Let’s solve each problem step by step.
First, we need to find the column vector for each letter (a, b, c, d) by looking at how many units they move right/left and up/down on the grid.
Remember:
→ Right = positive x-direction
→ Left = negative x-direction
→ Up = positive y-direction
→ Down = negative y-direction
We write vectors as:
[ horizontal change ]
[ vertical change ]
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Step 1: Find vector a
Vector
a starts at bottom-left and goes to top-right.
From start to end:
- Moves 3 units right → +3
- Moves 2 units up → +2
So,
a = [3, 2]
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Step 2: Find vector b
Vector
b goes down and slightly right.
From start to end:
- Moves 1 unit right → +1
- Moves 4 units down → -4
So,
b = [1, -4]
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Step 3: Find vector c
Vector
c is horizontal to the right.
- Moves 2 units right → +2
- No vertical movement → 0
So,
c = [2, 0]
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Step 4: Find vector d
Vector
d goes down and left.
From start to end:
- Moves 2 units left → -2
- Moves 2 units down → -2
So,
d = [-2, -2]
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Now let’s compute each sum:
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1) a + b = [3, 2] + [1, -4] = [3+1, 2+(-4)] = [4, -2]
2) b + a = [1, -4] + [3, 2] = [1+3, -4+2] = [4, -2]
(Same as #1 — addition is commutative!)
3) a + c = [3, 2] + [2, 0] = [3+2, 2+0] = [5, 2]
4) c + d = [2, 0] + [-2, -2] = [2+(-2), 0+(-2)] = [0, -2]
5) d + c = [-2, -2] + [2, 0] = [-2+2, -2+0] = [0, -2]
(Same as #4)
6) b + c = [1, -4] + [2, 0] = [1+2, -4+0] = [3, -4]
7) d + b + c = [-2, -2] + [1, -4] + [2, 0]
Add step by step:
First: [-2, -2] + [1, -4] = [-1, -6]
Then: [-1, -6] + [2, 0] = [1, -6]
8) a + b + c + d = [3, 2] + [1, -4] + [2, 0] + [-2, -2]
Add in order:
[3+1, 2+(-4)] = [4, -2]
[4+2, -2+0] = [6, -2]
[6+(-2), -2+(-2)] = [4, -4]
Alternatively, add all x-components: 3 + 1 + 2 + (-2) = 4
All y-components: 2 + (-4) + 0 + (-2) = -4
So [4, -4]
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Final Answer:
1) [4, -2]
2) [4, -2]
3) [5, 2]
4) [0, -2]
5) [0, -2]
6) [3, -4]
7) [1, -6]
8) [4, -4]
Parent Tip: Review the logic above to help your child master the concept of addition of vectors worksheet.