Math worksheet for practicing adding and subtracting fractions, featuring 20 problems and an answer column.

Let's solve each of these fraction addition and subtraction problems step by step. All the problems involve like denominators (same denominators), so we can simply add or subtract the numerators while keeping the denominator the same.

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1) $ \frac{1}{2} - \frac{1}{2} $

- Numerator: $ 1 - 1 = 0 $
- Denominator: 2
- Answer: $ \frac{0}{2} = 0 $

✔ Answer: 0

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2) $ \frac{5}{6} + \frac{5}{6} $

- Numerator: $ 5 + 5 = 10 $
- Denominator: 6
- $ \frac{10}{6} $ → Simplify: divide numerator and denominator by 2 → $ \frac{5}{3} $
- $ \frac{5}{3} = 1\frac{2}{3} $

✔ Answer: $ \frac{5}{3} $ or $ 1\frac{2}{3} $

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3) $ \frac{4}{8} - \frac{1}{8} $

- Numerator: $ 4 - 1 = 3 $
- Denominator: 8
- $ \frac{3}{8} $

✔ Answer: $ \frac{3}{8} $

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4) $ \frac{7}{10} + \frac{6}{10} $

- Numerator: $ 7 + 6 = 13 $
- Denominator: 10
- $ \frac{13}{10} = 1\frac{3}{10} $

✔ Answer: $ \frac{13}{10} $ or $ 1\frac{3}{10} $

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5) $ \frac{2}{4} - \frac{1}{4} $

- Numerator: $ 2 - 1 = 1 $
- Denominator: 4
- $ \frac{1}{4} $

✔ Answer: $ \frac{1}{4} $

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6) $ \frac{3}{5} + \frac{2}{5} $

- Numerator: $ 3 + 2 = 5 $
- Denominator: 5
- $ \frac{5}{5} = 1 $

✔ Answer: 1

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7) $ \frac{3}{8} - \frac{3}{8} $

- Numerator: $ 3 - 3 = 0 $
- Denominator: 8
- $ \frac{0}{8} = 0 $

✔ Answer: 0

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8) $ \frac{4}{5} + \frac{3}{5} $

- Numerator: $ 4 + 3 = 7 $
- Denominator: 5
- $ \frac{7}{5} = 1\frac{2}{5} $

✔ Answer: $ \frac{7}{5} $ or $ 1\frac{2}{5} $

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9) $ \frac{3}{6} - \frac{1}{6} $

- Numerator: $ 3 - 1 = 2 $
- Denominator: 6
- $ \frac{2}{6} = \frac{1}{3} $ (simplify by dividing by 2)

✔ Answer: $ \frac{1}{3} $

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10) $ \frac{1}{3} + \frac{1}{3} $

- Numerator: $ 1 + 1 = 2 $
- Denominator: 3
- $ \frac{2}{3} $

✔ Answer: $ \frac{2}{3} $

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11) $ \frac{6}{8} - \frac{6}{8} $

- Numerator: $ 6 - 6 = 0 $
- Denominator: 8
- $ \frac{0}{8} = 0 $

✔ Answer: 0

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12) $ \frac{2}{6} + \frac{2}{6} $

- Numerator: $ 2 + 2 = 4 $
- Denominator: 6
- $ \frac{4}{6} = \frac{2}{3} $ (simplify by dividing by 2)

✔ Answer: $ \frac{2}{3} $

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13) $ \frac{3}{5} - \frac{3}{5} $

- Numerator: $ 3 - 3 = 0 $
- Denominator: 5
- $ \frac{0}{5} = 0 $

✔ Answer: 0

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14) $ \frac{8}{12} + \frac{8}{12} $

- Numerator: $ 8 + 8 = 16 $
- Denominator: 12
- $ \frac{16}{12} = \frac{4}{3} $ (divide numerator and denominator by 4)
- $ \frac{4}{3} = 1\frac{1}{3} $

✔ Answer: $ \frac{4}{3} $ or $ 1\frac{1}{3} $

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15) $ \frac{2}{3} - \frac{1}{3} $

- Numerator: $ 2 - 1 = 1 $
- Denominator: 3
- $ \frac{1}{3} $

✔ Answer: $ \frac{1}{3} $

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16) $ \frac{1}{4} + \frac{1}{4} $

- Numerator: $ 1 + 1 = 2 $
- Denominator: 4
- $ \frac{2}{4} = \frac{1}{2} $

✔ Answer: $ \frac{1}{2} $

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17) $ \frac{8}{10} - \frac{3}{10} $

- Numerator: $ 8 - 3 = 5 $
- Denominator: 10
- $ \frac{5}{10} = \frac{1}{2} $

✔ Answer: $ \frac{1}{2} $

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18) $ \frac{5}{12} + \frac{4}{12} $

- Numerator: $ 5 + 4 = 9 $
- Denominator: 12
- $ \frac{9}{12} = \frac{3}{4} $ (simplify by dividing by 3)

✔ Answer: $ \frac{3}{4} $

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19) $ \frac{3}{5} - \frac{2}{5} $

- Numerator: $ 3 - 2 = 1 $
- Denominator: 5
- $ \frac{1}{5} $

✔ Answer: $ \frac{1}{5} $

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20) $ \frac{5}{6} + \frac{1}{6} $

- Numerator: $ 5 + 1 = 6 $
- Denominator: 6
- $ \frac{6}{6} = 1 $

✔ Answer: 1

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✔ Final Answers:

| Problem | Answer |
|--------|--------|
| 1 | 0 |
| 2 | $ \frac{5}{3} $ or $ 1\frac{2}{3} $ |
| 3 | $ \frac{3}{8} $ |
| 4 | $ \frac{13}{10} $ or $ 1\frac{3}{10} $ |
| 5 | $ \frac{1}{4} $ |
| 6 | 1 |
| 7 | 0 |
| 8 | $ \frac{7}{5} $ or $ 1\frac{2}{5} $ |
| 9 | $ \frac{1}{3} $ |
| 10 | $ \frac{2}{3} $ |
| 11 | 0 |
| 12 | $ \frac{2}{3} $ |
| 13 | 0 |
| 14 | $ \frac{4}{3} $ or $ 1\frac{1}{3} $ |
| 15 | $ \frac{1}{3} $ |
| 16 | $ \frac{1}{2} $ |
| 17 | $ \frac{1}{2} $ |
| 18 | $ \frac{3}{4} $ |
| 19 | $ \frac{1}{5} $ |
| 20 | 1 |

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💡 Tips for solving such problems:
- Always check if the denominators are the same.
- If yes, just add/subtract the numerators.
- Simplify the result if possible.
- Convert improper fractions to mixed numbers if needed.

Let me know if you'd like a printable version or help with any specific problem!