Grade 7 Word Problems Set 4. Math - Fill and Sign Printable ... - Free Printable
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Step-by-step solution for: Grade 7 Word Problems Set 4. Math - Fill and Sign Printable ...
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Step-by-step solution for: Grade 7 Word Problems Set 4. Math - Fill and Sign Printable ...
Let's solve each problem step by step.
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Question: Kory had an ant farm with three sections. In the first section, there were 32 ants, and in the second section, there were 98 ants. If there were 178 ants total, how many ants were in the third section?
Solution:
1. Let the number of ants in the third section be \( x \).
2. The total number of ants is given as 178.
3. The ants in the first section are 32, and in the second section are 98.
4. Therefore, we can write the equation:
\[
32 + 98 + x = 178
\]
5. Simplify the left side:
\[
130 + x = 178
\]
6. Solve for \( x \):
\[
x = 178 - 130
\]
\[
x = 48
\]
Answer: The number of ants in the third section is \(\boxed{48}\).
---
Question: For every dollar Billy makes, he has to pay $0.15 to his dad for rent. If he makes $827 dollars, how much money does Billy have to pay to his dad?
Solution:
1. Billy pays $0.15 for every dollar he earns.
2. Billy earns $827.
3. The amount Billy has to pay is:
\[
827 \times 0.15
\]
4. Perform the multiplication:
\[
827 \times 0.15 = 124.05
\]
Answer: Billy has to pay \(\boxed{124.05}\) dollars to his dad.
---
Question: Phil wanted to be able to climb up at least 93% of the mountain. If the mountain was 1,828 feet tall, what is the least amount of feet Phil would have to climb to reach his goal?
Solution:
1. The height of the mountain is 1,828 feet.
2. Phil wants to climb at least 93% of the mountain.
3. Calculate 93% of 1,828:
\[
0.93 \times 1,828
\]
4. Perform the multiplication:
\[
0.93 \times 1,828 = 1,700.04
\]
Answer: The least amount of feet Phil would have to climb is \(\boxed{1700.04}\).
---
Question: There was a scalene triangle that had a height of 6 feet tall. If the base of the triangle was 3 feet tall, what was the area of this scalene triangle?
Solution:
1. The formula for the area of a triangle is:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
2. The base of the triangle is 3 feet, and the height is 6 feet.
3. Substitute the values into the formula:
\[
\text{Area} = \frac{1}{2} \times 3 \times 6
\]
4. Perform the multiplication:
\[
\text{Area} = \frac{1}{2} \times 18 = 9
\]
Answer: The area of the scalene triangle is \(\boxed{9}\) square feet.
---
Question: Emily was drawing a circle for her art project. If the diameter of the circle was 8 ft, what was the circumference of the circle that she was drawing for her project?
Solution:
1. The formula for the circumference of a circle is:
\[
\text{Circumference} = \pi \times \text{diameter}
\]
2. The diameter of the circle is 8 ft.
3. Substitute the value into the formula:
\[
\text{Circumference} = \pi \times 8
\]
4. Use the approximation \(\pi \approx 3.14\):
\[
\text{Circumference} = 3.14 \times 8 = 25.12
\]
Answer: The circumference of the circle is \(\boxed{25.12}\) feet.
---
1. \(\boxed{48}\)
2. \(\boxed{124.05}\)
3. \(\boxed{1700.04}\)
4. \(\boxed{9}\)
5. \(\boxed{25.12}\)
---
Problem 1:
Question: Kory had an ant farm with three sections. In the first section, there were 32 ants, and in the second section, there were 98 ants. If there were 178 ants total, how many ants were in the third section?
Solution:
1. Let the number of ants in the third section be \( x \).
2. The total number of ants is given as 178.
3. The ants in the first section are 32, and in the second section are 98.
4. Therefore, we can write the equation:
\[
32 + 98 + x = 178
\]
5. Simplify the left side:
\[
130 + x = 178
\]
6. Solve for \( x \):
\[
x = 178 - 130
\]
\[
x = 48
\]
Answer: The number of ants in the third section is \(\boxed{48}\).
---
Problem 2:
Question: For every dollar Billy makes, he has to pay $0.15 to his dad for rent. If he makes $827 dollars, how much money does Billy have to pay to his dad?
Solution:
1. Billy pays $0.15 for every dollar he earns.
2. Billy earns $827.
3. The amount Billy has to pay is:
\[
827 \times 0.15
\]
4. Perform the multiplication:
\[
827 \times 0.15 = 124.05
\]
Answer: Billy has to pay \(\boxed{124.05}\) dollars to his dad.
---
Problem 3:
Question: Phil wanted to be able to climb up at least 93% of the mountain. If the mountain was 1,828 feet tall, what is the least amount of feet Phil would have to climb to reach his goal?
Solution:
1. The height of the mountain is 1,828 feet.
2. Phil wants to climb at least 93% of the mountain.
3. Calculate 93% of 1,828:
\[
0.93 \times 1,828
\]
4. Perform the multiplication:
\[
0.93 \times 1,828 = 1,700.04
\]
Answer: The least amount of feet Phil would have to climb is \(\boxed{1700.04}\).
---
Problem 4:
Question: There was a scalene triangle that had a height of 6 feet tall. If the base of the triangle was 3 feet tall, what was the area of this scalene triangle?
Solution:
1. The formula for the area of a triangle is:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
2. The base of the triangle is 3 feet, and the height is 6 feet.
3. Substitute the values into the formula:
\[
\text{Area} = \frac{1}{2} \times 3 \times 6
\]
4. Perform the multiplication:
\[
\text{Area} = \frac{1}{2} \times 18 = 9
\]
Answer: The area of the scalene triangle is \(\boxed{9}\) square feet.
---
Problem 5:
Question: Emily was drawing a circle for her art project. If the diameter of the circle was 8 ft, what was the circumference of the circle that she was drawing for her project?
Solution:
1. The formula for the circumference of a circle is:
\[
\text{Circumference} = \pi \times \text{diameter}
\]
2. The diameter of the circle is 8 ft.
3. Substitute the value into the formula:
\[
\text{Circumference} = \pi \times 8
\]
4. Use the approximation \(\pi \approx 3.14\):
\[
\text{Circumference} = 3.14 \times 8 = 25.12
\]
Answer: The circumference of the circle is \(\boxed{25.12}\) feet.
---
Final Answers:
1. \(\boxed{48}\)
2. \(\boxed{124.05}\)
3. \(\boxed{1700.04}\)
4. \(\boxed{9}\)
5. \(\boxed{25.12}\)
Parent Tip: Review the logic above to help your child master the concept of 7th grade algebra word problems worksheet.