Let's solve each of these literal equations for the indicated variable. We'll go step by step, showing the algebraic manipulations needed to isolate the desired variable.
---
1. $ P = IRT $ for $ T $
We want to solve for $ T $.
Divide both sides by $ IR $:
$$
T = \frac{P}{IR}
$$
✔ Answer: $ T = \frac{P}{IR} $
---
2. $ A = 2L + W $ for $ W $
We want to solve for $ W $.
Subtract $ 2L $ from both sides:
$$
W = A - 2L
$$
✔ Answer: $ W = A - 2L $
---
3. $ y = 5x - 6 $ for $ x $
We want to solve for $ x $.
Add 6 to both sides:
$$
y + 6 = 5x
$$
Now divide by 5:
$$
x = \frac{y + 6}{5}
$$
✔ Answer: $ x = \frac{y + 6}{5} $
---
4. $ 2x - 3y = 8 $ for $ y $
We want to solve for $ y $.
Subtract $ 2x $ from both sides:
$$
-3y = 8 - 2x
$$
Divide both sides by $ -3 $:
$$
y = \frac{2x - 8}{3}
$$
(Note: $ \frac{8 - 2x}{-3} = \frac{2x - 8}{3} $)
✔ Answer: $ y = \frac{2x - 8}{3} $
---
5. $ \frac{x + y}{3} = 5 $ for $ x $
Multiply both sides by 3:
$$
x + y = 15
$$
Subtract $ y $ from both sides:
$$
x = 15 - y
$$
✔ Answer: $ x = 15 - y $
---
6. $ y = mx + b $ for $ b $
We want to solve for $ b $.
Subtract $ mx $ from both sides:
$$
b = y - mx
$$
✔ Answer: $ b = y - mx $
---
7. $ ax + by = c $ for $ y $
We want to solve for $ y $.
Subtract $ ax $ from both sides:
$$
by = c - ax
$$
Divide both sides by $ b $:
$$
y = \frac{c - ax}{b}
$$
✔ Answer: $ y = \frac{c - ax}{b} $
---
8. $ A = \frac{1}{2} h b + c $ for $ b $
We want to solve for $ b $.
First, subtract $ c $ from both sides:
$$
A - c = \frac{1}{2} h b
$$
Now multiply both sides by 2:
$$
2(A - c) = h b
$$
Divide both sides by $ h $:
$$
b = \frac{2(A - c)}{h}
$$
✔ Answer: $ b = \frac{2(A - c)}{h} $
---
9. $ V = LWH $ for $ L $
We want to solve for $ L $.
Divide both sides by $ WH $:
$$
L = \frac{V}{WH}
$$
✔ Answer: $ L = \frac{V}{WH} $
---
10. $ W = 4\pi r $ for $ r $
We want to solve for $ r $.
Divide both sides by $ 4\pi $:
$$
r = \frac{W}{4\pi}
$$
✔ Answer: $ r = \frac{W}{4\pi} $
---
11. $ V = \pi r^2 h $ for $ h $
We want to solve for $ h $.
Divide both sides by $ \pi r^2 $:
$$
h = \frac{V}{\pi r^2}
$$
✔ Answer: $ h = \frac{V}{\pi r^2} $
---
12. $ 7x - y = 14 $ for $ x $
We want to solve for $ x $.
Add $ y $ to both sides:
$$
7x = 14 + y
$$
Divide both sides by 7:
$$
x = \frac{14 + y}{7}
$$
This can also be written as:
$$
x = 2 + \frac{y}{7}
$$
✔ Answer: $ x = \frac{14 + y}{7} $ or $ x = 2 + \frac{y}{7} $
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✔ Final Answers Summary:
1. $ T = \frac{P}{IR} $
2. $ W = A - 2L $
3. $ x = \frac{y + 6}{5} $
4. $ y = \frac{2x - 8}{3} $
5. $ x = 15 - y $
6. $ b = y - mx $
7. $ y = \frac{c - ax}{b} $
8. $ b = \frac{2(A - c)}{h} $
9. $ L = \frac{V}{WH} $
10. $ r = \frac{W}{4\pi} $
11. $ h = \frac{V}{\pi r^2} $
12. $ x = \frac{14 + y}{7} $
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Parent Tip: Review the logic above to help your child master the concept of a ced 1 worksheet.