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Factoring trinomials practice worksheet with ten algebraic expressions to factor completely.

A worksheet titled "Factoring Trinomials a > 1 Practice 2" with ten algebraic expressions to factor completely, including problems like 4x² + 4x - 35 and 5x² + 37x - 24.

A worksheet titled "Factoring Trinomials a > 1 Practice 2" with ten algebraic expressions to factor completely, including problems like 4x² + 4x - 35 and 5x² + 37x - 24.

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Show Answer Key & Explanations Step-by-step solution for: Factoring Polynomials Notes and Worksheets - Lindsay Bowden
Let's solve each trinomial by factoring completely. We'll use the AC method (also known as the "splitting the middle term" method) for trinomials where the leading coefficient $ a > 1 $. The general form is:

$$
ax^2 + bx + c
$$

We look for two numbers that:
- Multiply to $ a \cdot c $
- Add to $ b $

Then we split the middle term and factor by grouping.

---

1. $ 4x^2 + 4x - 35 $



- $ a = 4, b = 4, c = -35 $
- $ a \cdot c = 4 \cdot (-35) = -140 $
- Find two numbers that multiply to $-140$ and add to $4$:
Try: $ 14 $ and $-10$: $ 14 \cdot (-10) = -140 $, $ 14 + (-10) = 4 $

Split the middle term:
$$
4x^2 + 14x - 10x - 35
$$

Group:
$$
(4x^2 + 14x) + (-10x - 35)
= 2x(2x + 7) -5(2x + 7)
= (2x - 5)(2x + 7)
$$

Answer: $ (2x - 5)(2x + 7) $

---

2. $ 5x^2 + 37x - 24 $



- $ a = 5, b = 37, c = -24 $
- $ a \cdot c = 5 \cdot (-24) = -120 $
- Find two numbers that multiply to $-120$, add to $37$:
Try: $ 40 $ and $-3$: $ 40 \cdot (-3) = -120 $, $ 40 + (-3) = 37 $

Split:
$$
5x^2 + 40x - 3x - 24
$$

Group:
$$
(5x^2 + 40x) + (-3x - 24)
= 5x(x + 8) -3(x + 8)
= (5x - 3)(x + 8)
$$

Answer: $ (5x - 3)(x + 8) $

---

3. $ 3x^2 + 12x + 12 $



First, factor out GCF: $ 3 $
$$
3(x^2 + 4x + 4)
$$

Now factor the trinomial inside:
$$
x^2 + 4x + 4 = (x + 2)^2
$$

Answer: $ 3(x + 2)^2 $

---

4. $ 6x^2 - 44x + 14 $



Factor out GCF: $ 2 $
$$
2(3x^2 - 22x + 7)
$$

Now factor $ 3x^2 - 22x + 7 $:
- $ a = 3, b = -22, c = 7 $
- $ a \cdot c = 21 $
- Need two numbers that multiply to $21$, add to $-22$:
Try: $-21$ and $-1$: $-21 \cdot (-1) = 21$, $-21 + (-1) = -22$

Split:
$$
3x^2 - 21x - x + 7
$$

Group:
$$
(3x^2 - 21x) + (-x + 7)
= 3x(x - 7) -1(x - 7)
= (3x - 1)(x - 7)
$$

So overall:
$$
2(3x - 1)(x - 7)
$$

Answer: $ 2(3x - 1)(x - 7) $

---

5. $ 3x^2 - 23x - 36 $



- $ a = 3, b = -23, c = -36 $
- $ a \cdot c = 3 \cdot (-36) = -108 $
- Need two numbers that multiply to $-108$, add to $-23$:
Try: $-27$ and $4$: $-27 \cdot 4 = -108$, $-27 + 4 = -23$

Split:
$$
3x^2 - 27x + 4x - 36
$$

Group:
$$
(3x^2 - 27x) + (4x - 36)
= 3x(x - 9) + 4(x - 9)
= (3x + 4)(x - 9)
$$

Answer: $ (3x + 4)(x - 9) $

---

6. $ 2x^2 - 3x + 1 $



- $ a = 2, b = -3, c = 1 $
- $ a \cdot c = 2 $
- Need two numbers that multiply to $2$, add to $-3$:
Try: $-2$ and $-1$: $-2 \cdot (-1) = 2$, $-2 + (-1) = -3$

Split:
$$
2x^2 - 2x - x + 1
$$

Group:
$$
(2x^2 - 2x) + (-x + 1)
= 2x(x - 1) -1(x - 1)
= (2x - 1)(x - 1)
$$

Answer: $ (2x - 1)(x - 1) $

---

7. $ 20x^2 + 2x - 6 $



Factor out GCF: $ 2 $
$$
2(10x^2 + x - 3)
$$

Now factor $ 10x^2 + x - 3 $:
- $ a = 10, b = 1, c = -3 $
- $ a \cdot c = -30 $
- Need two numbers that multiply to $-30$, add to $1$:
Try: $6$ and $-5$: $6 \cdot (-5) = -30$, $6 + (-5) = 1$

Split:
$$
10x^2 + 6x - 5x - 3
$$

Group:
$$
(10x^2 + 6x) + (-5x - 3)
= 2x(5x + 3) -1(5x + 3)
= (2x - 1)(5x + 3)
$$

So overall:
$$
2(2x - 1)(5x + 3)
$$

Answer: $ 2(2x - 1)(5x + 3) $

---

8. $ 3x^2 + 25x + 42 $



- $ a = 3, b = 25, c = 42 $
- $ a \cdot c = 126 $
- Need two numbers that multiply to $126$, add to $25$:
Try: $18$ and $7$: $18 \cdot 7 = 126$, $18 + 7 = 25$

Split:
$$
3x^2 + 18x + 7x + 42
$$

Group:
$$
(3x^2 + 18x) + (7x + 42)
= 3x(x + 6) + 7(x + 6)
= (3x + 7)(x + 6)
$$

Answer: $ (3x + 7)(x + 6) $

---

9. $ 2x^2 - 3x - 20 $



- $ a = 2, b = -3, c = -20 $
- $ a \cdot c = -40 $
- Need two numbers that multiply to $-40$, add to $-3$:
Try: $-8$ and $5$: $-8 \cdot 5 = -40$, $-8 + 5 = -3$

Split:
$$
2x^2 - 8x + 5x - 20
$$

Group:
$$
(2x^2 - 8x) + (5x - 20)
= 2x(x - 4) + 5(x - 4)
= (2x + 5)(x - 4)
$$

Answer: $ (2x + 5)(x - 4) $

---

10. $ 35x^2 - 11x - 6 $



- $ a = 35, b = -11, c = -6 $
- $ a \cdot c = -210 $
- Need two numbers that multiply to $-210$, add to $-11$:
Try: $-21$ and $10$: $-21 \cdot 10 = -210$, $-21 + 10 = -11$

Split:
$$
35x^2 - 21x + 10x - 6
$$

Group:
$$
(35x^2 - 21x) + (10x - 6)
= 7x(5x - 3) + 2(5x - 3)
= (7x + 2)(5x - 3)
$$

Answer: $ (7x + 2)(5x - 3) $

---

Final Answers:



| Problem | Factored Form |
|--------|----------------|
| 1. $ 4x^2 + 4x - 35 $ | $ (2x - 5)(2x + 7) $ |
| 2. $ 5x^2 + 37x - 24 $ | $ (5x - 3)(x + 8) $ |
| 3. $ 3x^2 + 12x + 12 $ | $ 3(x + 2)^2 $ |
| 4. $ 6x^2 - 44x + 14 $ | $ 2(3x - 1)(x - 7) $ |
| 5. $ 3x^2 - 23x - 36 $ | $ (3x + 4)(x - 9) $ |
| 6. $ 2x^2 - 3x + 1 $ | $ (2x - 1)(x - 1) $ |
| 7. $ 20x^2 + 2x - 6 $ | $ 2(2x - 1)(5x + 3) $ |
| 8. $ 3x^2 + 25x + 42 $ | $ (3x + 7)(x + 6) $ |
| 9. $ 2x^2 - 3x - 20 $ | $ (2x + 5)(x - 4) $ |
| 10. $ 35x^2 - 11x - 6 $ | $ (7x + 2)(5x - 3) $ |

Let me know if you'd like these checked with multiplication or explained further!
Parent Tip: Review the logic above to help your child master the concept of algebra 1 factoring trinomials worksheet.
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