Addition and subtraction of algebraic fractions practice problems.
A worksheet titled "Addition and subtraction of algebraic fractions" displaying 20 problems involving addition and subtraction of algebraic fractions with variables in the denominators.
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Step-by-step solution for: Adding and subtracting algebraic fractions - TickTockMaths
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Show Answer Key & Explanations
Step-by-step solution for: Adding and subtracting algebraic fractions - TickTockMaths
Let's solve each of these algebraic fraction problems step by step. The goal is to add or subtract the given algebraic fractions. We'll follow the standard rules:
- If the denominators are the same, simply add or subtract the numerators.
- If the denominators are different, find a common denominator (LCD), rewrite each fraction with that denominator, then combine.
---
Same denominator:
$$
\frac{1 + 4}{a} = \frac{5}{a}
$$
✔ Answer: $\boxed{\frac{5}{a}}$
---
Same denominator:
$$
\frac{7 - 4}{b} = \frac{3}{b}
$$
✔ Answer: $\boxed{\frac{3}{b}}$
---
Same denominator:
$$
\frac{7 + 4}{3c} = \frac{11}{3c}
$$
✔ Answer: $\boxed{\frac{11}{3c}}$
---
Same denominator:
$$
\frac{7 - 4}{3d} = \frac{3}{3d} = \frac{1}{d}
$$
✔ Answer: $\boxed{\frac{1}{d}}$
---
Different denominators: $e$ and $3e$. LCD is $3e$.
Convert $\frac{7}{e} = \frac{7 \cdot 3}{3e} = \frac{21}{3e}$
Now:
$$
\frac{21}{3e} + \frac{4}{3e} = \frac{25}{3e}
$$
✔ Answer: $\boxed{\frac{25}{3e}}$
---
Same denominator:
$$
\frac{7 + 4}{1+f} = \frac{11}{1+f}
$$
✔ Answer: $\boxed{\frac{11}{1+f}}$
---
Same denominator:
$$
\frac{7 + 4}{g+h} = \frac{11}{g+h}
$$
✔ Answer: $\boxed{\frac{11}{g+h}}$
---
Same denominator:
$$
\frac{7 - 4}{g+h} = \frac{3}{g+h}
$$
✔ Answer: $\boxed{\frac{3}{g+h}}$
---
Same denominator:
$$
\frac{7 - 4}{g-h} = \frac{3}{g-h}
$$
✔ Answer: $\boxed{\frac{3}{g-h}}$
---
Same denominator:
$$
\frac{7 - 4}{i^2} = \frac{3}{i^2}
$$
✔ Answer: $\boxed{\frac{3}{i^2}}$
---
Different denominators: 2 and 3 → LCD = 6
$$
\frac{j}{2} = \frac{3j}{6},\quad \frac{j}{3} = \frac{2j}{6}
$$
$$
\frac{3j}{6} + \frac{2j}{6} = \frac{5j}{6}
$$
✔ Answer: $\boxed{\frac{5j}{6}}$
---
LCD of 3 and 5 is 15
$$
\frac{k}{3} = \frac{5k}{15},\quad \frac{k}{5} = \frac{3k}{15}
$$
$$
\frac{5k - 3k}{15} = \frac{2k}{15}
$$
✔ Answer: $\boxed{\frac{2k}{15}}$
---
LCD of 5 and 3 is 15
$$
\frac{l}{5} = \frac{3l}{15},\quad \frac{2l}{3} = \frac{10l}{15}
$$
$$
\frac{3l + 10l}{15} = \frac{13l}{15}
$$
✔ Answer: $\boxed{\frac{13l}{15}}$
---
LCD = 15
$$
\frac{2m}{5} = \frac{6m}{15},\quad \frac{2m}{3} = \frac{10m}{15}
$$
$$
\frac{6m + 10m}{15} = \frac{16m}{15}
$$
✔ Answer: $\boxed{\frac{16m}{15}}$
---
LCD of 7 and 3 is 21
$$
\frac{2p}{7} = \frac{6p}{21},\quad \frac{4p}{3} = \frac{28p}{21}
$$
$$
\frac{6p - 28p}{21} = \frac{-22p}{21}
$$
✔ Answer: $\boxed{-\frac{22p}{21}}$
---
LCD = 6
$$
\frac{q+1}{2} = \frac{3(q+1)}{6} = \frac{3q+3}{6},\quad \frac{2}{3} = \frac{4}{6}
$$
$$
\frac{3q+3 + 4}{6} = \frac{3q + 7}{6}
$$
✔ Answer: $\boxed{\frac{3q + 7}{6}}$
---
LCD = 6
$$
\frac{5}{2} = \frac{15}{6},\quad \frac{2r+2}{3} = \frac{2(2r+2)}{6} = \frac{4r+4}{6}
$$
$$
\frac{15 + 4r + 4}{6} = \frac{4r + 19}{6}
$$
✔ Answer: $\boxed{\frac{4r + 19}{6}}$
---
First simplify: $2(s+2) = 2s + 4$, so:
$$
\frac{5}{2} + \frac{2s+4}{3}
$$
LCD = 6
$$
\frac{5}{2} = \frac{15}{6},\quad \frac{2s+4}{3} = \frac{2(2s+4)}{6} = \frac{4s+8}{6}
$$
$$
\frac{15 + 4s + 8}{6} = \frac{4s + 23}{6}
$$
✔ Answer: $\boxed{\frac{4s + 23}{6}}$
---
LCD = 6
$$
\frac{t+1}{2} = \frac{3(t+1)}{6} = \frac{3t+3}{6},\quad \frac{t+2}{3} = \frac{2(t+2)}{6} = \frac{2t+4}{6}
$$
$$
\frac{3t+3 + 2t+4}{6} = \frac{5t + 7}{6}
$$
✔ Answer: $\boxed{\frac{5t + 7}{6}}$
---
LCD = 6
$$
\frac{v+1}{2} = \frac{3(v+1)}{6} = \frac{3v+3}{6},\quad \frac{v+2}{3} = \frac{2(v+2)}{6} = \frac{2v+4}{6}
$$
$$
\frac{3v+3 - (2v+4)}{6} = \frac{3v+3 - 2v - 4}{6} = \frac{v - 1}{6}
$$
✔ Answer: $\boxed{\frac{v - 1}{6}}$
---
| Problem | Answer |
|--------|--------|
| 1) | $\frac{5}{a}$ |
| 2) | $\frac{3}{b}$ |
| 3) | $\frac{11}{3c}$ |
| 4) | $\frac{1}{d}$ |
| 5) | $\frac{25}{3e}$ |
| 6) | $\frac{11}{1+f}$ |
| 7) | $\frac{11}{g+h}$ |
| 8) | $\frac{3}{g+h}$ |
| 9) | $\frac{3}{g-h}$ |
| 10) | $\frac{3}{i^2}$ |
| 11) | $\frac{5j}{6}$ |
| 12) | $\frac{2k}{15}$ |
| 13) | $\frac{13l}{15}$ |
| 14) | $\frac{16m}{15}$ |
| 15) | $-\frac{22p}{21}$ |
| 16) | $\frac{3q + 7}{6}$ |
| 17) | $\frac{4r + 19}{6}$ |
| 18) | $\frac{4s + 23}{6}$ |
| 19) | $\frac{5t + 7}{6}$ |
| 20) | $\frac{v - 1}{6}$ |
Let me know if you'd like these simplified further or explained in more detail!
- If the denominators are the same, simply add or subtract the numerators.
- If the denominators are different, find a common denominator (LCD), rewrite each fraction with that denominator, then combine.
---
1) $\frac{1}{a} + \frac{4}{a}$
Same denominator:
$$
\frac{1 + 4}{a} = \frac{5}{a}
$$
✔ Answer: $\boxed{\frac{5}{a}}$
---
2) $\frac{7}{b} - \frac{4}{b}$
Same denominator:
$$
\frac{7 - 4}{b} = \frac{3}{b}
$$
✔ Answer: $\boxed{\frac{3}{b}}$
---
3) $\frac{7}{3c} + \frac{4}{3c}$
Same denominator:
$$
\frac{7 + 4}{3c} = \frac{11}{3c}
$$
✔ Answer: $\boxed{\frac{11}{3c}}$
---
4) $\frac{7}{3d} - \frac{4}{3d}$
Same denominator:
$$
\frac{7 - 4}{3d} = \frac{3}{3d} = \frac{1}{d}
$$
✔ Answer: $\boxed{\frac{1}{d}}$
---
5) $\frac{7}{e} + \frac{4}{3e}$
Different denominators: $e$ and $3e$. LCD is $3e$.
Convert $\frac{7}{e} = \frac{7 \cdot 3}{3e} = \frac{21}{3e}$
Now:
$$
\frac{21}{3e} + \frac{4}{3e} = \frac{25}{3e}
$$
✔ Answer: $\boxed{\frac{25}{3e}}$
---
6) $\frac{7}{1+f} + \frac{4}{1+f}$
Same denominator:
$$
\frac{7 + 4}{1+f} = \frac{11}{1+f}
$$
✔ Answer: $\boxed{\frac{11}{1+f}}$
---
7) $\frac{7}{g+h} + \frac{4}{g+h}$
Same denominator:
$$
\frac{7 + 4}{g+h} = \frac{11}{g+h}
$$
✔ Answer: $\boxed{\frac{11}{g+h}}$
---
8) $\frac{7}{g+h} - \frac{4}{g+h}$
Same denominator:
$$
\frac{7 - 4}{g+h} = \frac{3}{g+h}
$$
✔ Answer: $\boxed{\frac{3}{g+h}}$
---
9) $\frac{7}{g-h} - \frac{4}{g-h}$
Same denominator:
$$
\frac{7 - 4}{g-h} = \frac{3}{g-h}
$$
✔ Answer: $\boxed{\frac{3}{g-h}}$
---
10) $\frac{7}{i^2} - \frac{4}{i^2}$
Same denominator:
$$
\frac{7 - 4}{i^2} = \frac{3}{i^2}
$$
✔ Answer: $\boxed{\frac{3}{i^2}}$
---
11) $\frac{j}{2} + \frac{j}{3}$
Different denominators: 2 and 3 → LCD = 6
$$
\frac{j}{2} = \frac{3j}{6},\quad \frac{j}{3} = \frac{2j}{6}
$$
$$
\frac{3j}{6} + \frac{2j}{6} = \frac{5j}{6}
$$
✔ Answer: $\boxed{\frac{5j}{6}}$
---
12) $\frac{k}{3} - \frac{k}{5}$
LCD of 3 and 5 is 15
$$
\frac{k}{3} = \frac{5k}{15},\quad \frac{k}{5} = \frac{3k}{15}
$$
$$
\frac{5k - 3k}{15} = \frac{2k}{15}
$$
✔ Answer: $\boxed{\frac{2k}{15}}$
---
13) $\frac{l}{5} + \frac{2l}{3}$
LCD of 5 and 3 is 15
$$
\frac{l}{5} = \frac{3l}{15},\quad \frac{2l}{3} = \frac{10l}{15}
$$
$$
\frac{3l + 10l}{15} = \frac{13l}{15}
$$
✔ Answer: $\boxed{\frac{13l}{15}}$
---
14) $\frac{2m}{5} + \frac{2m}{3}$
LCD = 15
$$
\frac{2m}{5} = \frac{6m}{15},\quad \frac{2m}{3} = \frac{10m}{15}
$$
$$
\frac{6m + 10m}{15} = \frac{16m}{15}
$$
✔ Answer: $\boxed{\frac{16m}{15}}$
---
15) $\frac{2p}{7} - \frac{4p}{3}$
LCD of 7 and 3 is 21
$$
\frac{2p}{7} = \frac{6p}{21},\quad \frac{4p}{3} = \frac{28p}{21}
$$
$$
\frac{6p - 28p}{21} = \frac{-22p}{21}
$$
✔ Answer: $\boxed{-\frac{22p}{21}}$
---
16) $\frac{q+1}{2} + \frac{2}{3}$
LCD = 6
$$
\frac{q+1}{2} = \frac{3(q+1)}{6} = \frac{3q+3}{6},\quad \frac{2}{3} = \frac{4}{6}
$$
$$
\frac{3q+3 + 4}{6} = \frac{3q + 7}{6}
$$
✔ Answer: $\boxed{\frac{3q + 7}{6}}$
---
17) $\frac{5}{2} + \frac{2r+2}{3}$
LCD = 6
$$
\frac{5}{2} = \frac{15}{6},\quad \frac{2r+2}{3} = \frac{2(2r+2)}{6} = \frac{4r+4}{6}
$$
$$
\frac{15 + 4r + 4}{6} = \frac{4r + 19}{6}
$$
✔ Answer: $\boxed{\frac{4r + 19}{6}}$
---
18) $\frac{5}{2} + \frac{2(s+2)}{3}$
First simplify: $2(s+2) = 2s + 4$, so:
$$
\frac{5}{2} + \frac{2s+4}{3}
$$
LCD = 6
$$
\frac{5}{2} = \frac{15}{6},\quad \frac{2s+4}{3} = \frac{2(2s+4)}{6} = \frac{4s+8}{6}
$$
$$
\frac{15 + 4s + 8}{6} = \frac{4s + 23}{6}
$$
✔ Answer: $\boxed{\frac{4s + 23}{6}}$
---
19) $\frac{t+1}{2} + \frac{t+2}{3}$
LCD = 6
$$
\frac{t+1}{2} = \frac{3(t+1)}{6} = \frac{3t+3}{6},\quad \frac{t+2}{3} = \frac{2(t+2)}{6} = \frac{2t+4}{6}
$$
$$
\frac{3t+3 + 2t+4}{6} = \frac{5t + 7}{6}
$$
✔ Answer: $\boxed{\frac{5t + 7}{6}}$
---
20) $\frac{v+1}{2} - \frac{v+2}{3}$
LCD = 6
$$
\frac{v+1}{2} = \frac{3(v+1)}{6} = \frac{3v+3}{6},\quad \frac{v+2}{3} = \frac{2(v+2)}{6} = \frac{2v+4}{6}
$$
$$
\frac{3v+3 - (2v+4)}{6} = \frac{3v+3 - 2v - 4}{6} = \frac{v - 1}{6}
$$
✔ Answer: $\boxed{\frac{v - 1}{6}}$
---
✔ Final Answers Summary:
| Problem | Answer |
|--------|--------|
| 1) | $\frac{5}{a}$ |
| 2) | $\frac{3}{b}$ |
| 3) | $\frac{11}{3c}$ |
| 4) | $\frac{1}{d}$ |
| 5) | $\frac{25}{3e}$ |
| 6) | $\frac{11}{1+f}$ |
| 7) | $\frac{11}{g+h}$ |
| 8) | $\frac{3}{g+h}$ |
| 9) | $\frac{3}{g-h}$ |
| 10) | $\frac{3}{i^2}$ |
| 11) | $\frac{5j}{6}$ |
| 12) | $\frac{2k}{15}$ |
| 13) | $\frac{13l}{15}$ |
| 14) | $\frac{16m}{15}$ |
| 15) | $-\frac{22p}{21}$ |
| 16) | $\frac{3q + 7}{6}$ |
| 17) | $\frac{4r + 19}{6}$ |
| 18) | $\frac{4s + 23}{6}$ |
| 19) | $\frac{5t + 7}{6}$ |
| 20) | $\frac{v - 1}{6}$ |
Let me know if you'd like these simplified further or explained in more detail!
Parent Tip: Review the logic above to help your child master the concept of adding and subtracting algebraic fractions worksheet.