids that attend Harlem High School. If 40 are in Mrs. Fetter's class and 20 are in Mrs. Cassy's class, what percent make up the last classroom?

#### Solution:
- Total number of kids = 90
- Kids in Mrs. Fetter's class = 40
- Kids in Mrs. Cassy's class = 20
- Kids in the last classroom = Total kids - (Kids in Mrs. Fetter's class + Kids in Mrs. Cassy's class)
- Kids in the last classroom = \( 90 - (40 + 20) = 90 - 60 = 30 \)
- Percentage of kids in the last classroom = \( \left( \frac{\text{Kids in the last classroom}}{\text{Total kids}} \right) \times 100 \)
- Percentage = \( \left( \frac{30}{90} \right) \times 100 = \frac{1}{3} \times 100 = 33.\overline{3}\% \)

#### Answer:
\[
\boxed{33.\overline{3}}
\]

---

Problem 5:

Bradley was passing out flyers to different neighborhoods. There were 20 neighborhoods that he wanted to hit. If each neighborhood had 83 houses, how many flyers would Bradley need?

#### Solution:
- Number of neighborhoods = 20
- Houses per neighborhood = 83
- Total flyers needed = Number of neighborhoods × Houses per neighborhood
- Total flyers needed = \( 20 \times 83 = 1660 \)

#### Answer:
\[
\boxed{1660}
\]

---

Final Answers:

1. \(\boxed{250}\)
2. \(\boxed{\frac{3}{4}}\)
3. \(\boxed{3.5}\)
4. \(\boxed{33.\overline{3}}\)
5. \(\boxed{1660}\)