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Step-by-step solution for: Solving Absolute Value Equations and Inequalities WS | PDF ...
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Step-by-step solution for: Solving Absolute Value Equations and Inequalities WS | PDF ...
Let’s solve each absolute value equation step by step, and check each solution to ensure it satisfies the original equation.
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Step 1: Absolute value equations split into two cases:
> Case 1: x – 6 = 8
> Case 2: x – 6 = –8
Solve Case 1:
x – 6 = 8 → x = 8 + 6 → x = 14
Solve Case 2:
x – 6 = –8 → x = –8 + 6 → x = –2
✔ Solutions: x = 14 or x = –2
Check:
- |14 – 6| = |8| = 8 ✔️
- |–2 – 6| = |–8| = 8 ✔️
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Step 1: The absolute value of any real number is always ≥ 0. It can never be negative.
So |x + 2| = –8 has no solution.
✘ No solution
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Note: |–9x| = |–9|·|x| = 9|x|, so this is equivalent to 9|x| = 64 → |x| = 64/9
But we can also solve directly:
Step 1: Split into two cases:
> Case 1: –9x = 64
> Case 2: –9x = –64
Case 1:
–9x = 64 → x = 64 / (–9) → x = –64/9
Case 2:
–9x = –64 → x = (–64)/(–9) → x = 64/9
✔ Solutions: x = 64/9 or x = –64/9
Check:
- |–9*(64/9)| = |–64| = 64 ✔️
- |–9*(–64/9)| = |64| = 64 ✔️
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Step 1: Split into two cases:
> Case 1: –7x + 4 = 18
> Case 2: –7x + 4 = –18
Case 1:
–7x + 4 = 18
→ –7x = 14
→ x = 14 / (–7) → x = –2
Case 2:
–7x + 4 = –18
→ –7x = –22
→ x = (–22)/(–7) → x = 22/7
✔ Solutions: x = –2 or x = 22/7
Check:
- |–7(–2) + 4| = |14 + 4| = |18| = 18 ✔️
- |–7*(22/7) + 4| = |–22 + 4| = |–18| = 18 ✔️
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Step 1: Split into two cases:
> Case 1: 4x + 4 = 28
> Case 2: 4x + 4 = –28
Case 1:
4x + 4 = 28 → 4x = 24 → x = 6
Case 2:
4x + 4 = –28 → 4x = –32 → x = –8
✔ Solutions: x = 6 or x = –8
Check:
- |4(6) + 4| = |24 + 4| = |28| = 28 ✔️
- |4(–8) + 4| = |–32 + 4| = |–28| = 28 ✔️
---
Step 1: Divide both sides by 5 first:
|n + 10| = 2
Now split into two cases:
> Case 1: n + 10 = 2
> Case 2: n + 10 = –2
Case 1:
n + 10 = 2 → n = –8
Case 2:
n + 10 = –2 → n = –12
✔ Solutions: n = –8 or n = –12
Check:
- 5|–8 + 10| = 5|2| = 5×2 = 10 ✔️
- 5|–12 + 10| = 5|–2| = 5×2 = 10 ✔️
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Step 1: Subtract 3 from both sides:
|–6n| = 43
Since |–6n| = 6|n|, we have 6|n| = 43 → |n| = 43/6
But let’s solve directly:
Split into two cases:
> Case 1: –6n = 43
> Case 2: –6n = –43
Case 1:
–6n = 43 → n = –43/6
Case 2:
–6n = –43 → n = 43/6
✔ Solutions: n = 43/6 or n = –43/6
Check:
- |–6*(43/6)| + 3 = |–43| + 3 = 43 + 3 = 46 ✔️
- |–6*(–43/6)| + 3 = |43| + 3 = 43 + 3 = 46 ✔️
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Step 1: Multiply both sides by 5:
|3v – 2| = 20
Split into two cases:
> Case 1: 3v – 2 = 20
> Case 2: 3v – 2 = –20
Case 1:
3v – 2 = 20 → 3v = 22 → v = 22/3
Case 2:
3v – 2 = –20 → 3v = –18 → v = –6
✔ Solutions: v = 22/3 or v = –6
Check:
- |3*(22/3) – 2| / 5 = |22 – 2| / 5 = |20| / 5 = 20/5 = 4 ✔️
- |3*(–6) – 2| / 5 = |–18 – 2| / 5 = |–20| / 5 = 20/5 = 4 ✔️
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## ✔ Final Answers:
a. x = 14 or x = –2
b. No solution
c. x = 64/9 or x = –64/9
d. x = –2 or x = 22/7
e. x = 6 or x = –8
f. n = –8 or n = –12
g. n = 43/6 or n = –43/6
h. v = 22/3 or v = –6
All solutions checked and verified!
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a. |x – 6| = 8
Step 1: Absolute value equations split into two cases:
> Case 1: x – 6 = 8
> Case 2: x – 6 = –8
Solve Case 1:
x – 6 = 8 → x = 8 + 6 → x = 14
Solve Case 2:
x – 6 = –8 → x = –8 + 6 → x = –2
✔ Solutions: x = 14 or x = –2
Check:
- |14 – 6| = |8| = 8 ✔️
- |–2 – 6| = |–8| = 8 ✔️
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b. |x + 2| = –8
Step 1: The absolute value of any real number is always ≥ 0. It can never be negative.
So |x + 2| = –8 has no solution.
✘ No solution
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c. |–9x| = 64
Note: |–9x| = |–9|·|x| = 9|x|, so this is equivalent to 9|x| = 64 → |x| = 64/9
But we can also solve directly:
Step 1: Split into two cases:
> Case 1: –9x = 64
> Case 2: –9x = –64
Case 1:
–9x = 64 → x = 64 / (–9) → x = –64/9
Case 2:
–9x = –64 → x = (–64)/(–9) → x = 64/9
✔ Solutions: x = 64/9 or x = –64/9
Check:
- |–9*(64/9)| = |–64| = 64 ✔️
- |–9*(–64/9)| = |64| = 64 ✔️
---
d. |–7x + 4| = 18
Step 1: Split into two cases:
> Case 1: –7x + 4 = 18
> Case 2: –7x + 4 = –18
Case 1:
–7x + 4 = 18
→ –7x = 14
→ x = 14 / (–7) → x = –2
Case 2:
–7x + 4 = –18
→ –7x = –22
→ x = (–22)/(–7) → x = 22/7
✔ Solutions: x = –2 or x = 22/7
Check:
- |–7(–2) + 4| = |14 + 4| = |18| = 18 ✔️
- |–7*(22/7) + 4| = |–22 + 4| = |–18| = 18 ✔️
---
e. |4x + 4| = 28
Step 1: Split into two cases:
> Case 1: 4x + 4 = 28
> Case 2: 4x + 4 = –28
Case 1:
4x + 4 = 28 → 4x = 24 → x = 6
Case 2:
4x + 4 = –28 → 4x = –32 → x = –8
✔ Solutions: x = 6 or x = –8
Check:
- |4(6) + 4| = |24 + 4| = |28| = 28 ✔️
- |4(–8) + 4| = |–32 + 4| = |–28| = 28 ✔️
---
f. 5|n + 10| = 10
Step 1: Divide both sides by 5 first:
|n + 10| = 2
Now split into two cases:
> Case 1: n + 10 = 2
> Case 2: n + 10 = –2
Case 1:
n + 10 = 2 → n = –8
Case 2:
n + 10 = –2 → n = –12
✔ Solutions: n = –8 or n = –12
Check:
- 5|–8 + 10| = 5|2| = 5×2 = 10 ✔️
- 5|–12 + 10| = 5|–2| = 5×2 = 10 ✔️
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g. |–6n| + 3 = 46
Step 1: Subtract 3 from both sides:
|–6n| = 43
Since |–6n| = 6|n|, we have 6|n| = 43 → |n| = 43/6
But let’s solve directly:
Split into two cases:
> Case 1: –6n = 43
> Case 2: –6n = –43
Case 1:
–6n = 43 → n = –43/6
Case 2:
–6n = –43 → n = 43/6
✔ Solutions: n = 43/6 or n = –43/6
Check:
- |–6*(43/6)| + 3 = |–43| + 3 = 43 + 3 = 46 ✔️
- |–6*(–43/6)| + 3 = |43| + 3 = 43 + 3 = 46 ✔️
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h. |3v – 2| / 5 = 4
Step 1: Multiply both sides by 5:
|3v – 2| = 20
Split into two cases:
> Case 1: 3v – 2 = 20
> Case 2: 3v – 2 = –20
Case 1:
3v – 2 = 20 → 3v = 22 → v = 22/3
Case 2:
3v – 2 = –20 → 3v = –18 → v = –6
✔ Solutions: v = 22/3 or v = –6
Check:
- |3*(22/3) – 2| / 5 = |22 – 2| / 5 = |20| / 5 = 20/5 = 4 ✔️
- |3*(–6) – 2| / 5 = |–18 – 2| / 5 = |–20| / 5 = 20/5 = 4 ✔️
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## ✔ Final Answers:
a. x = 14 or x = –2
b. No solution
c. x = 64/9 or x = –64/9
d. x = –2 or x = 22/7
e. x = 6 or x = –8
f. n = –8 or n = –12
g. n = 43/6 or n = –43/6
h. v = 22/3 or v = –6
All solutions checked and verified!
Parent Tip: Review the logic above to help your child master the concept of absolute value equations worksheet algebra 2.