High School Algebra 1 final exam with editable questions on graphing inequalities and simplifying expressions.

I'll solve the visible problems from this Algebra 1 exam.

## Problem 36: Which point is a solution to the graphed system of linear inequalities?

Looking at the graph, I can see:
- A solid line with positive slope (going up from left to right)
- A dashed horizontal line
- The shaded region is below both lines

Let me identify the equations:
- The solid line appears to pass through points like (-2, -2), (0, 0), and (2, 2), so it's y = x
- The dashed horizontal line appears to be at y = 2

The inequalities are:
- y ≤ x (solid line, shaded below)
- y < 2 (dashed line, shaded below)

Now let me check each point:

a. (-3, 0)
- Is 0 ≤ -3? No, 0 > -3
- This point does NOT satisfy y ≤ x

b. (2, 3)
- Is 3 ≤ 2? No, 3 > 2
- This point does NOT satisfy y ≤ x

c. (0, 3)
- Is 3 ≤ 0? No, 3 > 0
- This point does NOT satisfy y ≤ x

d. (-3, -5)
- Is -5 ≤ -3? Yes, -5 < -3 ✓
- Is -5 < 2? Yes ✓
- This point satisfies BOTH inequalities

Final Answer: d. (-3, -5)

---

## Simplify the expression: (15x⁻⁸yz / 3xyz³)⁰

Any non-zero expression raised to the power of 0 equals 1.

As long as the expression inside the parentheses is not zero (which it isn't, since we have variables and constants), the answer is simply 1.

Final Answer: 1

---

## Problem 40: Which equation best matches the graphed line?

Looking at the graph, I need to find the equation of the line shown.

From the graph, I can identify two points on the line:
- The line appears to pass through (0, -4) - the y-intercept
- The line appears to pass through (-3, 0) - the x-intercept

Let me calculate the slope:
m = (y₂ - y₁)/(x₂ - x₁) = (0 - (-4))/(-3 - 0) = 4/(-3) = -4/3

Using point-slope form with point (0, -4):
y - (-4) = -4/3(x - 0)
y + 4 = -4/3x
y = -4/3x - 4

Converting to standard form:
Multiply by 3: 3y = -4x - 12
Add 4x to both sides: 4x + 3y = -12

Hmm, that doesn't match any of the options exactly. Let me reconsider the points.

Looking more carefully at the grid, the line might pass through different points. Let me try:
- Point at approximately (-2, -2)
- Point at approximately (1, -6)

Actually, let me test each option by finding their intercepts:

a. 8x + 12y = -24
- If x = 0: 12y = -24, so y = -2
- If y = 0: 8x = -24, so x = -3
- Points: (0, -2) and (-3, 0)

b. 3x + 2y = 6
- If x = 0: 2y = 6, so y = 3
- If y = 0: 3x = 6, so x = 2
- Points: (0, 3) and (2, 0)

c. 4x - 6y = 12
- If x = 0: -6y = 12, so y = -2
- If y = 0: 4x = 12, so x = 3
- Points: (0, -2) and (3, 0)

d. 3x - 2y = -24
- If x = 0: -2y = -24, so y = 12
- If y = 0: 3x = -24, so x = -8
- Points: (0, 12) and (-8, 0)

Based on the graph showing a line with negative slope passing through approximately (-3, 0) and (0, -2), option a matches best.

Final Answer: a. 8x + 12y = -24