Math worksheet for adding and subtracting mixed fractions with 12 practice problems.
Worksheet titled "Adding and Subtracting Mixed Fractions (A)" with 12 math problems involving addition and subtraction of mixed fractions, instructions to find values in lowest terms, and source "Math-Drills.com" at the bottom.
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Step-by-step solution for: The Adding and Subtracting Mixed Fractions (A) math worksheet from ...
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Show Answer Key & Explanations
Step-by-step solution for: The Adding and Subtracting Mixed Fractions (A) math worksheet from ...
To solve the problems involving adding and subtracting mixed fractions, we need to follow these steps:
1. Convert mixed fractions to improper fractions.
2. Find a common denominator if necessary.
3. Perform the addition or subtraction.
4. Simplify the result to its lowest terms.
5. Convert back to a mixed fraction if needed.
Let's solve each problem step by step.
---
#### Step 1: Convert to improper fractions
- \( 2\frac{1}{5} = \frac{2 \times 5 + 1}{5} = \frac{11}{5} \)
- \( 1\frac{3}{4} = \frac{1 \times 4 + 3}{4} = \frac{7}{4} \)
#### Step 2: Find a common denominator
The denominators are 5 and 4. The least common denominator (LCD) is 20.
- Convert \( \frac{11}{5} \) to a fraction with denominator 20:
\[
\frac{11}{5} = \frac{11 \times 4}{5 \times 4} = \frac{44}{20}
\]
- Convert \( \frac{7}{4} \) to a fraction with denominator 20:
\[
\frac{7}{4} = \frac{7 \times 5}{4 \times 5} = \frac{35}{20}
\]
#### Step 3: Add the fractions
\[
\frac{44}{20} + \frac{35}{20} = \frac{44 + 35}{20} = \frac{79}{20}
\]
#### Step 4: Convert back to a mixed fraction
\[
\frac{79}{20} = 3 \frac{19}{20}
\]
#### Final Answer:
\[
\boxed{3\frac{19}{20}}
\]
---
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{7}{2} \)
- \( 2\frac{2}{3} = \frac{2 \times 3 + 2}{3} = \frac{8}{3} \)
#### Step 2: Find a common denominator
The denominators are 2 and 3. The least common denominator (LCD) is 6.
- Convert \( \frac{7}{2} \) to a fraction with denominator 6:
\[
\frac{7}{2} = \frac{7 \times 3}{2 \times 3} = \frac{21}{6}
\]
- Convert \( \frac{8}{3} \) to a fraction with denominator 6:
\[
\frac{8}{3} = \frac{8 \times 2}{3 \times 2} = \frac{16}{6}
\]
#### Step 3: Subtract the fractions
\[
\frac{21}{6} - \frac{16}{6} = \frac{21 - 16}{6} = \frac{5}{6}
\]
#### Final Answer:
\[
\boxed{\frac{5}{6}}
\]
---
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{7}{2} \)
#### Step 2: Subtract the fractions
\[
\frac{7}{2} - \frac{7}{2} = \frac{7 - 7}{2} = \frac{0}{2} = 0
\]
#### Final Answer:
\[
\boxed{0}
\]
---
#### Step 1: Convert to improper fractions
- \( 5\frac{3}{4} = \frac{5 \times 4 + 3}{4} = \frac{23}{4} \)
- \( 5\frac{1}{4} = \frac{5 \times 4 + 1}{4} = \frac{21}{4} \)
#### Step 2: Subtract the fractions
\[
\frac{23}{4} - \frac{21}{4} = \frac{23 - 21}{4} = \frac{2}{4} = \frac{1}{2}
\]
#### Final Answer:
\[
\boxed{\frac{1}{2}}
\]
---
#### Step 1: Convert to improper fractions
- \( 1\frac{1}{2} = \frac{1 \times 2 + 1}{2} = \frac{3}{2} \)
- \( 2\frac{3}{5} = \frac{2 \times 5 + 3}{5} = \frac{13}{5} \)
#### Step 2: Find a common denominator
The denominators are 2 and 5. The least common denominator (LCD) is 10.
- Convert \( \frac{3}{2} \) to a fraction with denominator 10:
\[
\frac{3}{2} = \frac{3 \times 5}{2 \times 5} = \frac{15}{10}
\]
- Convert \( \frac{13}{5} \) to a fraction with denominator 10:
\[
\frac{13}{5} = \frac{13 \times 2}{5 \times 2} = \frac{26}{10}
\]
#### Step 3: Add the fractions
\[
\frac{15}{10} + \frac{26}{10} = \frac{15 + 26}{10} = \frac{41}{10}
\]
#### Step 4: Convert back to a mixed fraction
\[
\frac{41}{10} = 4 \frac{1}{10}
\]
#### Final Answer:
\[
\boxed{4\frac{1}{10}}
\]
---
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{7}{2} \)
- \( 2\frac{5}{9} = \frac{2 \times 9 + 5}{9} = \frac{23}{9} \)
#### Step 2: Find a common denominator
The denominators are 2 and 9. The least common denominator (LCD) is 18.
- Convert \( \frac{7}{2} \) to a fraction with denominator 18:
\[
\frac{7}{2} = \frac{7 \times 9}{2 \times 9} = \frac{63}{18}
\]
- Convert \( \frac{23}{9} \) to a fraction with denominator 18:
\[
\frac{23}{9} = \frac{23 \times 2}{9 \times 2} = \frac{46}{18}
\]
#### Step 3: Subtract the fractions
\[
\frac{63}{18} - \frac{46}{18} = \frac{63 - 46}{18} = \frac{17}{18}
\]
#### Final Answer:
\[
\boxed{\frac{17}{18}}
\]
---
#### Step 1: Convert to improper fractions
- \( 2\frac{3}{4} = \frac{2 \times 4 + 3}{4} = \frac{11}{4} \)
- \( 1\frac{1}{5} = \frac{1 \times 5 + 1}{5} = \frac{6}{5} \)
#### Step 2: Find a common denominator
The denominators are 4 and 5. The least common denominator (LCD) is 20.
- Convert \( \frac{11}{4} \) to a fraction with denominator 20:
\[
\frac{11}{4} = \frac{11 \times 5}{4 \times 5} = \frac{55}{20}
\]
- Convert \( \frac{6}{5} \) to a fraction with denominator 20:
\[
\frac{6}{5} = \frac{6 \times 4}{5 \times 4} = \frac{24}{20}
\]
#### Step 3: Add the fractions
\[
\frac{55}{20} + \frac{24}{20} = \frac{55 + 24}{20} = \frac{79}{20}
\]
#### Step 4: Convert back to a mixed fraction
\[
\frac{79}{20} = 3 \frac{19}{20}
\]
#### Final Answer:
\[
\boxed{3\frac{19}{20}}
\]
---
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{4} = \frac{3 \times 4 + 1}{4} = \frac{13}{4} \)
- \( 2\frac{3}{8} = \frac{2 \times 8 + 3}{8} = \frac{19}{8} \)
#### Step 2: Find a common denominator
The denominators are 4 and 8. The least common denominator (LCD) is 8.
- Convert \( \frac{13}{4} \) to a fraction with denominator 8:
\[
\frac{13}{4} = \frac{13 \times 2}{4 \times 2} = \frac{26}{8}
\]
- \( \frac{19}{8} \) already has denominator 8.
#### Step 3: Subtract the fractions
\[
\frac{26}{8} - \frac{19}{8} = \frac{26 - 19}{8} = \frac{7}{8}
\]
#### Final Answer:
\[
\boxed{\frac{7}{8}}
\]
---
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{7}{2} \)
- \( 1\frac{1}{2} = \frac{1 \times 2 + 1}{2} = \frac{3}{2} \)
#### Step 2: Subtract the fractions
\[
\frac{7}{2} - \frac{3}{2} = \frac{7 - 3}{2} = \frac{4}{2} = 2
\]
#### Final Answer:
\[
\boxed{2}
\]
---
#### Step 1: Convert to improper fractions
- \( 5\frac{1}{2} = \frac{5 \times 2 + 1}{2} = \frac{11}{2} \)
- \( 5\frac{1}{4} = \frac{5 \times 4 + 1}{4} = \frac{21}{4} \)
#### Step 2: Find a common denominator
The denominators are 2 and 4. The least common denominator (LCD) is 4.
- Convert \( \frac{11}{2} \) to a fraction with denominator 4:
\[
\frac{11}{2} = \frac{11 \times 2}{2 \times 2} = \frac{22}{4}
\]
- \( \frac{21}{4} \) already has denominator 4.
#### Step 3: Add the fractions
\[
\frac{22}{4} + \frac{21}{4} = \frac{22 + 21}{4} = \frac{43}{4}
\]
#### Step 4: Convert back to a mixed fraction
\[
\frac{43}{4} = 10 \frac{3}{4}
\]
#### Final Answer:
\[
\boxed{10\frac{3}{4}}
\]
---
#### Step 1: Convert to improper fractions
- \( 1\frac{10}{11} = \frac{1 \times 11 + 10}{11} = \frac{21}{11} \)
- \( 1\frac{1}{3} = \frac{1 \times 3 + 1}{3} = \frac{4}{3} \)
#### Step 2: Find a common denominator
The denominators are 11 and 3. The least common denominator (LCD) is 33.
- Convert \( \frac{21}{11} \) to a fraction with denominator 33:
\[
\frac{21}{11} = \frac{21 \times 3}{11 \times 3} = \frac{63}{33}
\]
- Convert \( \frac{4}{3} \) to a fraction with denominator 33:
\[
\frac{4}{3} = \frac{4 \times 11}{3 \times 11} = \frac{44}{33}
\]
#### Step 3: Subtract the fractions
\[
\frac{63}{33} - \frac{44}{33} = \frac{63 - 44}{33} = \frac{19}{33}
\]
#### Final Answer:
\[
\boxed{\frac{19}{33}}
\]
---
#### Step 1: Convert to improper fractions
- \( 1\frac{5}{12} = \frac{1 \times 12 + 5}{12} = \frac{17}{12} \)
- \( 3\frac{1}{3} = \frac{3 \times 3 + 1}{3} = \frac{10}{3} \)
#### Step 2: Find a common denominator
The denominators are 12 and 3. The least common denominator (LCD) is 12.
- \( \frac{17}{12} \) already has denominator 12.
- Convert \( \frac{10}{3} \) to a fraction with denominator 12:
\[
\frac{10}{3} = \frac{10 \times 4}{3 \times 4} = \frac{40}{12}
\]
#### Step 3: Add the fractions
\[
\frac{17}{12} + \frac{40}{12} = \frac{17 + 40}{12} = \frac{57}{12}
\]
#### Step 4: Simplify the fraction
\[
\frac{57}{12} = \frac{19}{4}
\]
#### Step 5: Convert back to a mixed fraction
\[
\frac{19}{4} = 4 \frac{3}{4}
\]
#### Final Answer:
\[
\boxed{4\frac{3}{4}}
\]
---
1. \( \boxed{3\frac{19}{20}} \)
2. \( \boxed{\frac{5}{6}} \)
3. \( \boxed{0} \)
4. \( \boxed{\frac{1}{2}} \)
5. \( \boxed{4\frac{1}{10}} \)
6. \( \boxed{\frac{17}{18}} \)
7. \( \boxed{3\frac{19}{20}} \)
8. \( \boxed{\frac{7}{8}} \)
9. \( \boxed{2} \)
10. \( \boxed{10\frac{3}{4}} \)
11. \( \boxed{\frac{19}{33}} \)
12. \( \boxed{4\frac{3}{4}} \)
1. Convert mixed fractions to improper fractions.
2. Find a common denominator if necessary.
3. Perform the addition or subtraction.
4. Simplify the result to its lowest terms.
5. Convert back to a mixed fraction if needed.
Let's solve each problem step by step.
---
Problem 1: \( 2\frac{1}{5} + 1\frac{3}{4} \)
#### Step 1: Convert to improper fractions
- \( 2\frac{1}{5} = \frac{2 \times 5 + 1}{5} = \frac{11}{5} \)
- \( 1\frac{3}{4} = \frac{1 \times 4 + 3}{4} = \frac{7}{4} \)
#### Step 2: Find a common denominator
The denominators are 5 and 4. The least common denominator (LCD) is 20.
- Convert \( \frac{11}{5} \) to a fraction with denominator 20:
\[
\frac{11}{5} = \frac{11 \times 4}{5 \times 4} = \frac{44}{20}
\]
- Convert \( \frac{7}{4} \) to a fraction with denominator 20:
\[
\frac{7}{4} = \frac{7 \times 5}{4 \times 5} = \frac{35}{20}
\]
#### Step 3: Add the fractions
\[
\frac{44}{20} + \frac{35}{20} = \frac{44 + 35}{20} = \frac{79}{20}
\]
#### Step 4: Convert back to a mixed fraction
\[
\frac{79}{20} = 3 \frac{19}{20}
\]
#### Final Answer:
\[
\boxed{3\frac{19}{20}}
\]
---
Problem 2: \( 3\frac{1}{2} - 2\frac{2}{3} \)
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{7}{2} \)
- \( 2\frac{2}{3} = \frac{2 \times 3 + 2}{3} = \frac{8}{3} \)
#### Step 2: Find a common denominator
The denominators are 2 and 3. The least common denominator (LCD) is 6.
- Convert \( \frac{7}{2} \) to a fraction with denominator 6:
\[
\frac{7}{2} = \frac{7 \times 3}{2 \times 3} = \frac{21}{6}
\]
- Convert \( \frac{8}{3} \) to a fraction with denominator 6:
\[
\frac{8}{3} = \frac{8 \times 2}{3 \times 2} = \frac{16}{6}
\]
#### Step 3: Subtract the fractions
\[
\frac{21}{6} - \frac{16}{6} = \frac{21 - 16}{6} = \frac{5}{6}
\]
#### Final Answer:
\[
\boxed{\frac{5}{6}}
\]
---
Problem 3: \( 3\frac{1}{2} - 3\frac{1}{2} \)
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{7}{2} \)
#### Step 2: Subtract the fractions
\[
\frac{7}{2} - \frac{7}{2} = \frac{7 - 7}{2} = \frac{0}{2} = 0
\]
#### Final Answer:
\[
\boxed{0}
\]
---
Problem 4: \( 5\frac{3}{4} - 5\frac{1}{4} \)
#### Step 1: Convert to improper fractions
- \( 5\frac{3}{4} = \frac{5 \times 4 + 3}{4} = \frac{23}{4} \)
- \( 5\frac{1}{4} = \frac{5 \times 4 + 1}{4} = \frac{21}{4} \)
#### Step 2: Subtract the fractions
\[
\frac{23}{4} - \frac{21}{4} = \frac{23 - 21}{4} = \frac{2}{4} = \frac{1}{2}
\]
#### Final Answer:
\[
\boxed{\frac{1}{2}}
\]
---
Problem 5: \( 1\frac{1}{2} + 2\frac{3}{5} \)
#### Step 1: Convert to improper fractions
- \( 1\frac{1}{2} = \frac{1 \times 2 + 1}{2} = \frac{3}{2} \)
- \( 2\frac{3}{5} = \frac{2 \times 5 + 3}{5} = \frac{13}{5} \)
#### Step 2: Find a common denominator
The denominators are 2 and 5. The least common denominator (LCD) is 10.
- Convert \( \frac{3}{2} \) to a fraction with denominator 10:
\[
\frac{3}{2} = \frac{3 \times 5}{2 \times 5} = \frac{15}{10}
\]
- Convert \( \frac{13}{5} \) to a fraction with denominator 10:
\[
\frac{13}{5} = \frac{13 \times 2}{5 \times 2} = \frac{26}{10}
\]
#### Step 3: Add the fractions
\[
\frac{15}{10} + \frac{26}{10} = \frac{15 + 26}{10} = \frac{41}{10}
\]
#### Step 4: Convert back to a mixed fraction
\[
\frac{41}{10} = 4 \frac{1}{10}
\]
#### Final Answer:
\[
\boxed{4\frac{1}{10}}
\]
---
Problem 6: \( 3\frac{1}{2} - 2\frac{5}{9} \)
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{7}{2} \)
- \( 2\frac{5}{9} = \frac{2 \times 9 + 5}{9} = \frac{23}{9} \)
#### Step 2: Find a common denominator
The denominators are 2 and 9. The least common denominator (LCD) is 18.
- Convert \( \frac{7}{2} \) to a fraction with denominator 18:
\[
\frac{7}{2} = \frac{7 \times 9}{2 \times 9} = \frac{63}{18}
\]
- Convert \( \frac{23}{9} \) to a fraction with denominator 18:
\[
\frac{23}{9} = \frac{23 \times 2}{9 \times 2} = \frac{46}{18}
\]
#### Step 3: Subtract the fractions
\[
\frac{63}{18} - \frac{46}{18} = \frac{63 - 46}{18} = \frac{17}{18}
\]
#### Final Answer:
\[
\boxed{\frac{17}{18}}
\]
---
Problem 7: \( 2\frac{3}{4} + 1\frac{1}{5} \)
#### Step 1: Convert to improper fractions
- \( 2\frac{3}{4} = \frac{2 \times 4 + 3}{4} = \frac{11}{4} \)
- \( 1\frac{1}{5} = \frac{1 \times 5 + 1}{5} = \frac{6}{5} \)
#### Step 2: Find a common denominator
The denominators are 4 and 5. The least common denominator (LCD) is 20.
- Convert \( \frac{11}{4} \) to a fraction with denominator 20:
\[
\frac{11}{4} = \frac{11 \times 5}{4 \times 5} = \frac{55}{20}
\]
- Convert \( \frac{6}{5} \) to a fraction with denominator 20:
\[
\frac{6}{5} = \frac{6 \times 4}{5 \times 4} = \frac{24}{20}
\]
#### Step 3: Add the fractions
\[
\frac{55}{20} + \frac{24}{20} = \frac{55 + 24}{20} = \frac{79}{20}
\]
#### Step 4: Convert back to a mixed fraction
\[
\frac{79}{20} = 3 \frac{19}{20}
\]
#### Final Answer:
\[
\boxed{3\frac{19}{20}}
\]
---
Problem 8: \( 3\frac{1}{4} - 2\frac{3}{8} \)
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{4} = \frac{3 \times 4 + 1}{4} = \frac{13}{4} \)
- \( 2\frac{3}{8} = \frac{2 \times 8 + 3}{8} = \frac{19}{8} \)
#### Step 2: Find a common denominator
The denominators are 4 and 8. The least common denominator (LCD) is 8.
- Convert \( \frac{13}{4} \) to a fraction with denominator 8:
\[
\frac{13}{4} = \frac{13 \times 2}{4 \times 2} = \frac{26}{8}
\]
- \( \frac{19}{8} \) already has denominator 8.
#### Step 3: Subtract the fractions
\[
\frac{26}{8} - \frac{19}{8} = \frac{26 - 19}{8} = \frac{7}{8}
\]
#### Final Answer:
\[
\boxed{\frac{7}{8}}
\]
---
Problem 9: \( 3\frac{1}{2} - 1\frac{1}{2} \)
#### Step 1: Convert to improper fractions
- \( 3\frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{7}{2} \)
- \( 1\frac{1}{2} = \frac{1 \times 2 + 1}{2} = \frac{3}{2} \)
#### Step 2: Subtract the fractions
\[
\frac{7}{2} - \frac{3}{2} = \frac{7 - 3}{2} = \frac{4}{2} = 2
\]
#### Final Answer:
\[
\boxed{2}
\]
---
Problem 10: \( 5\frac{1}{2} + 5\frac{1}{4} \)
#### Step 1: Convert to improper fractions
- \( 5\frac{1}{2} = \frac{5 \times 2 + 1}{2} = \frac{11}{2} \)
- \( 5\frac{1}{4} = \frac{5 \times 4 + 1}{4} = \frac{21}{4} \)
#### Step 2: Find a common denominator
The denominators are 2 and 4. The least common denominator (LCD) is 4.
- Convert \( \frac{11}{2} \) to a fraction with denominator 4:
\[
\frac{11}{2} = \frac{11 \times 2}{2 \times 2} = \frac{22}{4}
\]
- \( \frac{21}{4} \) already has denominator 4.
#### Step 3: Add the fractions
\[
\frac{22}{4} + \frac{21}{4} = \frac{22 + 21}{4} = \frac{43}{4}
\]
#### Step 4: Convert back to a mixed fraction
\[
\frac{43}{4} = 10 \frac{3}{4}
\]
#### Final Answer:
\[
\boxed{10\frac{3}{4}}
\]
---
Problem 11: \( 1\frac{10}{11} - 1\frac{1}{3} \)
#### Step 1: Convert to improper fractions
- \( 1\frac{10}{11} = \frac{1 \times 11 + 10}{11} = \frac{21}{11} \)
- \( 1\frac{1}{3} = \frac{1 \times 3 + 1}{3} = \frac{4}{3} \)
#### Step 2: Find a common denominator
The denominators are 11 and 3. The least common denominator (LCD) is 33.
- Convert \( \frac{21}{11} \) to a fraction with denominator 33:
\[
\frac{21}{11} = \frac{21 \times 3}{11 \times 3} = \frac{63}{33}
\]
- Convert \( \frac{4}{3} \) to a fraction with denominator 33:
\[
\frac{4}{3} = \frac{4 \times 11}{3 \times 11} = \frac{44}{33}
\]
#### Step 3: Subtract the fractions
\[
\frac{63}{33} - \frac{44}{33} = \frac{63 - 44}{33} = \frac{19}{33}
\]
#### Final Answer:
\[
\boxed{\frac{19}{33}}
\]
---
Problem 12: \( 1\frac{5}{12} + 3\frac{1}{3} \)
#### Step 1: Convert to improper fractions
- \( 1\frac{5}{12} = \frac{1 \times 12 + 5}{12} = \frac{17}{12} \)
- \( 3\frac{1}{3} = \frac{3 \times 3 + 1}{3} = \frac{10}{3} \)
#### Step 2: Find a common denominator
The denominators are 12 and 3. The least common denominator (LCD) is 12.
- \( \frac{17}{12} \) already has denominator 12.
- Convert \( \frac{10}{3} \) to a fraction with denominator 12:
\[
\frac{10}{3} = \frac{10 \times 4}{3 \times 4} = \frac{40}{12}
\]
#### Step 3: Add the fractions
\[
\frac{17}{12} + \frac{40}{12} = \frac{17 + 40}{12} = \frac{57}{12}
\]
#### Step 4: Simplify the fraction
\[
\frac{57}{12} = \frac{19}{4}
\]
#### Step 5: Convert back to a mixed fraction
\[
\frac{19}{4} = 4 \frac{3}{4}
\]
#### Final Answer:
\[
\boxed{4\frac{3}{4}}
\]
---
Final Answers:
1. \( \boxed{3\frac{19}{20}} \)
2. \( \boxed{\frac{5}{6}} \)
3. \( \boxed{0} \)
4. \( \boxed{\frac{1}{2}} \)
5. \( \boxed{4\frac{1}{10}} \)
6. \( \boxed{\frac{17}{18}} \)
7. \( \boxed{3\frac{19}{20}} \)
8. \( \boxed{\frac{7}{8}} \)
9. \( \boxed{2} \)
10. \( \boxed{10\frac{3}{4}} \)
11. \( \boxed{\frac{19}{33}} \)
12. \( \boxed{4\frac{3}{4}} \)
Parent Tip: Review the logic above to help your child master the concept of adding and subtracting fractions and mixed numbers worksheet.