Addition Worksheets | Dynamically Created Addition Worksheets - Free Printable
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Step-by-step solution for: Addition Worksheets | Dynamically Created Addition Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Addition Worksheets | Dynamically Created Addition Worksheets
Here are the solutions to the addition problems on the worksheet.
How to solve these:
1. Add the inches first. Add the top number and the bottom number together.
2. Check for wholes. If the inches add up to 12 or more, you need to "carry over" to the feet. Since 12 inches equals 1 foot, subtract 12 from your inches total and add 1 to your feet total.
3. Add the feet. Add the top feet, bottom feet, and any carried-over feet together.
***
Row 1
* Problem 1: $30\text{ ft } 3 \frac{1}{2}\text{ in} + 73\text{ ft } 1 \frac{7}{16}\text{ in}$
* Inches: $\frac{1}{2} = \frac{8}{16}$. So, $\frac{8}{16} + \frac{7}{16} = \frac{15}{16}$.
* Feet: $30 + 73 = 103$.
* Answer: $103\text{ ft } \frac{15}{16}\text{ in}$
* Problem 2: $48\text{ ft } 3 \frac{1}{2}\text{ in} + 86\text{ ft } 4 \frac{1}{2}\text{ in}$
* Inches: $\frac{1}{2} + \frac{1}{2} = 1$. Then $3 + 4 + 1 = 8$ inches.
* Feet: $48 + 86 = 134$.
* Answer: $134\text{ ft } 8\text{ in}$
* Problem 3: $13\text{ ft } 6 \frac{3}{4}\text{ in} + 26\text{ ft } 4 \frac{5}{8}\text{ in}$
* Inches: Convert $\frac{3}{4}$ to $\frac{6}{8}$. Then $\frac{6}{8} + \frac{5}{8} = \frac{11}{8}$. This is $1 \frac{3}{8}$ inches.
* Carry over: Add the 1 inch to the whole inches ($6 + 4 + 1 = 11$). The fraction remains $\frac{3}{8}$. Total inches: $11 \frac{3}{8}$.
* Feet: $13 + 26 = 39$.
* Answer: $39\text{ ft } 11 \frac{3}{8}\text{ in}$
***
Row 2
* Problem 4: $34\text{ ft } 5 \frac{3}{4}\text{ in} + 20\text{ ft } 3 \frac{5}{8}\text{ in}$
* Inches: Convert $\frac{3}{4}$ to $\frac{6}{8}$. Then $\frac{6}{8} + \frac{5}{8} = \frac{11}{8}$. This is $1 \frac{3}{8}$ inches.
* Carry over: Add the 1 inch to the whole inches ($5 + 3 + 1 = 9$). Total inches: $9 \frac{3}{8}$.
* Feet: $34 + 20 = 54$.
* Answer: $54\text{ ft } 9 \frac{3}{8}\text{ in}$
* Problem 5: $51\text{ ft } 10 \frac{3}{4}\text{ in} + 71\text{ ft } 11 \frac{3}{4}\text{ in}$
* Inches: $\frac{3}{4} + \frac{3}{4} = \frac{6}{4} = 1 \frac{2}{4} = 1 \frac{1}{2}$.
* Whole inches: $10 + 11 + 1 (\text{carried}) = 22$ inches.
* Convert to feet: 22 inches is $1\text{ ft } 10\text{ in}$. So we have $10 \frac{1}{2}$ inches remaining and carry 1 foot.
* Feet: $51 + 71 + 1 = 123$.
* Answer: $123\text{ ft } 10 \frac{1}{2}\text{ in}$
* Problem 6: $15\text{ ft } 5 \frac{5}{8}\text{ in} + 17\text{ ft } 9 \frac{3}{8}\text{ in}$
* Inches: $\frac{5}{8} + \frac{3}{8} = \frac{8}{8} = 1$.
* Whole inches: $5 + 9 + 1 = 15$ inches.
* Convert to feet: 15 inches is $1\text{ ft } 3\text{ in}$. Carry the 1 foot.
* Feet: $15 + 17 + 1 = 33$.
* Answer: $33\text{ ft } 3\text{ in}$
***
Row 3
* Problem 7: $36\text{ ft } 9 \frac{3}{4}\text{ in} + 42\text{ ft } 9 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{2}{4}$. Then $\frac{3}{4} + \frac{2}{4} = \frac{5}{4} = 1 \frac{1}{4}$.
* Whole inches: $9 + 9 + 1 = 19$ inches.
* Convert to feet: 19 inches is $1\text{ ft } 7\text{ in}$. Carry the 1 foot.
* Feet: $36 + 42 + 1 = 79$.
* Answer: $79\text{ ft } 7 \frac{1}{4}\text{ in}$
* Problem 8: $28\text{ ft } 11 \frac{1}{8}\text{ in} + 66\text{ ft } 11 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{4}{8}$. Then $\frac{1}{8} + \frac{4}{8} = \frac{5}{8}$.
* Whole inches: $11 + 11 = 22$ inches.
* Convert to feet: 22 inches is $1\text{ ft } 10\text{ in}$. Carry the 1 foot.
* Feet: $28 + 66 + 1 = 95$.
* Answer: $95\text{ ft } 10 \frac{5}{8}\text{ in}$
* Problem 9: $45\text{ ft } 10 \frac{3}{4}\text{ in} + 77\text{ ft } 8 \frac{7}{8}\text{ in}$
* Inches: Convert $\frac{3}{4}$ to $\frac{6}{8}$. Then $\frac{6}{8} + \frac{7}{8} = \frac{13}{8} = 1 \frac{5}{8}$.
* Whole inches: $10 + 8 + 1 = 19$ inches.
* Convert to feet: 19 inches is $1\text{ ft } 7\text{ in}$. Carry the 1 foot.
* Feet: $45 + 77 + 1 = 123$.
* Answer: $123\text{ ft } 7 \frac{5}{8}\text{ in}$
***
Row 4
* Problem 10: $10\text{ ft } 11 \frac{9}{16}\text{ in} + 90\text{ ft } 11 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{8}{16}$. Then $\frac{9}{16} + \frac{8}{16} = \frac{17}{16} = 1 \frac{1}{16}$.
* Whole inches: $11 + 11 + 1 = 23$ inches.
* Convert to feet: 23 inches is $1\text{ ft } 11\text{ in}$. Carry the 1 foot.
* Feet: $10 + 90 + 1 = 101$.
* Answer: $101\text{ ft } 11 \frac{1}{16}\text{ in}$
* Problem 11: $60\text{ ft } 6 \frac{13}{16}\text{ in} + 61\text{ ft } 4 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{8}{16}$. Then $\frac{13}{16} + \frac{8}{16} = \frac{21}{16} = 1 \frac{5}{16}$.
* Whole inches: $6 + 4 + 1 = 11$ inches.
* Feet: $60 + 61 = 121$.
* Answer: $121\text{ ft } 11 \frac{5}{16}\text{ in}$
* Problem 12: $11\text{ ft } 3 \frac{1}{2}\text{ in} + 56\text{ ft } 6 \frac{1}{2}\text{ in}$
* Inches: $\frac{1}{2} + \frac{1}{2} = 1$.
* Whole inches: $3 + 6 + 1 = 10$ inches.
* Feet: $11 + 56 = 67$.
* Answer: $67\text{ ft } 10\text{ in}$
***
Row 5
* Problem 13: $53\text{ ft } 1 \frac{7}{8}\text{ in} + 43\text{ ft } 10 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{4}{8}$. Then $\frac{7}{8} + \frac{4}{8} = \frac{11}{8} = 1 \frac{3}{8}$.
* Whole inches: $1 + 10 + 1 = 12$ inches.
* Convert to feet: 12 inches is exactly $1\text{ ft } 0\text{ in}$. Carry the 1 foot.
* Feet: $53 + 43 + 1 = 97$.
* Answer: $97\text{ ft } \frac{3}{8}\text{ in}$ (or $97\text{ ft } 0 \frac{3}{8}\text{ in}$)
* Problem 14: $87\text{ ft } 10 \frac{13}{16}\text{ in} + 47\text{ ft } 9 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{8}{16}$. Then $\frac{13}{16} + \frac{8}{16} = \frac{21}{16} = 1 \frac{5}{16}$.
* Whole inches: $10 + 9 + 1 = 20$ inches.
* Convert to feet: 20 inches is $1\text{ ft } 8\text{ in}$. Carry the 1 foot.
* Feet: $87 + 47 + 1 = 135$.
* Answer: $135\text{ ft } 8 \frac{5}{16}\text{ in}$
* Problem 15: $68\text{ ft } 8 \frac{1}{16}\text{ in} + 44\text{ ft } 3 \frac{3}{4}\text{ in}$
* Inches: Convert $\frac{3}{4}$ to $\frac{12}{16}$. Then $\frac{1}{16} + \frac{12}{16} = \frac{13}{16}$.
* Whole inches: $8 + 3 = 11$ inches.
* Feet: $68 + 44 = 112$.
* Answer: $112\text{ ft } 11 \frac{13}{16}\text{ in}$
Final Answer:
1. $103\text{ ft } \frac{15}{16}\text{ in}$
2. $134\text{ ft } 8\text{ in}$
3. $39\text{ ft } 11 \frac{3}{8}\text{ in}$
4. $54\text{ ft } 9 \frac{3}{8}\text{ in}$
5. $123\text{ ft } 10 \frac{1}{2}\text{ in}$
6. $33\text{ ft } 3\text{ in}$
7. $79\text{ ft } 7 \frac{1}{4}\text{ in}$
8. $95\text{ ft } 10 \frac{5}{8}\text{ in}$
9. $123\text{ ft } 7 \frac{5}{8}\text{ in}$
10. $101\text{ ft } 11 \frac{1}{16}\text{ in}$
11. $121\text{ ft } 11 \frac{5}{16}\text{ in}$
12. $67\text{ ft } 10\text{ in}$
13. $97\text{ ft } \frac{3}{8}\text{ in}$
14. $135\text{ ft } 8 \frac{5}{16}\text{ in}$
15. $112\text{ ft } 11 \frac{13}{16}\text{ in}$
How to solve these:
1. Add the inches first. Add the top number and the bottom number together.
2. Check for wholes. If the inches add up to 12 or more, you need to "carry over" to the feet. Since 12 inches equals 1 foot, subtract 12 from your inches total and add 1 to your feet total.
3. Add the feet. Add the top feet, bottom feet, and any carried-over feet together.
***
Row 1
* Problem 1: $30\text{ ft } 3 \frac{1}{2}\text{ in} + 73\text{ ft } 1 \frac{7}{16}\text{ in}$
* Inches: $\frac{1}{2} = \frac{8}{16}$. So, $\frac{8}{16} + \frac{7}{16} = \frac{15}{16}$.
* Feet: $30 + 73 = 103$.
* Answer: $103\text{ ft } \frac{15}{16}\text{ in}$
* Problem 2: $48\text{ ft } 3 \frac{1}{2}\text{ in} + 86\text{ ft } 4 \frac{1}{2}\text{ in}$
* Inches: $\frac{1}{2} + \frac{1}{2} = 1$. Then $3 + 4 + 1 = 8$ inches.
* Feet: $48 + 86 = 134$.
* Answer: $134\text{ ft } 8\text{ in}$
* Problem 3: $13\text{ ft } 6 \frac{3}{4}\text{ in} + 26\text{ ft } 4 \frac{5}{8}\text{ in}$
* Inches: Convert $\frac{3}{4}$ to $\frac{6}{8}$. Then $\frac{6}{8} + \frac{5}{8} = \frac{11}{8}$. This is $1 \frac{3}{8}$ inches.
* Carry over: Add the 1 inch to the whole inches ($6 + 4 + 1 = 11$). The fraction remains $\frac{3}{8}$. Total inches: $11 \frac{3}{8}$.
* Feet: $13 + 26 = 39$.
* Answer: $39\text{ ft } 11 \frac{3}{8}\text{ in}$
***
Row 2
* Problem 4: $34\text{ ft } 5 \frac{3}{4}\text{ in} + 20\text{ ft } 3 \frac{5}{8}\text{ in}$
* Inches: Convert $\frac{3}{4}$ to $\frac{6}{8}$. Then $\frac{6}{8} + \frac{5}{8} = \frac{11}{8}$. This is $1 \frac{3}{8}$ inches.
* Carry over: Add the 1 inch to the whole inches ($5 + 3 + 1 = 9$). Total inches: $9 \frac{3}{8}$.
* Feet: $34 + 20 = 54$.
* Answer: $54\text{ ft } 9 \frac{3}{8}\text{ in}$
* Problem 5: $51\text{ ft } 10 \frac{3}{4}\text{ in} + 71\text{ ft } 11 \frac{3}{4}\text{ in}$
* Inches: $\frac{3}{4} + \frac{3}{4} = \frac{6}{4} = 1 \frac{2}{4} = 1 \frac{1}{2}$.
* Whole inches: $10 + 11 + 1 (\text{carried}) = 22$ inches.
* Convert to feet: 22 inches is $1\text{ ft } 10\text{ in}$. So we have $10 \frac{1}{2}$ inches remaining and carry 1 foot.
* Feet: $51 + 71 + 1 = 123$.
* Answer: $123\text{ ft } 10 \frac{1}{2}\text{ in}$
* Problem 6: $15\text{ ft } 5 \frac{5}{8}\text{ in} + 17\text{ ft } 9 \frac{3}{8}\text{ in}$
* Inches: $\frac{5}{8} + \frac{3}{8} = \frac{8}{8} = 1$.
* Whole inches: $5 + 9 + 1 = 15$ inches.
* Convert to feet: 15 inches is $1\text{ ft } 3\text{ in}$. Carry the 1 foot.
* Feet: $15 + 17 + 1 = 33$.
* Answer: $33\text{ ft } 3\text{ in}$
***
Row 3
* Problem 7: $36\text{ ft } 9 \frac{3}{4}\text{ in} + 42\text{ ft } 9 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{2}{4}$. Then $\frac{3}{4} + \frac{2}{4} = \frac{5}{4} = 1 \frac{1}{4}$.
* Whole inches: $9 + 9 + 1 = 19$ inches.
* Convert to feet: 19 inches is $1\text{ ft } 7\text{ in}$. Carry the 1 foot.
* Feet: $36 + 42 + 1 = 79$.
* Answer: $79\text{ ft } 7 \frac{1}{4}\text{ in}$
* Problem 8: $28\text{ ft } 11 \frac{1}{8}\text{ in} + 66\text{ ft } 11 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{4}{8}$. Then $\frac{1}{8} + \frac{4}{8} = \frac{5}{8}$.
* Whole inches: $11 + 11 = 22$ inches.
* Convert to feet: 22 inches is $1\text{ ft } 10\text{ in}$. Carry the 1 foot.
* Feet: $28 + 66 + 1 = 95$.
* Answer: $95\text{ ft } 10 \frac{5}{8}\text{ in}$
* Problem 9: $45\text{ ft } 10 \frac{3}{4}\text{ in} + 77\text{ ft } 8 \frac{7}{8}\text{ in}$
* Inches: Convert $\frac{3}{4}$ to $\frac{6}{8}$. Then $\frac{6}{8} + \frac{7}{8} = \frac{13}{8} = 1 \frac{5}{8}$.
* Whole inches: $10 + 8 + 1 = 19$ inches.
* Convert to feet: 19 inches is $1\text{ ft } 7\text{ in}$. Carry the 1 foot.
* Feet: $45 + 77 + 1 = 123$.
* Answer: $123\text{ ft } 7 \frac{5}{8}\text{ in}$
***
Row 4
* Problem 10: $10\text{ ft } 11 \frac{9}{16}\text{ in} + 90\text{ ft } 11 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{8}{16}$. Then $\frac{9}{16} + \frac{8}{16} = \frac{17}{16} = 1 \frac{1}{16}$.
* Whole inches: $11 + 11 + 1 = 23$ inches.
* Convert to feet: 23 inches is $1\text{ ft } 11\text{ in}$. Carry the 1 foot.
* Feet: $10 + 90 + 1 = 101$.
* Answer: $101\text{ ft } 11 \frac{1}{16}\text{ in}$
* Problem 11: $60\text{ ft } 6 \frac{13}{16}\text{ in} + 61\text{ ft } 4 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{8}{16}$. Then $\frac{13}{16} + \frac{8}{16} = \frac{21}{16} = 1 \frac{5}{16}$.
* Whole inches: $6 + 4 + 1 = 11$ inches.
* Feet: $60 + 61 = 121$.
* Answer: $121\text{ ft } 11 \frac{5}{16}\text{ in}$
* Problem 12: $11\text{ ft } 3 \frac{1}{2}\text{ in} + 56\text{ ft } 6 \frac{1}{2}\text{ in}$
* Inches: $\frac{1}{2} + \frac{1}{2} = 1$.
* Whole inches: $3 + 6 + 1 = 10$ inches.
* Feet: $11 + 56 = 67$.
* Answer: $67\text{ ft } 10\text{ in}$
***
Row 5
* Problem 13: $53\text{ ft } 1 \frac{7}{8}\text{ in} + 43\text{ ft } 10 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{4}{8}$. Then $\frac{7}{8} + \frac{4}{8} = \frac{11}{8} = 1 \frac{3}{8}$.
* Whole inches: $1 + 10 + 1 = 12$ inches.
* Convert to feet: 12 inches is exactly $1\text{ ft } 0\text{ in}$. Carry the 1 foot.
* Feet: $53 + 43 + 1 = 97$.
* Answer: $97\text{ ft } \frac{3}{8}\text{ in}$ (or $97\text{ ft } 0 \frac{3}{8}\text{ in}$)
* Problem 14: $87\text{ ft } 10 \frac{13}{16}\text{ in} + 47\text{ ft } 9 \frac{1}{2}\text{ in}$
* Inches: Convert $\frac{1}{2}$ to $\frac{8}{16}$. Then $\frac{13}{16} + \frac{8}{16} = \frac{21}{16} = 1 \frac{5}{16}$.
* Whole inches: $10 + 9 + 1 = 20$ inches.
* Convert to feet: 20 inches is $1\text{ ft } 8\text{ in}$. Carry the 1 foot.
* Feet: $87 + 47 + 1 = 135$.
* Answer: $135\text{ ft } 8 \frac{5}{16}\text{ in}$
* Problem 15: $68\text{ ft } 8 \frac{1}{16}\text{ in} + 44\text{ ft } 3 \frac{3}{4}\text{ in}$
* Inches: Convert $\frac{3}{4}$ to $\frac{12}{16}$. Then $\frac{1}{16} + \frac{12}{16} = \frac{13}{16}$.
* Whole inches: $8 + 3 = 11$ inches.
* Feet: $68 + 44 = 112$.
* Answer: $112\text{ ft } 11 \frac{13}{16}\text{ in}$
Final Answer:
1. $103\text{ ft } \frac{15}{16}\text{ in}$
2. $134\text{ ft } 8\text{ in}$
3. $39\text{ ft } 11 \frac{3}{8}\text{ in}$
4. $54\text{ ft } 9 \frac{3}{8}\text{ in}$
5. $123\text{ ft } 10 \frac{1}{2}\text{ in}$
6. $33\text{ ft } 3\text{ in}$
7. $79\text{ ft } 7 \frac{1}{4}\text{ in}$
8. $95\text{ ft } 10 \frac{5}{8}\text{ in}$
9. $123\text{ ft } 7 \frac{5}{8}\text{ in}$
10. $101\text{ ft } 11 \frac{1}{16}\text{ in}$
11. $121\text{ ft } 11 \frac{5}{16}\text{ in}$
12. $67\text{ ft } 10\text{ in}$
13. $97\text{ ft } \frac{3}{8}\text{ in}$
14. $135\text{ ft } 8 \frac{5}{16}\text{ in}$
15. $112\text{ ft } 11 \frac{13}{16}\text{ in}$
Parent Tip: Review the logic above to help your child master the concept of add math worksheet.
