Grade 1 Algebra Worksheets | Printables | Free Worksheets - Free Printable

Problem Description:

The task involves solving a series of algebraic equations where either addition or subtraction is required to find the missing number in each equation. The goal is to determine what number should replace the blank (□) in each equation to make it true.

Solution Approach:

For each equation, we need to analyze whether addition or subtraction is needed based on the given numbers and the result. We will solve each equation step by step.

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Detailed Solutions:

#### A. \( 8 \, \square = 3 \)
- Here, we need to determine what number, when subtracted from 8, gives 3.
- Equation: \( 8 - x = 3 \)
- Solve for \( x \):
\[
x = 8 - 3 = 5
\]
- Answer: \( \boxed{5} \)

#### B. \( 9 \, \square = 10 \)
- Here, we need to determine what number, when added to 9, gives 10.
- Equation: \( 9 + x = 10 \)
- Solve for \( x \):
\[
x = 10 - 9 = 1
\]
- Answer: \( \boxed{1} \)

#### C. \( 2 \, \square = 8 \)
- Here, we need to determine what number, when added to 2, gives 8.
- Equation: \( 2 + x = 8 \)
- Solve for \( x \):
\[
x = 8 - 2 = 6
\]
- Answer: \( \boxed{6} \)

#### D. \( 40 \, \square = 36 \)
- Here, we need to determine what number, when subtracted from 40, gives 36.
- Equation: \( 40 - x = 36 \)
- Solve for \( x \):
\[
x = 40 - 36 = 4
\]
- Answer: \( \boxed{4} \)

#### E. \( 27 \, \square = 30 \)
- Here, we need to determine what number, when added to 27, gives 30.
- Equation: \( 27 + x = 30 \)
- Solve for \( x \):
\[
x = 30 - 27 = 3
\]
- Answer: \( \boxed{3} \)

#### F. \( 57 \, \square = 60 \)
- Here, we need to determine what number, when added to 57, gives 60.
- Equation: \( 57 + x = 60 \)
- Solve for \( x \):
\[
x = 60 - 57 = 3
\]
- Answer: \( \boxed{3} \)

#### G. \( 2 \, \square = 1 \)
- Here, we need to determine what number, when subtracted from 2, gives 1.
- Equation: \( 2 - x = 1 \)
- Solve for \( x \):
\[
x = 2 - 1 = 1
\]
- Answer: \( \boxed{1} \)

#### H. \( 14 \, \square = 20 \)
- Here, we need to determine what number, when added to 14, gives 20.
- Equation: \( 14 + x = 20 \)
- Solve for \( x \):
\[
x = 20 - 14 = 6
\]
- Answer: \( \boxed{6} \)

#### I. \( 38 \, \square = 33 \)
- Here, we need to determine what number, when subtracted from 38, gives 33.
- Equation: \( 38 - x = 33 \)
- Solve for \( x \):
\[
x = 38 - 33 = 5
\]
- Answer: \( \boxed{5} \)

#### J. \( 21 \, \square = 25 \)
- Here, we need to determine what number, when added to 21, gives 25.
- Equation: \( 21 + x = 25 \)
- Solve for \( x \):
\[
x = 25 - 21 = 4
\]
- Answer: \( \boxed{4} \)

#### K. \( 50 \, \square = 48 \)
- Here, we need to determine what number, when subtracted from 50, gives 48.
- Equation: \( 50 - x = 48 \)
- Solve for \( x \):
\[
x = 50 - 48 = 2
\]
- Answer: \( \boxed{2} \)

#### L. \( 41 \, \square = 47 \)
- Here, we need to determine what number, when added to 41, gives 47.
- Equation: \( 41 + x = 47 \)
- Solve for \( x \):
\[
x = 47 - 41 = 6
\]
- Answer: \( \boxed{6} \)

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Final Answers:

\[
\begin{aligned}
&\text{A. } \boxed{5}, \quad \text{B. } \boxed{1}, \quad \text{C. } \boxed{6}, \quad \text{D. } \boxed{4}, \quad \text{E. } \boxed{3}, \quad \text{F. } \boxed{3}, \\
&\text{G. } \boxed{1}, \quad \text{H. } \boxed{6}, \quad \text{I. } \boxed{5}, \quad \text{J. } \boxed{4}, \quad \text{K. } \boxed{2}, \quad \text{L. } \boxed{6}.
\end{aligned}
\]

\boxed{\text{Final Answers as above}}