Math Puzzle Worksheets 5th Grade Kids Will Love! Get It Free Now! - Free Printable

To find the correct path from Start to Finish, we need to solve each equation in the white boxes and check if the value of $X$ matches the number written on the yellow path leading out of that box. If they match, that is the correct way to go.

Let's trace the path step-by-step:

Step 1: Start at the top-left box.
* Equation: $X + 7 = 15$
* Solve for $X$: Subtract 7 from 15.
$$15 - 7 = 8$$
So, $X = 8$.
* Look at the paths:
* The path going right says $X = 17$. (Incorrect)
* The path going down says $X = 11$. (Incorrect)
* The diagonal path going down-right says $X = 8$. (Correct)
* Move: Follow the diagonal path labeled $X = 8$.

Step 2: Arrive at the second box.
* Equation: $X + 6 = 13$
* Solve for $X$: Subtract 6 from 13.
$$13 - 6 = 7$$
So, $X = 7$.
* Look at the paths:
* The path going up says $X = 2$. (Incorrect)
* The path going right says $X = 4$. (Incorrect)
* The path going down says $X = 5$. (Incorrect)
* The diagonal path going down-left says $X = 7$. (Correct)
* Move: Follow the diagonal path labeled $X = 7$.

Step 3: Arrive at the third box.
* Equation: $5X = 20$
* Solve for $X$: Divide 20 by 5.
$$20 / 5 = 4$$
So, $X = 4$.
* Look at the paths:
* The path going up says $X = 11$. (Incorrect)
* The path going down says $X = 6$. (Incorrect)
* The diagonal path going down-right says $X = 4$. (Correct)
* Move: Follow the diagonal path labeled $X = 4$.

Step 4: Arrive at the fourth box.
* Equation: $X + 3 = 12$
* Solve for $X$: Subtract 3 from 12.
$$12 - 3 = 9$$
So, $X = 9$.
* Look at the paths:
* The path going up says $X = 8$. (Incorrect)
* The path going right says $X = 8$. (Incorrect)
* The path going down says $X = 9$. (Correct)
* Move: Follow the vertical path down labeled $X = 9$.

Step 5: Arrive at the fifth box.
* Equation: $X - 4 = 8$
* Solve for $X$: Add 4 to 8.
$$8 + 4 = 12$$
So, $X = 12$.
* Look at the paths:
* The path going right says $X = 11$. (Incorrect)
* The diagonal path going up-right says $X = 4$. (Incorrect)
* Wait, let me re-check the previous step. Let's look at the neighbors of "X - 4 = 8".
* Up: $X+3=12 \rightarrow X=9$. Path down is labeled $X=9$. Correct.
* From $X-4=8$, $X=12$.
* Paths from this box:
* Right: Label is $X=11$. ($12 \neq 11$)
* Diagonal Up-Right: Label is $X=4$. ($12 \neq 4$)

Let me re-evaluate Step 4. Did I make a mistake?
Box: $X + 3 = 12 \rightarrow X = 9$.
Paths from this box:
- Down: Label $X=9$. Leads to $X-4=8$.
- Right: Label $X=8$. Leads to $X-10=5$.
- Diagonal Down-Right: Label $X=4$? No, looking closely at the image, the diagonal from $X+3=12$ goes to $X-10=5$? No, the grid structure is:
Row 3 Left: $5X=20$.
Row 4 Left: $X+3=12$.
Row 5 Left: $X-4=8$.

Let's re-read the connections from $X+3=12$.
- Down to $X-4=8$: Label is $X=9$. Since $X=9$ for the current box, this is a valid move.
- Right to $X-10=5$: Label is $X=8$. Since $X=9$ for current box, this is invalid.
- Diagonal to $X-10=5$? The yellow bar between $X+3=12$ and $X-10=5$ is labeled $X=8$? No, the bar connecting $X+3=12$ (Row 4, Col 1) and $X-10=5$ (Row 4, Col 2) is horizontal? No, looking at the layout:

Let's map the coordinates roughly:
(1,1) Start: $X+7=15 \rightarrow X=8$. Path diag to (2,2).
(2,2) $X+6=13 \rightarrow X=7$. Path diag to (3,1).
(3,1) $5X=20 \rightarrow X=4$. Path diag to (4,2)? Or (4,1)?
The box below $5X=20$ is $X+3=12$. The path is vertical, labeled $X=6$. $4 \neq 6$. So we don't go down.
The box to the right of $5X=20$ is not directly connected horizontally.
The diagonal path from $5X=20$ goes to $X-10=5$? The label is $X=4$.
Let's check the box $X-10=5$.
Equation: $X - 10 = 5 \rightarrow X = 15$.

Let's restart the trace carefully.

Node 1: Start ($X + 7 = 15$)
$X = 8$.
Possible exits:
- Right ($X=17$): No.
- Down ($X=11$): No.
- Diagonal Down-Right ($X=8$): Yes.
Next Node: $X + 6 = 13$

Node 2: $X + 6 = 13$
$X = 7$.
Possible exits:
- Up ($X=2$): No.
- Right ($X=4$): No.
- Down ($X=5$): No.
- Diagonal Down-Left ($X=7$): Yes.
Next Node: $5X = 20$

Node 3: $5X = 20$
$X = 4$.
Possible exits:
- Up ($X=11$): No.
- Down ($X=6$): No.
- Diagonal Down-Right ($X=4$): Yes.
Next Node: $X - 10 = 5$ (This is in the 4th row, 2nd column position visually)

Node 4: $X - 10 = 5$
$X = 15$.
Possible exits:
- Up ($X=5$): No.
- Left ($X=8$ - coming from $X+3=12$? No, that's a different connection): Let's look at connections FROM $X-10=5$.
- Up-Left (back to start area): No.
- Right ($X=15$): There is a horizontal path to the right labeled $X=15$. Let's follow it.
- Down ($X=25$): No.
- Diagonal Down-Right ($X=14$): No.

So, from $X-10=5$ ($X=15$), the path labeled $X=15$ goes to the right.
Next Node: $8X = 24$

Node 5: $8X = 24$
$X = 3$ ($24 / 8 = 3$).
Possible exits:
- Up ($X=3$): This leads back to $6+X=15$. Let's check if we came from there? No, we came from left. Can we go up?
The path Up is labeled $X=3$. Since $X=3$, this is a valid mathematical match. However, usually these mazes don't loop back. Let's check other options first.
- Left ($X=15$): We came from here.
- Right ($X=6$): No ($3 \neq 6$).
- Down ($X=4$): No ($3 \neq 4$).
- Diagonal Down-Right ($X=2$): No ($3 \neq 2$).
- Diagonal Up-Right ($X=12$? No, that's from previous node).

Wait, let's look at the connections around $8X=24$ again.
It is connected to:
- Left: $X-10=5$. Path label $X=15$. (We used this to enter).
- Up: $6+X=15$. Path label $X=3$.
- Right: $8+X=15$. Path label $X=6$.
- Down: $X+2=10$. Path label $X=4$.
- Diagonal Down-Right: To Finish? No, Finish is further right/down.

Let's re-solve Node 5: $8X = 24 \rightarrow X = 3$.
Exits:
- Up to $6+X=15$: Label is $X=3$. Match!
- Right to $8+X=15$: Label is $X=6$. No Match.
- Down to $X+2=10$: Label is $X=4$. No Match.
- Diagonal Down-Right to Finish: Label is $X=2$. No Match.

So we must go Up to $6 + X = 15$.

Node 6: $6 + X = 15$
$X = 9$ ($15 - 6 = 9$).
Possible exits:
- Down (back to $8X=24$): Label $X=3$. No ($9 \neq 3$).
- Left ($X=4$): No.
- Right ($X=9$): There is a path to the right labeled $X=9$.
- Up ($X=3$): No.
- Diagonal Up-Right ($X=2$): No.

So, from $6+X=15$ ($X=9$), the path labeled $X=9$ goes to the right.
Next Node: $X - 7 = 6$

Node 7: $X - 7 = 6$
$X = 13$ ($6 + 7 = 13$).
Possible exits:
- Left (back): Label $X=9$. No.
- Up ($X=10$): No.
- Down ($X=13$): There is a path down labeled $X=13$.
- Diagonal Down-Left ($X=12$): No.

So, from $X-7=6$ ($X=13$), the path labeled $X=13$ goes down.
Next Node: $8 + X = 15$

Node 8: $8 + X = 15$
$X = 7$ ($15 - 8 = 7$).
Possible exits:
- Up (back): Label $X=13$. No.
- Left ($X=6$): No.
- Down ($X=7$): There is a path down labeled $X=7$.
- Diagonal Down-Left ($X=2$): No.

So, from $8+X=15$ ($X=7$), the path labeled $X=7$ goes down.
Next Node: Finish

Let's double check the final step.
The box above Finish is $8+X=15$.
$X=7$.
The path from $8+X=15$ to Finish is labeled $X=7$.
This matches.

Let's verify the full sequence one more time to be absolutely sure.

1. Start: $X + 7 = 15 \Rightarrow X = 8$. Path $X=8$ (diag) $\rightarrow$
2. $X + 6 = 13 \Rightarrow X = 7$. Path $X=7$ (diag) $\rightarrow$
3. $5X = 20 \Rightarrow X = 4$. Path $X=4$ (diag) $\rightarrow$
4. $X - 10 = 5 \Rightarrow X = 15$. Path $X=15$ (right) $\rightarrow$
5. $8X = 24 \Rightarrow X = 3$. Path $X=3$ (up) $\rightarrow$
*Wait*, going UP from $8X=24$ leads to $6+X=15$.
Let's check the label on the path between $8X=24$ and $6+X=15$.
The vertical yellow bar between them has the text $X=3$.
Since $X=3$ for the box $8X=24$, this is a valid exit.
6. $6 + X = 15 \Rightarrow X = 9$. Path $X=9$ (right) $\rightarrow$
7. $X - 7 = 6 \Rightarrow X = 13$. Path $X=13$ (down) $\rightarrow$
8. $8 + X = 15 \Rightarrow X = 7$. Path $X=7$ (down) $\rightarrow$
9. Finish.

The logic holds up perfectly.

Final Answer:
The correct path is:
1. $X + 7 = 15$ ($X=8$) $\xrightarrow{X=8}$
2. $X + 6 = 13$ ($X=7$) $\xrightarrow{X=7}$
3. $5X = 20$ ($X=4$) $\xrightarrow{X=4}$
4. $X - 10 = 5$ ($X=15$) $\xrightarrow{X=15}$
5. $8X = 24$ ($X=3$) $\xrightarrow{X=3}$
6. $6 + X = 15$ ($X=9$) $\xrightarrow{X=9}$
7. $X - 7 = 6$ ($X=13$) $\xrightarrow{X=13}$
8. $8 + X = 15$ ($X=7$) $\xrightarrow{X=7}$
9. Finish