Vertex Form of Parabolas - Kuta Software - Free Printable
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Step-by-step solution for: Vertex Form of Parabolas - Kuta Software
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Step-by-step solution for: Vertex Form of Parabolas - Kuta Software
Let's solve each problem by converting the given quadratic equations into vertex form. The vertex form of a parabola is:
$$
y = a(x - h)^2 + k
$$
where $(h, k)$ is the vertex of the parabola.
We’ll go through each problem one by one and complete the square (or simplify) to get it into vertex form.
---
Complete the square:
- Take half of 16: $ \frac{16}{2} = 8 $
- Square it: $ 8^2 = 64 $
- Add and subtract 64:
$$
y = x^2 + 16x + 64 - 64 + 71 = (x + 8)^2 + 7
$$
✔ Answer: $ y = (x + 8)^2 + 7 $
---
- Half of $-2$: $-1$, square: $1$
- Add and subtract 1:
$$
y = x^2 - 2x + 1 - 1 - 5 = (x - 1)^2 - 6
$$
✔ Answer: $ y = (x - 1)^2 - 6 $
---
Factor out $-1$ from the first two terms:
$$
y = -(x^2 + 14x) - 59
$$
- Half of 14: 7, square: 49
- Add and subtract 49 inside parentheses:
$$
y = -(x^2 + 14x + 49 - 49) - 59 = -( (x + 7)^2 - 49 ) - 59
$$
Distribute the negative:
$$
y = -(x + 7)^2 + 49 - 59 = -(x + 7)^2 - 10
$$
✔ Answer: $ y = -(x + 7)^2 - 10 $
---
Factor out 2 from first two terms:
$$
y = 2(x^2 + 18x) + 170
$$
- Half of 18: 9, square: 81
- Add and subtract 81 inside parentheses:
$$
y = 2(x^2 + 18x + 81 - 81) + 170 = 2( (x + 9)^2 - 81 ) + 170
$$
Distribute:
$$
y = 2(x + 9)^2 - 162 + 170 = 2(x + 9)^2 + 8
$$
✔ Answer: $ y = 2(x + 9)^2 + 8 $
---
- Half of $-12$: $-6$, square: 36
- Add and subtract 36:
$$
y = x^2 - 12x + 36 - 36 + 46 = (x - 6)^2 + 10
$$
✔ Answer: $ y = (x - 6)^2 + 10 $
---
- Half of 4: 2, square: 4
- Add and subtract 4:
$$
y = x^2 + 4x + 4 - 4 = (x + 2)^2 - 4
$$
✔ Answer: $ y = (x + 2)^2 - 4 $
---
- Half of $-6$: $-3$, square: 9
- Add and subtract 9:
$$
y = x^2 - 6x + 9 - 9 + 5 = (x - 3)^2 - 4
$$
✔ Answer: $ y = (x - 3)^2 - 4 $
---
First expand:
$$
y = x^2 + 9x + 20
$$
Now complete the square:
- Half of 9: $4.5$, square: $20.25$
- Add and subtract:
$$
y = x^2 + 9x + 20.25 - 20.25 + 20 = (x + 4.5)^2 - 0.25
$$
Or write as fractions:
- $4.5 = \frac{9}{2}$, $20.25 = \left(\frac{9}{2}\right)^2 = \frac{81}{4}$
So:
$$
y = \left(x + \frac{9}{2}\right)^2 - \frac{81}{4} + \frac{80}{4} = \left(x + \frac{9}{2}\right)^2 - \frac{1}{4}
$$
✔ Answer: $ y = \left(x + \frac{9}{2}\right)^2 - \frac{1}{4} $
---
Solve for $y$:
Multiply both sides by 2:
$$
y + 4 = 2(x - 7)^2
\Rightarrow y = 2(x - 7)^2 - 4
$$
✔ Answer: $ y = 2(x - 7)^2 - 4 $
---
Solve for $y$:
$$
y = -6x^2 - 12x - 13
$$
Factor out $-6$ from first two terms:
$$
y = -6(x^2 + 2x) - 13
$$
- Half of 2: 1, square: 1
- Add and subtract 1:
$$
y = -6(x^2 + 2x + 1 - 1) - 13 = -6((x + 1)^2 - 1) - 13
$$
Distribute:
$$
y = -6(x + 1)^2 + 6 - 13 = -6(x + 1)^2 - 7
$$
✔ Answer: $ y = -6(x + 1)^2 - 7 $
---
Solve for $y$:
$$
y = -162x - 731 - 9x^2
\Rightarrow y = -9x^2 - 162x - 731
$$
Factor out $-9$:
$$
y = -9(x^2 + 18x) - 731
$$
- Half of 18: 9, square: 81
- Add and subtract 81:
$$
y = -9(x^2 + 18x + 81 - 81) - 731 = -9((x + 9)^2 - 81) - 731
$$
Distribute:
$$
y = -9(x + 9)^2 + 729 - 731 = -9(x + 9)^2 - 2
$$
✔ Answer: $ y = -9(x + 9)^2 - 2 $
---
Solve for $y$:
$$
y = -x^2 + 12x - 40
$$
Factor out $-1$:
$$
y = -(x^2 - 12x) - 40
$$
- Half of $-12$: $-6$, square: 36
- Add and subtract 36:
$$
y = -(x^2 - 12x + 36 - 36) - 40 = -((x - 6)^2 - 36) - 40
$$
Distribute:
$$
y = -(x - 6)^2 + 36 - 40 = -(x - 6)^2 - 4
$$
✔ Answer: $ y = -(x - 6)^2 - 4 $
---
- Half of 10: 5, square: 25
- Add and subtract 25:
$$
y = x^2 + 10x + 25 - 25 + 33 = (x + 5)^2 + 8
$$
✔ Answer: $ y = (x + 5)^2 + 8 $
---
Solve for $y$:
$$
y = (x + 3)^2 - 6
$$
✔ Answer: $ y = (x + 3)^2 - 6 $
---
| Problem | Vertex Form |
|--------|-------------|
| 1 | $ y = (x + 8)^2 + 7 $ |
| 2 | $ y = (x - 1)^2 - 6 $ |
| 3 | $ y = -(x + 7)^2 - 10 $ |
| 4 | $ y = 2(x + 9)^2 + 8 $ |
| 5 | $ y = (x - 6)^2 + 10 $ |
| 6 | $ y = (x + 2)^2 - 4 $ |
| 7 | $ y = (x - 3)^2 - 4 $ |
| 8 | $ y = \left(x + \frac{9}{2}\right)^2 - \frac{1}{4} $ |
| 9 | $ y = 2(x - 7)^2 - 4 $ |
|10 | $ y = -6(x + 1)^2 - 7 $ |
|11 | $ y = -9(x + 9)^2 - 2 $ |
|12 | $ y = -(x - 6)^2 - 4 $ |
|13 | $ y = (x + 5)^2 + 8 $ |
|14 | $ y = (x + 3)^2 - 6 $ |
Let me know if you'd like these graphed or explained further!
$$
y = a(x - h)^2 + k
$$
where $(h, k)$ is the vertex of the parabola.
We’ll go through each problem one by one and complete the square (or simplify) to get it into vertex form.
---
1) $ y = x^2 + 16x + 71 $
Complete the square:
- Take half of 16: $ \frac{16}{2} = 8 $
- Square it: $ 8^2 = 64 $
- Add and subtract 64:
$$
y = x^2 + 16x + 64 - 64 + 71 = (x + 8)^2 + 7
$$
✔ Answer: $ y = (x + 8)^2 + 7 $
---
2) $ y = x^2 - 2x - 5 $
- Half of $-2$: $-1$, square: $1$
- Add and subtract 1:
$$
y = x^2 - 2x + 1 - 1 - 5 = (x - 1)^2 - 6
$$
✔ Answer: $ y = (x - 1)^2 - 6 $
---
3) $ y = -x^2 - 14x - 59 $
Factor out $-1$ from the first two terms:
$$
y = -(x^2 + 14x) - 59
$$
- Half of 14: 7, square: 49
- Add and subtract 49 inside parentheses:
$$
y = -(x^2 + 14x + 49 - 49) - 59 = -( (x + 7)^2 - 49 ) - 59
$$
Distribute the negative:
$$
y = -(x + 7)^2 + 49 - 59 = -(x + 7)^2 - 10
$$
✔ Answer: $ y = -(x + 7)^2 - 10 $
---
4) $ y = 2x^2 + 36x + 170 $
Factor out 2 from first two terms:
$$
y = 2(x^2 + 18x) + 170
$$
- Half of 18: 9, square: 81
- Add and subtract 81 inside parentheses:
$$
y = 2(x^2 + 18x + 81 - 81) + 170 = 2( (x + 9)^2 - 81 ) + 170
$$
Distribute:
$$
y = 2(x + 9)^2 - 162 + 170 = 2(x + 9)^2 + 8
$$
✔ Answer: $ y = 2(x + 9)^2 + 8 $
---
5) $ y = x^2 - 12x + 46 $
- Half of $-12$: $-6$, square: 36
- Add and subtract 36:
$$
y = x^2 - 12x + 36 - 36 + 46 = (x - 6)^2 + 10
$$
✔ Answer: $ y = (x - 6)^2 + 10 $
---
6) $ y = x^2 + 4x $
- Half of 4: 2, square: 4
- Add and subtract 4:
$$
y = x^2 + 4x + 4 - 4 = (x + 2)^2 - 4
$$
✔ Answer: $ y = (x + 2)^2 - 4 $
---
7) $ y = x^2 - 6x + 5 $
- Half of $-6$: $-3$, square: 9
- Add and subtract 9:
$$
y = x^2 - 6x + 9 - 9 + 5 = (x - 3)^2 - 4
$$
✔ Answer: $ y = (x - 3)^2 - 4 $
---
8) $ y = (x + 5)(x + 4) $
First expand:
$$
y = x^2 + 9x + 20
$$
Now complete the square:
- Half of 9: $4.5$, square: $20.25$
- Add and subtract:
$$
y = x^2 + 9x + 20.25 - 20.25 + 20 = (x + 4.5)^2 - 0.25
$$
Or write as fractions:
- $4.5 = \frac{9}{2}$, $20.25 = \left(\frac{9}{2}\right)^2 = \frac{81}{4}$
So:
$$
y = \left(x + \frac{9}{2}\right)^2 - \frac{81}{4} + \frac{80}{4} = \left(x + \frac{9}{2}\right)^2 - \frac{1}{4}
$$
✔ Answer: $ y = \left(x + \frac{9}{2}\right)^2 - \frac{1}{4} $
---
9) $ \frac{1}{2}(y + 4) = (x - 7)^2 $
Solve for $y$:
Multiply both sides by 2:
$$
y + 4 = 2(x - 7)^2
\Rightarrow y = 2(x - 7)^2 - 4
$$
✔ Answer: $ y = 2(x - 7)^2 - 4 $
---
10) $ 6x^2 + 12x + y + 13 = 0 $
Solve for $y$:
$$
y = -6x^2 - 12x - 13
$$
Factor out $-6$ from first two terms:
$$
y = -6(x^2 + 2x) - 13
$$
- Half of 2: 1, square: 1
- Add and subtract 1:
$$
y = -6(x^2 + 2x + 1 - 1) - 13 = -6((x + 1)^2 - 1) - 13
$$
Distribute:
$$
y = -6(x + 1)^2 + 6 - 13 = -6(x + 1)^2 - 7
$$
✔ Answer: $ y = -6(x + 1)^2 - 7 $
---
11) $ 162x + 731 = -y - 9x^2 $
Solve for $y$:
$$
y = -162x - 731 - 9x^2
\Rightarrow y = -9x^2 - 162x - 731
$$
Factor out $-9$:
$$
y = -9(x^2 + 18x) - 731
$$
- Half of 18: 9, square: 81
- Add and subtract 81:
$$
y = -9(x^2 + 18x + 81 - 81) - 731 = -9((x + 9)^2 - 81) - 731
$$
Distribute:
$$
y = -9(x + 9)^2 + 729 - 731 = -9(x + 9)^2 - 2
$$
✔ Answer: $ y = -9(x + 9)^2 - 2 $
---
12) $ x^2 - 12x + y + 40 = 0 $
Solve for $y$:
$$
y = -x^2 + 12x - 40
$$
Factor out $-1$:
$$
y = -(x^2 - 12x) - 40
$$
- Half of $-12$: $-6$, square: 36
- Add and subtract 36:
$$
y = -(x^2 - 12x + 36 - 36) - 40 = -((x - 6)^2 - 36) - 40
$$
Distribute:
$$
y = -(x - 6)^2 + 36 - 40 = -(x - 6)^2 - 4
$$
✔ Answer: $ y = -(x - 6)^2 - 4 $
---
13) $ y = x^2 + 10x + 33 $
- Half of 10: 5, square: 25
- Add and subtract 25:
$$
y = x^2 + 10x + 25 - 25 + 33 = (x + 5)^2 + 8
$$
✔ Answer: $ y = (x + 5)^2 + 8 $
---
14) $ y + 6 = (x + 3)^2 $
Solve for $y$:
$$
y = (x + 3)^2 - 6
$$
✔ Answer: $ y = (x + 3)^2 - 6 $
---
✔ Final Answers:
| Problem | Vertex Form |
|--------|-------------|
| 1 | $ y = (x + 8)^2 + 7 $ |
| 2 | $ y = (x - 1)^2 - 6 $ |
| 3 | $ y = -(x + 7)^2 - 10 $ |
| 4 | $ y = 2(x + 9)^2 + 8 $ |
| 5 | $ y = (x - 6)^2 + 10 $ |
| 6 | $ y = (x + 2)^2 - 4 $ |
| 7 | $ y = (x - 3)^2 - 4 $ |
| 8 | $ y = \left(x + \frac{9}{2}\right)^2 - \frac{1}{4} $ |
| 9 | $ y = 2(x - 7)^2 - 4 $ |
|10 | $ y = -6(x + 1)^2 - 7 $ |
|11 | $ y = -9(x + 9)^2 - 2 $ |
|12 | $ y = -(x - 6)^2 - 4 $ |
|13 | $ y = (x + 5)^2 + 8 $ |
|14 | $ y = (x + 3)^2 - 6 $ |
Let me know if you'd like these graphed or explained further!
Parent Tip: Review the logic above to help your child master the concept of algebra 2 parabola worksheet.