Adding fractions: bar models - Fraction Worksheets for Year 3 (age ... - Free Printable

Let’s go through each problem one by one. We’re adding fractions that have the same denominator (bottom number), so we just add the top numbers and keep the bottom number the same.

---

Problem 1:
Bar model shows 2 blue + 1 yellow = 3 shaded out of 5 total parts.
So:
$\frac{2}{5} + \frac{1}{5} = \frac{3}{5}$

✔ Answer: $\frac{3}{5}$

---

Problem 2:
Bar model: 2 blue + 2 yellow = 4 shaded out of 5 total parts.
So:
$\frac{2}{5} + \frac{2}{5} = \frac{4}{5}$

✔ Answer: $\frac{4}{5}$

---

Problem 3:
Bar model: 2 blue + 1 yellow = 3 shaded out of 6 total parts.
So:
$\frac{2}{6} + \frac{1}{6} = \frac{3}{6}$
We can simplify $\frac{3}{6}$ to $\frac{1}{2}$, but since the worksheet doesn’t ask for simplifying, we’ll leave it as $\frac{3}{6}$ unless told otherwise. But looking at other problems, they don’t simplify — so we’ll keep it as is.

Wait — actually, let’s check the bar: it’s divided into 6 equal parts. Blue covers 2, yellow covers 1 → total 3 shaded. So yes, $\frac{3}{6}$.

But in some curricula, they might expect simplified form. However, since the worksheet has blanks with denominators already filled (like 6), and no instruction to simplify, we’ll write $\frac{3}{6}$.

Actually, looking ahead — Problem 7 has denominator 9, and answer will be over 9 — so likely no simplification needed.

✔ Answer: $\frac{3}{6}$

---

Problem 4:
Bar model: 3 blue + 2 yellow = 5 shaded out of 6 total parts? Wait — let’s count.

The bar is split into 6 parts? Let me recount from image description:

Actually, looking at problem 4: bar has 6 sections? No — wait, the bar in problem 4: blue takes 3, yellow takes 2, and there’s 1 white → total 6 parts? Yes.

So:
$\frac{3}{6} + \frac{2}{6} = \frac{5}{6}$

✔ Answer: $\frac{5}{6}$

---

Problem 5:
Bar model: 1 blue + 4 yellow = 5 shaded out of 8 total parts.
So:
$\frac{1}{8} + \frac{4}{8} = \frac{5}{8}$

✔ Answer: $\frac{5}{8}$

---

Problem 6:
Bar model: 3 blue + 4 yellow = 7 shaded out of 8 total parts? Let’s see: bar has 8 sections? Blue=3, yellow=4, white=1 → yes, 8 total.

So:
$\frac{3}{8} + \frac{4}{8} = \frac{7}{8}$

✔ Answer: $\frac{7}{8}$

---

Problem 7:
Bar model: 4 blue + 5 yellow = 9 shaded out of 9 total parts? Bar has 9 sections? Blue=4, yellow=5 → total 9 shaded, no white → so all 9 are shaded.

So:
$\frac{4}{9} + \frac{5}{9} = \frac{9}{9} = 1$

But again, since denominator is given as 9 in the blank, we write $\frac{9}{9}$

✔ Answer: $\frac{9}{9}$

---

Problem 8:
Bar model: 2 blue + 5 yellow = 7 shaded out of 9 total parts? Let’s count: bar has 9 sections? Blue=2, yellow=5, white=2 → total 9.

So:
$\frac{2}{9} + \frac{5}{9} = \frac{7}{9}$

✔ Answer: $\frac{7}{9}$

---

Problem 9:
Bar model: 4 blue + 3 yellow = 7 shaded out of 9 total parts? Bar has 9 sections: blue=4, yellow=3, white=2 → yes.

So:
$\frac{4}{9} + \frac{3}{9} = \frac{7}{9}$

✔ Answer: $\frac{7}{9}$

---

Problem 10:
Bar model: 3 blue + 6 yellow = 9 shaded out of 10 total parts? Bar has 10 sections: blue=3, yellow=6, white=1 → total 10.

So:
$\frac{3}{10} + \frac{6}{10} = \frac{9}{10}$

✔ Answer: $\frac{9}{10}$

---

Now, let’s compile all answers clearly.

Final Answer:
1. $\frac{3}{5}$
2. $\frac{4}{5}$
3. $\frac{3}{6}$
4. $\frac{5}{6}$
5. $\frac{5}{8}$
6. $\frac{7}{8}$
7. $\frac{9}{9}$
8. $\frac{7}{9}$
9. $\frac{7}{9}$
10. $\frac{9}{10}$