Printable primary math worksheet for math grades 1 to 6 based on ... - Free Printable

To solve the problems in the worksheet, we need to subtract fractions and simplify the results to their lowest terms. Let's go through each problem step by step.

Problem 1: \( \frac{5}{8} - \frac{1}{2} \)

1. Find a common denominator. The denominators are 8 and 2. The least common denominator (LCD) is 8.
2. Rewrite \( \frac{1}{2} \) with a denominator of 8:
\[
\frac{1}{2} = \frac{4}{8}
\]
3. Subtract the fractions:
\[
\frac{5}{8} - \frac{4}{8} = \frac{1}{8}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{1}{8} \)

Problem 2: \( \frac{4}{3} - \frac{6}{6} \)

1. Simplify \( \frac{6}{6} \):
\[
\frac{6}{6} = 1
\]
2. Rewrite 1 as a fraction with a denominator of 3:
\[
1 = \frac{3}{3}
\]
3. Subtract the fractions:
\[
\frac{4}{3} - \frac{3}{3} = \frac{1}{3}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{1}{3} \)

Problem 3: \( \frac{6}{6} - \frac{1}{3} \)

1. Simplify \( \frac{6}{6} \):
\[
\frac{6}{6} = 1
\]
2. Rewrite 1 as a fraction with a denominator of 3:
\[
1 = \frac{3}{3}
\]
3. Subtract the fractions:
\[
\frac{3}{3} - \frac{1}{3} = \frac{2}{3}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{2}{3} \)

Problem 4: \( \frac{4}{6} - \frac{1}{2} \)

1. Simplify \( \frac{4}{6} \):
\[
\frac{4}{6} = \frac{2}{3}
\]
2. Find a common denominator. The denominators are 3 and 2. The LCD is 6.
3. Rewrite \( \frac{1}{2} \) with a denominator of 6:
\[
\frac{1}{2} = \frac{3}{6}
\]
4. Subtract the fractions:
\[
\frac{2}{3} = \frac{4}{6}, \quad \frac{4}{6} - \frac{3}{6} = \frac{1}{6}
\]
5. The result is already in its lowest terms.

Answer: \( \frac{1}{6} \)

Problem 5: \( \frac{3}{3} - \frac{1}{6} \)

1. Simplify \( \frac{3}{3} \):
\[
\frac{3}{3} = 1
\]
2. Rewrite 1 as a fraction with a denominator of 6:
\[
1 = \frac{6}{6}
\]
3. Subtract the fractions:
\[
\frac{6}{6} - \frac{1}{6} = \frac{5}{6}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{5}{6} \)

Problem 6: \( \frac{4}{8} - \frac{1}{4} \)

1. Simplify \( \frac{4}{8} \):
\[
\frac{4}{8} = \frac{1}{2}
\]
2. Find a common denominator. The denominators are 2 and 4. The LCD is 4.
3. Rewrite \( \frac{1}{2} \) with a denominator of 4:
\[
\frac{1}{2} = \frac{2}{4}
\]
4. Subtract the fractions:
\[
\frac{2}{4} - \frac{1}{4} = \frac{1}{4}
\]
5. The result is already in its lowest terms.

Answer: \( \frac{1}{4} \)

Problem 7: \( \frac{2}{4} - \frac{2}{8} \)

1. Simplify \( \frac{2}{4} \):
\[
\frac{2}{4} = \frac{1}{2}
\]
2. Find a common denominator. The denominators are 2 and 8. The LCD is 8.
3. Rewrite \( \frac{1}{2} \) with a denominator of 8:
\[
\frac{1}{2} = \frac{4}{8}
\]
4. Subtract the fractions:
\[
\frac{4}{8} - \frac{2}{8} = \frac{2}{8}
\]
5. Simplify \( \frac{2}{8} \):
\[
\frac{2}{8} = \frac{1}{4}
\]

Answer: \( \frac{1}{4} \)

Problem 8: \( \frac{3}{4} - \frac{1}{8} \)

1. Find a common denominator. The denominators are 4 and 8. The LCD is 8.
2. Rewrite \( \frac{3}{4} \) with a denominator of 8:
\[
\frac{3}{4} = \frac{6}{8}
\]
3. Subtract the fractions:
\[
\frac{6}{8} - \frac{1}{8} = \frac{5}{8}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{5}{8} \)

Problem 9: \( \frac{9}{6} - \frac{2}{3} \)

1. Simplify \( \frac{9}{6} \):
\[
\frac{9}{6} = \frac{3}{2}
\]
2. Find a common denominator. The denominators are 2 and 3. The LCD is 6.
3. Rewrite \( \frac{3}{2} \) with a denominator of 6:
\[
\frac{3}{2} = \frac{9}{6}
\]
4. Rewrite \( \frac{2}{3} \) with a denominator of 6:
\[
\frac{2}{3} = \frac{4}{6}
\]
5. Subtract the fractions:
\[
\frac{9}{6} - \frac{4}{6} = \frac{5}{6}
\]
6. The result is already in its lowest terms.

Answer: \( \frac{5}{6} \)

Problem 10: \( \frac{1}{2} - \frac{1}{6} \)

1. Find a common denominator. The denominators are 2 and 6. The LCD is 6.
2. Rewrite \( \frac{1}{2} \) with a denominator of 6:
\[
\frac{1}{2} = \frac{3}{6}
\]
3. Subtract the fractions:
\[
\frac{3}{6} - \frac{1}{6} = \frac{2}{6}
\]
4. Simplify \( \frac{2}{6} \):
\[
\frac{2}{6} = \frac{1}{3}
\]

Answer: \( \frac{1}{3} \)

Problem 11: \( \frac{1}{4} - \frac{1}{8} \)

1. Find a common denominator. The denominators are 4 and 8. The LCD is 8.
2. Rewrite \( \frac{1}{4} \) with a denominator of 8:
\[
\frac{1}{4} = \frac{2}{8}
\]
3. Subtract the fractions:
\[
\frac{2}{8} - \frac{1}{8} = \frac{1}{8}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{1}{8} \)

Problem 12: \( \frac{1}{3} - \frac{1}{6} \)

1. Find a common denominator. The denominators are 3 and 6. The LCD is 6.
2. Rewrite \( \frac{1}{3} \) with a denominator of 6:
\[
\frac{1}{3} = \frac{2}{6}
\]
3. Subtract the fractions:
\[
\frac{2}{6} - \frac{1}{6} = \frac{1}{6}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{1}{6} \)

Problem 13: \( \frac{4}{5} - \frac{1}{10} \)

1. Find a common denominator. The denominators are 5 and 10. The LCD is 10.
2. Rewrite \( \frac{4}{5} \) with a denominator of 10:
\[
\frac{4}{5} = \frac{8}{10}
\]
3. Subtract the fractions:
\[
\frac{8}{10} - \frac{1}{10} = \frac{7}{10}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{7}{10} \)

Problem 14: \( \frac{5}{6} - \frac{1}{6} \)

1. Subtract the fractions:
\[
\frac{5}{6} - \frac{1}{6} = \frac{4}{6}
\]
2. Simplify \( \frac{4}{6} \):
\[
\frac{4}{6} = \frac{2}{3}
\]

Answer: \( \frac{2}{3} \)

Problem 15: \( \frac{1}{2} - \frac{1}{8} \)

1. Find a common denominator. The denominators are 2 and 8. The LCD is 8.
2. Rewrite \( \frac{1}{2} \) with a denominator of 8:
\[
\frac{1}{2} = \frac{4}{8}
\]
3. Subtract the fractions:
\[
\frac{4}{8} - \frac{1}{8} = \frac{3}{8}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{3}{8} \)

Problem 16: \( \frac{3}{5} - \frac{4}{10} \)

1. Simplify \( \frac{4}{10} \):
\[
\frac{4}{10} = \frac{2}{5}
\]
2. Find a common denominator. The denominators are 5 and 5. The LCD is 5.
3. Subtract the fractions:
\[
\frac{3}{5} - \frac{2}{5} = \frac{1}{5}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{1}{5} \)

Problem 17: \( \frac{6}{9} - \frac{1}{3} \)

1. Simplify \( \frac{6}{9} \):
\[
\frac{6}{9} = \frac{2}{3}
\]
2. Find a common denominator. The denominators are 3 and 3. The LCD is 3.
3. Subtract the fractions:
\[
\frac{2}{3} - \frac{1}{3} = \frac{1}{3}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{1}{3} \)

Problem 18: \( \frac{3}{6} - \frac{1}{3} \)

1. Simplify \( \frac{3}{6} \):
\[
\frac{3}{6} = \frac{1}{2}
\]
2. Find a common denominator. The denominators are 2 and 3. The LCD is 6.
3. Rewrite \( \frac{1}{2} \) with a denominator of 6:
\[
\frac{1}{2} = \frac{3}{6}
\]
4. Rewrite \( \frac{1}{3} \) with a denominator of 6:
\[
\frac{1}{3} = \frac{2}{6}
\]
5. Subtract the fractions:
\[
\frac{3}{6} - \frac{2}{6} = \frac{1}{6}
\]
6. The result is already in its lowest terms.

Answer: \( \frac{1}{6} \)

Problem 19: \( \frac{3}{3} - \frac{2}{6} \)

1. Simplify \( \frac{3}{3} \):
\[
\frac{3}{3} = 1
\]
2. Simplify \( \frac{2}{6} \):
\[
\frac{2}{6} = \frac{1}{3}
\]
3. Rewrite 1 as a fraction with a denominator of 3:
\[
1 = \frac{3}{3}
\]
4. Subtract the fractions:
\[
\frac{3}{3} - \frac{1}{3} = \frac{2}{3}
\]
5. The result is already in its lowest terms.

Answer: \( \frac{2}{3} \)

Problem 20: \( \frac{4}{3} - \frac{4}{6} \)

1. Simplify \( \frac{4}{6} \):
\[
\frac{4}{6} = \frac{2}{3}
\]
2. Find a common denominator. The denominators are 3 and 3. The LCD is 3.
3. Subtract the fractions:
\[
\frac{4}{3} - \frac{2}{3} = \frac{2}{3}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{2}{3} \)

Problem 21: \( \frac{5}{6} - \frac{1}{6} \)

1. Subtract the fractions:
\[
\frac{5}{6} - \frac{1}{6} = \frac{4}{6}
\]
2. Simplify \( \frac{4}{6} \):
\[
\frac{4}{6} = \frac{2}{3}
\]

Answer: \( \frac{2}{3} \)

Problem 22: \( \frac{4}{6} - \frac{1}{3} \)

1. Simplify \( \frac{4}{6} \):
\[
\frac{4}{6} = \frac{2}{3}
\]
2. Find a common denominator. The denominators are 3 and 3. The LCD is 3.
3. Subtract the fractions:
\[
\frac{2}{3} - \frac{1}{3} = \frac{1}{3}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{1}{3} \)

Problem 23: \( \frac{5}{8} - \frac{2}{4} \)

1. Simplify \( \frac{2}{4} \):
\[
\frac{2}{4} = \frac{1}{2}
\]
2. Find a common denominator. The denominators are 8 and 2. The LCD is 8.
3. Rewrite \( \frac{1}{2} \) with a denominator of 8:
\[
\frac{1}{2} = \frac{4}{8}
\]
4. Subtract the fractions:
\[
\frac{5}{8} - \frac{4}{8} = \frac{1}{8}
\]
5. The result is already in its lowest terms.

Answer: \( \frac{1}{8} \)

Problem 24: \( \frac{3}{4} - \frac{1}{2} \)

1. Find a common denominator. The denominators are 4 and 2. The LCD is 4.
2. Rewrite \( \frac{1}{2} \) with a denominator of 4:
\[
\frac{1}{2} = \frac{2}{4}
\]
3. Subtract the fractions:
\[
\frac{3}{4} - \frac{2}{4} = \frac{1}{4}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{1}{4} \)

Problem 25: \( \frac{2}{3} - \frac{1}{6} \)

1. Find a common denominator. The denominators are 3 and 6. The LCD is 6.
2. Rewrite \( \frac{2}{3} \) with a denominator of 6:
\[
\frac{2}{3} = \frac{4}{6}
\]
3. Subtract the fractions:
\[
\frac{4}{6} - \frac{1}{6} = \frac{3}{6}
\]
4. Simplify \( \frac{3}{6} \):
\[
\frac{3}{6} = \frac{1}{2}
\]

Answer: \( \frac{1}{2} \)

Problem 26: \( \frac{1}{2} - \frac{1}{4} \)

1. Find a common denominator. The denominators are 2 and 4. The LCD is 4.
2. Rewrite \( \frac{1}{2} \) with a denominator of 4:
\[
\frac{1}{2} = \frac{2}{4}
\]
3. Subtract the fractions:
\[
\frac{2}{4} - \frac{1}{4} = \frac{1}{4}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{1}{4} \)

Problem 27: \( \frac{4}{5} - \frac{2}{10} \)

1. Simplify \( \frac{2}{10} \):
\[
\frac{2}{10} = \frac{1}{5}
\]
2. Find a common denominator. The denominators are 5 and 5. The LCD is 5.
3. Subtract the fractions:
\[
\frac{4}{5} - \frac{1}{5} = \frac{3}{5}
\]
4. The result is already in its lowest terms.

Answer: \( \frac{3}{5} \)

Final Answer:

\[
\boxed{
\begin{array}{ccc}
\frac{1}{8} & \frac{1}{3} & \\
\frac{2}{3} & \frac{1}{6} & \\
\frac{5}{6} & \frac{1}{4} & \\
\frac{1}{4} & \frac{5}{8} & \frac{5}{6} \\
\frac{1}{3} & \frac{1}{8} & \frac{1}{6} \\
\frac{7}{10} & \frac{2}{3} & \frac{3}{8} \\
\frac{1}{5} & \frac{1}{3} & \frac{1}{6} \\
\frac{2}{3} & \frac{2}{3} & \frac{2}{3} \\
\frac{1}{3} & \frac{1}{8} & \frac{1}{4} \\
\frac{1}{2} & \frac{1}{4} & \frac{3}{5} \\
\end{array}
}
\]