Investigate chance processes and develop, use, and evaluate ... - Free Printable

Final Answer:
1. 1/6
2. 1/3
3. 1/6
4. You are more likely to spin an odd number because there are 3 odd numbers (1, 1, 3) and only 2 even numbers (2, 4, 4 — but 4 appears twice, so still only 2 unique even outcomes? Wait — let’s count actual sections: the spinner has 6 equal sections: 1, 1, 2, 3, 4, 4. So odd numbers: 1, 1, 3 → 3 sections. Even numbers: 2, 4, 4 → 3 sections. So actually, they are equally likely. Correction: 3 odd sections, 3 even sections → equally likely.

Wait — let me recount carefully:

Sections:
- 1 (odd)
- 1 (odd)
- 2 (even)
- 3 (odd)
- 4 (even)
- 4 (even)

So:
Odd: 1, 1, 3 → 3 sections
Even: 2, 4, 4 → 3 sections

→ Equal chance!

So final corrected answer for #4: You are equally likely to spin an odd or even number, because there are 3 odd-numbered sections and 3 even-numbered sections.

──────────────────────────────────────

Explanation:
Let’s go one question at a time.

1. What is the probability of landing on a 3?
→ The spinner has 6 equal parts. Only 1 part has a 3.
→ So, 1 out of 6 → 1/6.

2. What is the probability of landing on a 1?
→ Look: two parts have a 1.
→ So, 2 out of 6 → that’s 2/6, which simplifies to 1/3.

3. What is the probability of landing on a 2?
→ Only one part has a 2.
→ So, 1 out of 6 → 1/6.

4. Are you more likely to spin an odd or even number?
→ Odd numbers: 1, 1, 3 → that’s 3 sections.
→ Even numbers: 2, 4, 4 → that’s also 3 sections.
→ Same number of sections → same chance!
→ So, you’re equally likely to get odd or even.

Tip: Always count the actual sections — not just the different numbers. For example, even though “4” appears twice, it counts as two separate sections.

──────────────────────────────────────