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Algebra worksheet focusing on adding and subtracting rational expressions, designed for practice in simplifying complex fractions with variables.

Worksheet for adding and subtracting rational expressions from Kuta Software - Infinite Algebra 2, featuring 14 algebra problems involving simplification of rational expressions with variables and fractions.

Worksheet for adding and subtracting rational expressions from Kuta Software - Infinite Algebra 2, featuring 14 algebra problems involving simplification of rational expressions with variables and fractions.

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Show Answer Key & Explanations Step-by-step solution for: SOLUTION: Adding and subtracting rational expressions - Studypool
Let's solve each of these adding and subtracting rational expressions problems step by step. The key idea is to:

1. Find a common denominator (if needed),
2. Rewrite each expression with the common denominator,
3. Combine the numerators,
4. Simplify the resulting expression (factor and cancel if possible).

---

1) $\frac{u - v}{8v} + \frac{6u - 3v}{8v}$



Same denominator: $8v$

Add numerators:
$$
\frac{(u - v) + (6u - 3v)}{8v} = \frac{u - v + 6u - 3v}{8v} = \frac{7u - 4v}{8v}
$$

Answer: $\boxed{\frac{7u - 4v}{8v}}$

---

2) $\frac{m - 3n}{6m^3n} - \frac{m + 3n}{6m^3n}$



Same denominator: $6m^3n$

Subtract numerators:
$$
\frac{(m - 3n) - (m + 3n)}{6m^3n} = \frac{m - 3n - m - 3n}{6m^3n} = \frac{-6n}{6m^3n}
$$

Simplify:
$$
\frac{-6n}{6m^3n} = \frac{-1}{m^3}
$$

Answer: $\boxed{-\frac{1}{m^3}}$

---

3) $\frac{5}{a^2 + 3a + 2} + \frac{5a + 1}{a^2 + 3a + 2}$



Same denominator: factor it first.

$a^2 + 3a + 2 = (a+1)(a+2)$

Now add:
$$
\frac{5 + (5a + 1)}{(a+1)(a+2)} = \frac{5a + 6}{(a+1)(a+2)}
$$

No further simplification.

Answer: $\boxed{\frac{5a + 6}{(a+1)(a+2)}}$

---

4) $\frac{5}{10n^2 + 16n + 6} + \frac{n - 6}{10n^2 + 16n + 6}$



Same denominator. Factor denominator:

$10n^2 + 16n + 6 = 2(5n^2 + 8n + 3)$

Try factoring: $5n^2 + 8n + 3 = (5n + 3)(n + 1)$

So denominator: $2(5n + 3)(n + 1)$

Now combine numerators:
$$
\frac{5 + (n - 6)}{10n^2 + 16n + 6} = \frac{n - 1}{10n^2 + 16n + 6}
$$

We can write:
$$
\frac{n - 1}{2(5n + 3)(n + 1)}
$$

No cancellation possible.

Answer: $\boxed{\frac{n - 1}{10n^2 + 16n + 6}}$ or $\boxed{\frac{n - 1}{2(5n + 3)(n + 1)}}$

---

5) $\frac{r + 6}{3r - 6} + \frac{r + 1}{3r - 6}$



Same denominator: $3r - 6 = 3(r - 2)$

Add numerators:
$$
\frac{(r + 6) + (r + 1)}{3r - 6} = \frac{2r + 7}{3(r - 2)}
$$

Answer: $\boxed{\frac{2r + 7}{3(r - 2)}}$

---

6) $\frac{x + 2}{2x^2 + 13x + 20} - \frac{x + 3}{2x^2 + 13x + 20}$



Same denominator.

Factor: $2x^2 + 13x + 20 = (2x + 5)(x + 4)$

Subtract numerators:
$$
\frac{(x + 2) - (x + 3)}{(2x + 5)(x + 4)} = \frac{x + 2 - x - 3}{(2x + 5)(x + 4)} = \frac{-1}{(2x + 5)(x + 4)}
$$

Answer: $\boxed{-\frac{1}{(2x + 5)(x + 4)}}$

---

7) $\frac{6}{x - 1} - \frac{5x}{4}$



Different denominators: $x - 1$ and $4$

LCM: $4(x - 1)$

Rewrite both:
$$
\frac{6}{x - 1} = \frac{6 \cdot 4}{4(x - 1)} = \frac{24}{4(x - 1)}
$$
$$
\frac{5x}{4} = \frac{5x(x - 1)}{4(x - 1)} = \frac{5x^2 - 5x}{4(x - 1)}
$$

Now subtract:
$$
\frac{24 - (5x^2 - 5x)}{4(x - 1)} = \frac{24 - 5x^2 + 5x}{4(x - 1)} = \frac{-5x^2 + 5x + 24}{4(x - 1)}
$$

Answer: $\boxed{\frac{-5x^2 + 5x + 24}{4(x - 1)}}$

---

8) $6 - \frac{x + 5}{(7x - 5)(x + 4)}$



Write 6 as a fraction with denominator $(7x - 5)(x + 4)$:
$$
6 = \frac{6(7x - 5)(x + 4)}{(7x - 5)(x + 4)}
$$

Now subtract:
$$
\frac{6(7x - 5)(x + 4) - (x + 5)}{(7x - 5)(x + 4)}
$$

First compute $6(7x - 5)(x + 4)$

Step-by-step:
- $(7x - 5)(x + 4) = 7x(x) + 7x(4) -5(x) -5(4) = 7x^2 + 28x - 5x - 20 = 7x^2 + 23x - 20$
- Multiply by 6: $6(7x^2 + 23x - 20) = 42x^2 + 138x - 120$

Now subtract $(x + 5)$:
$$
42x^2 + 138x - 120 - x - 5 = 42x^2 + 137x - 125
$$

So:
$$
\frac{42x^2 + 137x - 125}{(7x - 5)(x + 4)}
$$

Answer: $\boxed{\frac{42x^2 + 137x - 125}{(7x - 5)(x + 4)}}$

---

9) $\frac{3}{x + 7} + \frac{4}{x - 8}$



Different denominators: LCM = $(x + 7)(x - 8)$

Rewrite:
$$
\frac{3(x - 8)}{(x + 7)(x - 8)} + \frac{4(x + 7)}{(x + 7)(x - 8)} = \frac{3x - 24 + 4x + 28}{(x + 7)(x - 8)} = \frac{7x + 4}{(x + 7)(x - 8)}
$$

Answer: $\boxed{\frac{7x + 4}{(x + 7)(x - 8)}}$

---

10) $\frac{3}{4v^2 + 4v} - \frac{7}{2}$



Factor denominator: $4v^2 + 4v = 4v(v + 1)$

LCM: $4v(v + 1)$

Rewrite:
$$
\frac{3}{4v(v + 1)} - \frac{7}{2} = \frac{3}{4v(v + 1)} - \frac{7 \cdot 2v(v + 1)}{4v(v + 1)} = \frac{3 - 14v(v + 1)}{4v(v + 1)}
$$

Compute numerator:
$$
14v(v + 1) = 14v^2 + 14v
$$
$$
3 - (14v^2 + 14v) = -14v^2 - 14v + 3
$$

Answer: $\boxed{\frac{-14v^2 - 14v + 3}{4v(v + 1)}}$

---

11) $\frac{7}{3} - \frac{8}{12x - 8}$



Simplify second denominator: $12x - 8 = 4(3x - 2)$

So:
$$
\frac{7}{3} - \frac{8}{4(3x - 2)} = \frac{7}{3} - \frac{2}{3x - 2}
$$

LCM: $3(3x - 2)$

Rewrite:
$$
\frac{7(3x - 2)}{3(3x - 2)} - \frac{2 \cdot 3}{3(3x - 2)} = \frac{21x - 14 - 6}{3(3x - 2)} = \frac{21x - 20}{3(3x - 2)}
$$

Answer: $\boxed{\frac{21x - 20}{3(3x - 2)}}$

---

12) $\frac{5}{n + 5} + \frac{4n}{2n + 6}$



Simplify second term: $2n + 6 = 2(n + 3)$

So:
$$
\frac{5}{n + 5} + \frac{4n}{2(n + 3)} = \frac{5}{n + 5} + \frac{2n}{n + 3}
$$

LCM: $(n + 5)(n + 3)$

Rewrite:
$$
\frac{5(n + 3)}{(n + 5)(n + 3)} + \frac{2n(n + 5)}{(n + 5)(n + 3)} = \frac{5n + 15 + 2n^2 + 10n}{(n + 5)(n + 3)} = \frac{2n^2 + 15n + 15}{(n + 5)(n + 3)}
$$

Answer: $\boxed{\frac{2n^2 + 15n + 15}{(n + 5)(n + 3)}}$

---

13) $\frac{2x}{5x + 4} + \frac{6x}{2x + 3}$



Different denominators: LCM = $(5x + 4)(2x + 3)$

Rewrite:
$$
\frac{2x(2x + 3)}{(5x + 4)(2x + 3)} + \frac{6x(5x + 4)}{(5x + 4)(2x + 3)} = \frac{4x^2 + 6x + 30x^2 + 24x}{(5x + 4)(2x + 3)}
$$

Combine:
$$
(4x^2 + 30x^2) + (6x + 24x) = 34x^2 + 30x
$$

So:
$$
\frac{34x^2 + 30x}{(5x + 4)(2x + 3)} = \frac{2x(17x + 15)}{(5x + 4)(2x + 3)}
$$

Answer: $\boxed{\frac{2x(17x + 15)}{(5x + 4)(2x + 3)}}$

---

14) $\frac{2}{3x^2 + 12x} + \frac{8}{2x}$



Factor:
- $3x^2 + 12x = 3x(x + 4)$
- $2x = 2x$

LCM: $6x(x + 4)$

Rewrite:
$$
\frac{2}{3x(x + 4)} = \frac{2 \cdot 2}{6x(x + 4)} = \frac{4}{6x(x + 4)}
$$
$$
\frac{8}{2x} = \frac{8 \cdot 3(x + 4)}{6x(x + 4)} = \frac{24(x + 4)}{6x(x + 4)}
$$

Now add:
$$
\frac{4 + 24(x + 4)}{6x(x + 4)} = \frac{4 + 24x + 96}{6x(x + 4)} = \frac{24x + 100}{6x(x + 4)}
$$

Simplify:
Factor numerator: $4(6x + 25)$, denominator: $6x(x + 4)$

$$
= \frac{4(6x + 25)}{6x(x + 4)} = \frac{2(6x + 25)}{3x(x + 4)}
$$

Answer: $\boxed{\frac{2(6x + 25)}{3x(x + 4)}}$

---

Final Answers Summary:



| Problem | Answer |
|--------|--------|
| 1 | $\frac{7u - 4v}{8v}$ |
| 2 | $-\frac{1}{m^3}$ |
| 3 | $\frac{5a + 6}{(a+1)(a+2)}$ |
| 4 | $\frac{n - 1}{10n^2 + 16n + 6}$ |
| 5 | $\frac{2r + 7}{3(r - 2)}$ |
| 6 | $-\frac{1}{(2x + 5)(x + 4)}$ |
| 7 | $\frac{-5x^2 + 5x + 24}{4(x - 1)}$ |
| 8 | $\frac{42x^2 + 137x - 125}{(7x - 5)(x + 4)}$ |
| 9 | $\frac{7x + 4}{(x + 7)(x - 8)}$ |
| 10 | $\frac{-14v^2 - 14v + 3}{4v(v + 1)}$ |
| 11 | $\frac{21x - 20}{3(3x - 2)}$ |
| 12 | $\frac{2n^2 + 15n + 15}{(n + 5)(n + 3)}$ |
| 13 | $\frac{2x(17x + 15)}{(5x + 4)(2x + 3)}$ |
| 14 | $\frac{2(6x + 25)}{3x(x + 4)}$ |

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