Four Digit Addition Worksheet-4 - skoolon.com - Free Printable

Let's solve the math worksheet step by step.

---

Q1: Look at the picture and fill in the missing number.

We are given a Venn diagram with three overlapping circles labeled A, B, and C.

The numbers provided are:
- Intersection of A and B: 800
- Intersection of B and C: 700
- Only B: 1400
- Only C: 2200
- A has a missing number (the part that is only in A, not overlapping with B or C)

We need to find the missing number in circle A.

But wait — the question says "Look at the picture" — but we don't have actual visual data about total values. However, based on typical such problems, this might be a set addition problem, where the numbers represent quantities in regions.

Let’s interpret:

- The only B region = 1400
- A ∩ B = 800
- B ∩ C = 700
- Only C = 2200
- Only A = ?

But there's no total given for the whole set. So perhaps the idea is that the sum of all parts equals some total, but since it's not provided, maybe the missing number is just asking for what belongs only to A?

Wait — let’s look again. Perhaps the diagram is meant to represent addition relationships between the sets.

Alternatively, maybe the total of all regions is implied from context? But no totals are given.

Wait — actually, here's a different interpretation: sometimes in these diagrams, the numbers in the overlaps represent shared values, and we may need to deduce the value only in A using logic.

But unless there’s more information, like a total sum, we can’t determine the missing number.

But hold on — maybe this is a number decomposition or addition puzzle based on the diagram.

Wait — perhaps the entire circle B has a total value?

Let’s assume that the value in circle B is the sum of its parts:
- Only B: 1400
- A ∩ B: 800
- B ∩ C: 700

So total in B = 1400 + 800 + 700 = 2900

Similarly, total in C = Only C + B ∩ C = 2200 + 700 = 2900

Now, if we suppose symmetry or pattern, maybe total in A is also 2900?

Then:
- Only A = ?
- A ∩ B = 800
- So Only A = 2900 - 800 = 2100

But that’s an assumption.

Alternatively, maybe the sum of all unique parts is required?

But we don’t know the total.

Wait — perhaps the diagram represents additive relationships, and the missing number is such that the sum across the entire figure makes sense.

But without more context, this seems ambiguous.

Wait — let’s consider another possibility: Maybe the numbers in the intersections are addends, and the missing number is such that when added to others, gives a total.

But still unclear.

Wait — perhaps this is a Venn diagram where the numbers are values in each region, and we are to find the value in only A, but we need more info.

But look — maybe the sum of all regions is implied from other questions? Probably not.

Wait — perhaps this is a misunderstanding. Let’s re-read:

> Q1. Look at the picture and fill in the missing number.

There’s a diagram with:
- A and B overlap: 800
- B and C overlap: 700
- Only B: 1400
- Only C: 2200
- Only A: ?

But unless we know the total or some relationship, we cannot find the missing number.

Wait — perhaps the value in circle A is supposed to be equal to something?

Alternatively, maybe the numbers are parts of a larger addition, and the missing number is such that the total of A is consistent with other totals.

But we don’t have any totals.

Wait — let’s check if there’s a typo or misinterpretation.

Another idea: Perhaps the numbers in the overlaps are differences or shared values, but still.

Wait — perhaps the total of B is 1400 + 800 + 700 = 2900

Total of C = 2200 + 700 = 2900

So both B and C have total 2900.

Maybe A also has total 2900?

Then:
- A = Only A + (A ∩ B) = ? + 800 = 2900 → Only A = 2100

That would make sense.

So the missing number is 2100

But is that logical?

Yes, if the diagram is symmetric or designed so that each circle has the same total.

Alternatively, maybe the sum of all regions is needed, but we don’t have that.

But since the only way to get a numerical answer is to assume symmetry, and B and C both sum to 2900, likely A also does.

Thus:
- Only A = Total A - (A ∩ B)
- = 2900 - 800 = 2100

So the missing number is 2100

✔ Answer to Q1: 2100

---

Q2: Fill the missing numbers in the circle.

This is a set of 4-digit addition problems with place values labeled: Th (Thousands), H (Hundreds), T (Tens), O (Ones).

Let’s solve each one.

---

#### Problem 1:

```
Th H T O
3 6 7 ?
+ 3 ? 4
-----------
3 9 7 9
```

Let’s add column by column from right to left.

Ones (O):
- ? + 4 = 9 → ? = 5

So first missing digit (top right) is 5

Tens (T):
- 7 + ? = 7 → ? = 0

But wait: 7 + ? = 7 → ? = 0

But we must check for carry-over.

From ones: 5 + 4 = 9 → no carry-over → OK

So tens: 7 + ? = 7 → ? = 0

So second missing digit (bottom tens) is 0

Hundreds (H):
- 6 + 3 = 9 → matches

No carry-over

Thousands (Th):
- 3 + 0 = 3 → matches

So complete:

```
3 6 7 5
+ 3 0 4
-----------
3 9 7 9
```

✔ So missing digits: top O = 5, bottom T = 0

---

#### Problem 2:

```
Th H T O
? 9 5 4
+ 3 ? 6
-----------
6 3 2 0
```

Start from right.

Ones (O):
- 4 + 6 = 10 → write 0, carry 1

So units digit is 0 → correct

Tens (T):
- 5 + ? + carry 1 = 2 → 5 + ? + 1 = 2 → 6 + ? = 2 → ? = -4 → impossible

Wait! That can’t be.

Wait: 5 + ? + 1 = 2 → but 5 + ? + 1 ≥ 6, but result is 2 → so must have carry-over to hundreds

So: 5 + ? + 1 = 12 → because digit is 2, carry 1 to next

So: 5 + ? + 1 = 12 → ? = 6

So tens digit in second number is 6

And carry 1 to hundreds

Hundreds (H):
- 9 + 3 + carry 1 = 13 → write 3, carry 1

But the sum shows 3 in hundreds → OK

Thousands (Th):
- ? + 0 + carry 1 = 6 → so ? + 1 = 6 → ? = 5

So top thousands digit is 5

Check:

```
5 9 5 4
+ 3 6 6
-----------
6 3 2 0
```

Add:
- 4 + 6 = 10 → write 0, carry 1
- 5 + 6 + 1 = 12 → write 2, carry 1
- 9 + 3 + 1 = 13 → write 3, carry 1
- 5 + 0 + 1 = 6 → write 6

Perfect.

✔ Missing digits: top Th = 5, bottom T = 6

---

#### Problem 3:

```
Th H T O
6 ? 1 7
+ 9 7 ?
-----------
7 2 9 2
```

Start from right.

Ones (O):
- 7 + ? = 2 → must have carry-over

So 7 + ? = 12 → ? = 5 (since 7 + 5 = 12), carry 1

So bottom O = 5

Tens (T):
- 1 + 7 + carry 1 = 9 → 1 + 7 + 1 = 9 → perfect → no carry

So tens digit is correct.

Hundreds (H):
- ? + 9 = 2 → but ? + 9 = 2 → impossible unless carry-over

So ? + 9 = 12 → then write 2, carry 1

So ? = 3 (since 3 + 9 = 12)

So top H = 3

Thousands (Th):
- 6 + 0 + carry 1 = 7 → 6 + 1 = 7 → correct

So:

```
6 3 1 7
+ 9 7 5
-----------
7 2 9 2
```

Check:
- 7 + 5 = 12 → write 2, carry 1
- 1 + 7 + 1 = 9 → write 9
- 3 + 9 = 12 → write 2, carry 1
- 6 + 0 + 1 = 7 → write 7

Perfect.

✔ Missing digits: top H = 3, bottom O = 5

---

#### Problem 4:

```
Th H T O
5 ? 7 ?
+ 3 3 ? ?
-----------
8 8 9 2
```

Wait — this one has two missing digits in the second number?

But looking at the image: the second number is written as:

```
3 3 ? ?
```

But the sum is 8892

So we need to fill in the last two digits of the second number.

But the first number is: 5 ? 7 ?

So two missing digits in first number, two in second.

Let’s write it clearly:

```
Th H T O
5 ? 7 ?
+ 3 3 ? ?
-------------
8 8 9 2
```

We need to find four digits: ?, ?, ?, ?

Let’s start from right.

Ones (O):
- ? + ? = 2 → possible combinations: 0+2, 1+1, 2+0, etc., but could have carry

But we don’t know.

Let’s denote:
- First number: 5 A 7 B
- Second number: 3 3 C D
- Sum: 8 8 9 2

So:

Ones (O):
- B + D = 2 or 12 or 22... but max 9+9=18 → so either 2 or 12

If B + D = 2 → carry 0
If B + D = 12 → carry 1

Tens (T):
- 7 + C + carry = 9 → so 7 + C + c1 = 9 or 19

→ 7 + C + c1 = 9 → C = 2 - c1 → if c1=0 → C=2; if c1=1 → C=1

Or 7 + C + c1 = 19 → C = 12 - c1 → impossible since C ≤ 9

So only possibilities:
- c1 = 0 → C = 2
- c1 = 1 → C = 1

So C = 1 or 2

Hundreds (H):
- A + 3 + carry from tens = 8

Let’s call carry from tens = c2

So A + 3 + c2 = 8 or 18

→ A + 3 + c2 = 8 → A = 5 - c2
→ A + 3 + c2 = 18 → A = 15 - c2 → impossible since A ≤ 9

So A + 3 + c2 = 8 → A = 5 - c2

c2 is carry from tens → either 0 or 1

So:
- If c2 = 0 → A = 5
- If c2 = 1 → A = 4

Thousands (Th):
- 5 + 3 + carry from hundreds = 8

So 8 + c3 = 8 → c3 = 0

So carry from hundreds = 0

But from hundreds: A + 3 + c2 = 8 → and carry to thousands is c3

But we just said c3 = 0

So A + 3 + c2 = 8 → and no carry → so A + 3 + c2 ≤ 9

But we already have that.

Now back to tens.

We had:
- 7 + C + c1 = 9 → so C = 2 - c1 → C = 2 or 1

And carry from tens = c2 = 0 or 1

But c2 is carry from tens → so if 7 + C + c1 ≥ 10 → c2 = 1, else 0

Now try possibilities.

Let’s try c1 = 0 → then B + D = 2 → no carry

Then tens: 7 + C + 0 = 9 → C = 2 → so C = 2

Then tens sum = 7 + 2 = 9 → no carry → c2 = 0

Then hundreds: A + 3 + 0 = 8 → A = 5

Then thousands: 5 + 3 + 0 = 8 → good

Now ones: B + D = 2 → B and D digits → possible: B=0,D=2; B=1,D=1; B=2,D=0

But we need to check if any constraint.

But we have no other constraints.

But the first number is 5 A 7 B = 5 5 7 B

Second number: 3 3 2 D

Sum: 8 8 9 2

Try B = 0, D = 2:

First: 5570
Second: 3322
Sum: 5570 + 3322 = 8892 → YES!

Check:
- 0 + 2 = 2 → OK
- 7 + 2 = 9 → OK
- 5 + 3 = 8 → OK
- 5 + 3 = 8 → OK

Perfect.

So solution: A = 5, B = 0, C = 2, D = 2

But wait — the second number has two missing digits: C and D

In our case: C = 2, D = 2

But the problem says "fill the missing numbers", so we need to fill:

- Top H: A = 5
- Top O: B = 0
- Bottom T: C = 2
- Bottom O: D = 2

So missing digits: 5, 0, 2, 2

But let’s see if other solutions exist.

Suppose c1 = 1 → B + D = 12 → carry 1

Then tens: 7 + C + 1 = 9 → C = 1

Then tens sum = 7 + 1 + 1 = 9 → no carry → c2 = 0

Then hundreds: A + 3 + 0 = 8 → A = 5

Thousands: 5 + 3 + 0 = 8 → OK

Now ones: B + D = 12 → possible: B=3,D=9; B=4,D=8; ... up to B=9,D=3

Try B=3, D=9

First number: 5 5 7 3 = 5573
Second: 3 3 1 9 = 3319
Sum: 5573 + 3319 = 8892? → 5573 + 3319 = 8892 → yes!

Check:
- 3 + 9 = 12 → write 2, carry 1
- 7 + 1 + 1 = 9 → OK
- 5 + 3 = 8 → OK
- 5 + 3 = 8 → OK

Also works.

So multiple solutions?

But the problem expects specific answers.

But in the image, the second number is written as:

```
3 3 ? ?
```

So both T and O are missing.

But we have multiple possibilities.

But let’s check the first number: it’s 5 ? 7 ?

We found A = 5 in both cases.

But in first case: B = 0, D = 2 → 5570 + 3322 = 8892

Second case: B = 3, D = 9 → 5573 + 3319 = 8892

Both work.

But is there a constraint we missed?

Wait — the sum is 8892, and both give that.

But perhaps the problem assumes no leading zero, but 3322 and 3319 are fine.

But maybe the first number has a missing digit in hundreds, which is A = 5 in both cases.

So A = 5 is fixed.

But B and C, D vary.

But in the diagram, the second number has two missing digits, so we need to specify.

But without more constraints, multiple solutions exist.

But perhaps the problem intends minimal digits or something.

Wait — but in the tens place, the sum is 9.

In first case: 7 + 2 = 9 → no carry

In second case: 7 + 1 + 1 (carry from ones) = 9 → also valid

But both are valid.

But perhaps we can look at the ones place.

But no constraint.

Wait — but the first number is 5 ? 7 ?

If we assume no leading zero, but it's already 5, so fine.

But perhaps the intended solution is the one with smaller numbers.

But let’s see the thousands:

5 + 3 = 8 → no carry → so carry from hundreds must be 0

So A + 3 + c2 ≤ 9

We already used that.

But in both cases, c2 = 0

So both are valid.

But maybe the problem has a typo, or we need to assume no carry-over?

But both are valid.

Wait — but look at the second number: it’s written as:

```
3 3 ? ?
```

But in the first solution: 3322 → 3 3 2 2

In second: 3319 → 3 3 1 9

But the tens digit is missing — so both possible.

But perhaps the problem expects only one answer, so maybe we need to pick the one where digits are consistent.

But there’s no unique solution.

Wait — but in the first number, the ones digit is missing — so B is unknown.

But in the sum, the ones digit is 2.

So B + D = 2 or 12

But if B + D = 2 → B and D small

If B + D = 12 → larger

But both work.

But perhaps the intended solution is the simplest, like B=0, D=2, C=2

Then:

First number: 5 5 7 0 = 5570

Second: 3 3 2 2 = 3322

Sum: 5570 + 3322 = 8892 → correct

So missing digits:
- Top H: 5
- Top O: 0
- Bottom T: 2
- Bottom O: 2

So we’ll go with that.

✔ Answer: A=5, B=0, C=2, D=2

But note: other solutions exist, but this is likely intended.

---

✔ Final Answers:

#### Q1: The missing number is 2100

#### Q2:

1.
```
3 6 7 5
+ 3 0 4
-----------
3 9 7 9
```
→ Missing: 5 and 0

2.
```
5 9 5 4
+ 3 6 6
-----------
6 3 2 0
```
→ Missing: 5 and 6

3.
```
6 3 1 7
+ 9 7 5
-----------
7 2 9 2
```
→ Missing: 3 and 5

4.
```
5 5 7 0
+ 3 3 2 2
-----------
8 8 9 2
```
→ Missing: 5, 0, 2, 2

---

Summary:

Q1: 2100

Q2:
- Problem 1: 5, 0
- Problem 2: 5, 6
- Problem 3: 3, 5
- Problem 4: 5, 0, 2, 2

Let me know if you'd like a printed version or explanation for any part!