Mixed Operations Math Crossword Puzzle for kids to solve with addition, subtraction, multiplication, and division.

To solve the mixed operations crossword puzzle, we need to fill in the blanks such that all the equations are true. Let's break it down step by step.

Puzzle Layout:

The crossword puzzle consists of horizontal and vertical equations. We will solve each equation systematically.

---

Horizontal Equations:

1. Top Row:
\[
12 + \_ = 36
\]
- Solve for the blank:
\[
12 + x = 36 \implies x = 36 - 12 = 24
\]
- Fill in: \( 24 \)

2. Second Row:
\[
\_ - \_ = 4
\]
- This equation has two blanks. We will revisit it after solving other equations.

3. Third Row:
\[
\_ \times \_ = 6
\]
- Possible pairs that multiply to 6: \( (1, 6), (2, 3), (3, 2), (6, 1) \)
- We will determine the correct pair based on intersecting equations.

4. Fourth Row:
\[
\_ \times 5 = \_
\]
- This equation has two blanks. We will revisit it after solving other equations.

5. Fifth Row:
\[
56 - \_ = \_
\]
- This equation has two blanks. We will revisit it after solving other equations.

6. Bottom Row:
\[
20 - \_ = 11
\]
- Solve for the blank:
\[
20 - x = 11 \implies x = 20 - 11 = 9
\]
- Fill in: \( 9 \)

---

Vertical Equations:

1. First Column:
\[
12 + \_ = \_
\]
- The top row already gives us \( 12 + 24 = 36 \).
- The second row is \( \_ - \_ = 4 \).

2. Second Column:
\[
\_ \div \_ = \_
\]
- This equation has three blanks. We will revisit it after solving other equations.

3. Third Column:
\[
\_ \times \_ = 6
\]
- This is the same as the third row horizontal equation.

4. Fourth Column:
\[
\_ \times 5 = \_
\]
- This is the same as the fourth row horizontal equation.

5. Fifth Column:
\[
\_ + \_ = \_
\]
- This equation has three blanks. We will revisit it after solving other equations.

6. Sixth Column:
\[
23 + \_ = \_
\]
- This equation has two blanks. We will revisit it after solving other equations.

---

Solving Step-by-Step:

#### Horizontal Equation (Second Row):
\[
\_ - \_ = 4
\]
- Let’s denote the blanks as \( a \) and \( b \):
\[
a - b = 4
\]

#### Horizontal Equation (Third Row):
\[
\_ \times \_ = 6
\]
- Possible pairs: \( (1, 6), (2, 3), (3, 2), (6, 1) \)

#### Horizontal Equation (Fourth Row):
\[
\_ \times 5 = \_
\]
- Let’s denote the blanks as \( c \) and \( d \):
\[
c \times 5 = d
\]

#### Horizontal Equation (Fifth Row):
\[
56 - \_ = \_
\]
- Let’s denote the blanks as \( e \) and \( f \):
\[
56 - e = f
\]

#### Vertical Equation (Second Column):
\[
\_ \div \_ = \_
\]
- Let’s denote the blanks as \( g \), \( h \), and \( i \):
\[
g \div h = i
\]

#### Vertical Equation (Fourth Column):
\[
\_ \times 5 = \_
\]
- This is the same as the fourth row horizontal equation.

#### Vertical Equation (Fifth Column):
\[
\_ + \_ = \_
\]
- Let’s denote the blanks as \( j \), \( k \), and \( l \):
\[
j + k = l
\]

#### Vertical Equation (Sixth Column):
\[
23 + \_ = \_
\]
- Let’s denote the blanks as \( m \) and \( n \):
\[
23 + m = n
\]

---

Filling in Known Values:

1. Top row: \( 12 + 24 = 36 \)
- First column: \( 12 + 24 = 36 \)

2. Bottom row: \( 20 - 9 = 11 \)
- Sixth column: \( 23 + 9 = 32 \)

---

Solving Remaining Equations:

#### Third Row:
\[
\_ \times \_ = 6
\]
- From the third column, we need a pair that fits. Let’s try \( 2 \times 3 = 6 \).

#### Fourth Row:
\[
\_ \times 5 = \_
\]
- From the fourth column, let’s try \( 2 \times 5 = 10 \).

#### Fifth Row:
\[
56 - \_ = \_
\]
- Let’s try \( 56 - 7 = 49 \).

#### Second Row:
\[
\_ - \_ = 4
\]
- From the first column, let’s try \( 8 - 4 = 4 \).

#### Second Column:
\[
\_ \div \_ = \_
\]
- From the second column, let’s try \( 8 \div 2 = 4 \).

#### Fifth Column:
\[
\_ + \_ = \_
\]
- From the fifth column, let’s try \( 4 + 5 = 9 \).

---

Final Puzzle:

After filling in all the blanks, the completed crossword puzzle looks like this:

\[
\begin{array}{|c|c|c|c|c|c|}
\hline
12 & + & 24 & = & 36 & \\
\hline
8 & - & 4 & = & 4 & \\
\hline
2 & \times & 3 & = & 6 & \\
\hline
2 & \times & 5 & = & 10 & \\
\hline
56 & - & 7 & = & 49 & \\
\hline
20 & - & 9 & = & 11 & \\
\hline
\end{array}
\]

---

Final Answer:

\[
\boxed{
\begin{array}{|c|c|c|c|c|c|}
\hline
12 & + & 24 & = & 36 & \\
\hline
8 & - & 4 & = & 4 & \\
\hline
2 & \times & 3 & = & 6 & \\
\hline
2 & \times & 5 & = & 10 & \\
\hline
56 & - & 7 & = & 49 & \\
\hline
20 & - & 9 & = & 11 & \\
\hline
\end{array}
}
\]