Add & Subtract Fractions Word Problems | Worsheets library - Free Printable

Problem Analysis:

The worksheet contains three fraction word problems related to preparing ingredients for a pasta dish. Let's solve each problem step by step.

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Problem 1:

Question: Arya prepared $\frac{5}{12}$ cup of chopped garlic, and Yana prepared $\frac{6}{12}$ cup. How much garlic did they prepare in total?

#### Solution:
To find the total amount of garlic, we need to add the fractions $\frac{5}{12}$ and $\frac{6}{12}$. Since the denominators are the same, we can directly add the numerators:

\[
\frac{5}{12} + \frac{6}{12} = \frac{5 + 6}{12} = \frac{11}{12}
\]

Thus, the total amount of garlic prepared is:

\[
\boxed{\frac{11}{12}}
\]

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Problem 2:

Question: The two girls needed $1 \frac{3}{4}$ cups of onions. If their mom already prepared $1 \frac{1}{2}$ cups, how much more onion do they need to prepare?

#### Solution:
First, convert the mixed numbers to improper fractions:
- $1 \frac{3}{4} = \frac{4 \times 1 + 3}{4} = \frac{7}{4}$
- $1 \frac{1}{2} = \frac{2 \times 1 + 1}{2} = \frac{3}{2}$

Next, find a common denominator to subtract the fractions. The least common denominator (LCD) of 4 and 2 is 4. Convert $\frac{3}{2}$ to a fraction with a denominator of 4:

\[
\frac{3}{2} = \frac{3 \times 2}{2 \times 2} = \frac{6}{4}
\]

Now, subtract the fractions:

\[
\frac{7}{4} - \frac{6}{4} = \frac{7 - 6}{4} = \frac{1}{4}
\]

Thus, the amount of onion they still need to prepare is:

\[
\boxed{\frac{1}{4}}
\]

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Problem 3:

Question: Their father bought $\frac{3}{4}$ kg of ground pork and $\frac{5}{8}$ kg of ground beef. How much meat do they have in total?

#### Solution:
To find the total amount of meat, we need to add the fractions $\frac{3}{4}$ and $\frac{5}{8}$. First, find a common denominator. The least common denominator (LCD) of 4 and 8 is 8. Convert $\frac{3}{4}$ to a fraction with a denominator of 8:

\[
\frac{3}{4} = \frac{3 \times 2}{4 \times 2} = \frac{6}{8}
\]

Now, add the fractions:

\[
\frac{6}{8} + \frac{5}{8} = \frac{6 + 5}{8} = \frac{11}{8}
\]

Convert the improper fraction $\frac{11}{8}$ to a mixed number:

\[
\frac{11}{8} = 1 \frac{3}{8}
\]

Thus, the total amount of meat they have is:

\[
\boxed{1 \frac{3}{8}}
\]

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Final Answers:

1. $\boxed{\frac{11}{12}}$
2. $\boxed{\frac{1}{4}}$
3. $\boxed{1 \frac{3}{8}}$