Math practice worksheet featuring 72 one-step algebra equations for solving variables.
A worksheet with 72 algebraic equations to solve for the variable, arranged in four columns.
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Show Answer Key & Explanations
Step-by-step solution for: Worksheet solving basic algebra | Basic algebra, Basic algebra ...
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Show Answer Key & Explanations
Step-by-step solution for: Worksheet solving basic algebra | Basic algebra, Basic algebra ...
To solve for the variable \( y \) in each equation, we will isolate \( y \) on one side of the equation. Let's go through a few examples step by step to illustrate the process.
1. Simplify both sides of the equation if necessary.
2. Move all terms involving \( y \) to one side and all constant terms to the other side.
3. Combine like terms.
4. Solve for \( y \) by dividing both sides by the coefficient of \( y \).
#### Problem 1: \( 1y + 8 = 17 \)
1. Subtract 8 from both sides:
\[
1y + 8 - 8 = 17 - 8
\]
\[
1y = 9
\]
2. Since the coefficient of \( y \) is 1, \( y = 9 \).
#### Problem 2: \( 59 = 8y + 3 \)
1. Subtract 3 from both sides:
\[
59 - 3 = 8y + 3 - 3
\]
\[
56 = 8y
\]
2. Divide both sides by 8:
\[
\frac{56}{8} = \frac{8y}{8}
\]
\[
y = 7
\]
#### Problem 3: \( 54 = 9 + 9y \)
1. Subtract 9 from both sides:
\[
54 - 9 = 9 + 9y - 9
\]
\[
45 = 9y
\]
2. Divide both sides by 9:
\[
\frac{45}{9} = \frac{9y}{9}
\]
\[
y = 5
\]
#### Problem 4: \( 2 + 8y = 34 \)
1. Subtract 2 from both sides:
\[
2 + 8y - 2 = 34 - 2
\]
\[
8y = 32
\]
2. Divide both sides by 8:
\[
\frac{8y}{8} = \frac{32}{8}
\]
\[
y = 4
\]
#### Problem 5: \( 61 = 5 + 7y \)
1. Subtract 5 from both sides:
\[
61 - 5 = 5 + 7y - 5
\]
\[
56 = 7y
\]
2. Divide both sides by 7:
\[
\frac{56}{7} = \frac{7y}{7}
\]
\[
y = 8
\]
#### Problem 6: \( 5y + 7 = 47 \)
1. Subtract 7 from both sides:
\[
5y + 7 - 7 = 47 - 7
\]
\[
5y = 40
\]
2. Divide both sides by 5:
\[
\frac{5y}{5} = \frac{40}{5}
\]
\[
y = 8
\]
#### Problem 7: \( 9 = 8 + y \)
1. Subtract 8 from both sides:
\[
9 - 8 = 8 + y - 8
\]
\[
1 = y
\]
\[
y = 1
\]
#### Problem 8: \( 7 = 3y + 1 \)
1. Subtract 1 from both sides:
\[
7 - 1 = 3y + 1 - 1
\]
\[
6 = 3y
\]
2. Divide both sides by 3:
\[
\frac{6}{3} = \frac{3y}{3}
\]
\[
y = 2
\]
After solving all the problems using the same method, the solutions are:
\[
\boxed{
\begin{array}{ll}
1. y = 9 & 2. y = 7 \\
3. y = 5 & 4. y = 4 \\
5. y = 8 & 6. y = 8 \\
7. y = 1 & 8. y = 2 \\
9. y = 3 & 10. y = 3 \\
11. y = 4 & 12. y = 2 \\
13. y = 5 & 14. y = 8 \\
15. y = 8 & 16. y = 3 \\
17. y = 8 & 18. y = 2 \\
19. y = 5 & 20. y = 2 \\
21. y = 5 & 22. y = 1 \\
23. y = 9 & 24. y = 1 \\
25. y = 9 & 26. y = 4 \\
27. y = 7 & 28. y = 1 \\
29. y = 7 & 30. y = 4 \\
31. y = 3 & 32. y = 8 \\
33. y = 7 & 34. y = 3 \\
35. y = 1 & 36. y = 4 \\
37. y = 2 & 38. y = 9 \\
39. y = 5 & 40. y = 9 \\
41. y = 3 & 42. y = 9 \\
43. y = 2 & 44. y = 4 \\
45. y = 7 & 46. y = 8 \\
47. y = 4 & 48. y = 7 \\
49. y = 6 & 50. y = 1 \\
51. y = 4 & 52. y = 7 \\
53. y = 6 & 54. y = 7 \\
55. y = 5 & 56. y = 1 \\
57. y = 5 & 58. y = 6 \\
59. y = 9 & 60. y = 3 \\
61. y = 9 & 62. y = 2 \\
63. y = 7 & 64. y = 9 \\
65. y = 8 & 66. y = 7 \\
67. y = 6 & 68. y = 2 \\
69. y = 5 & 70. y = 5 \\
71. y = 4 & 72. y = 6 \\
\end{array}
}
\]
General Steps:
1. Simplify both sides of the equation if necessary.
2. Move all terms involving \( y \) to one side and all constant terms to the other side.
3. Combine like terms.
4. Solve for \( y \) by dividing both sides by the coefficient of \( y \).
Example Solutions:
#### Problem 1: \( 1y + 8 = 17 \)
1. Subtract 8 from both sides:
\[
1y + 8 - 8 = 17 - 8
\]
\[
1y = 9
\]
2. Since the coefficient of \( y \) is 1, \( y = 9 \).
#### Problem 2: \( 59 = 8y + 3 \)
1. Subtract 3 from both sides:
\[
59 - 3 = 8y + 3 - 3
\]
\[
56 = 8y
\]
2. Divide both sides by 8:
\[
\frac{56}{8} = \frac{8y}{8}
\]
\[
y = 7
\]
#### Problem 3: \( 54 = 9 + 9y \)
1. Subtract 9 from both sides:
\[
54 - 9 = 9 + 9y - 9
\]
\[
45 = 9y
\]
2. Divide both sides by 9:
\[
\frac{45}{9} = \frac{9y}{9}
\]
\[
y = 5
\]
#### Problem 4: \( 2 + 8y = 34 \)
1. Subtract 2 from both sides:
\[
2 + 8y - 2 = 34 - 2
\]
\[
8y = 32
\]
2. Divide both sides by 8:
\[
\frac{8y}{8} = \frac{32}{8}
\]
\[
y = 4
\]
Continuing this process for all problems:
#### Problem 5: \( 61 = 5 + 7y \)
1. Subtract 5 from both sides:
\[
61 - 5 = 5 + 7y - 5
\]
\[
56 = 7y
\]
2. Divide both sides by 7:
\[
\frac{56}{7} = \frac{7y}{7}
\]
\[
y = 8
\]
#### Problem 6: \( 5y + 7 = 47 \)
1. Subtract 7 from both sides:
\[
5y + 7 - 7 = 47 - 7
\]
\[
5y = 40
\]
2. Divide both sides by 5:
\[
\frac{5y}{5} = \frac{40}{5}
\]
\[
y = 8
\]
#### Problem 7: \( 9 = 8 + y \)
1. Subtract 8 from both sides:
\[
9 - 8 = 8 + y - 8
\]
\[
1 = y
\]
\[
y = 1
\]
#### Problem 8: \( 7 = 3y + 1 \)
1. Subtract 1 from both sides:
\[
7 - 1 = 3y + 1 - 1
\]
\[
6 = 3y
\]
2. Divide both sides by 3:
\[
\frac{6}{3} = \frac{3y}{3}
\]
\[
y = 2
\]
Final Answers:
After solving all the problems using the same method, the solutions are:
\[
\boxed{
\begin{array}{ll}
1. y = 9 & 2. y = 7 \\
3. y = 5 & 4. y = 4 \\
5. y = 8 & 6. y = 8 \\
7. y = 1 & 8. y = 2 \\
9. y = 3 & 10. y = 3 \\
11. y = 4 & 12. y = 2 \\
13. y = 5 & 14. y = 8 \\
15. y = 8 & 16. y = 3 \\
17. y = 8 & 18. y = 2 \\
19. y = 5 & 20. y = 2 \\
21. y = 5 & 22. y = 1 \\
23. y = 9 & 24. y = 1 \\
25. y = 9 & 26. y = 4 \\
27. y = 7 & 28. y = 1 \\
29. y = 7 & 30. y = 4 \\
31. y = 3 & 32. y = 8 \\
33. y = 7 & 34. y = 3 \\
35. y = 1 & 36. y = 4 \\
37. y = 2 & 38. y = 9 \\
39. y = 5 & 40. y = 9 \\
41. y = 3 & 42. y = 9 \\
43. y = 2 & 44. y = 4 \\
45. y = 7 & 46. y = 8 \\
47. y = 4 & 48. y = 7 \\
49. y = 6 & 50. y = 1 \\
51. y = 4 & 52. y = 7 \\
53. y = 6 & 54. y = 7 \\
55. y = 5 & 56. y = 1 \\
57. y = 5 & 58. y = 6 \\
59. y = 9 & 60. y = 3 \\
61. y = 9 & 62. y = 2 \\
63. y = 7 & 64. y = 9 \\
65. y = 8 & 66. y = 7 \\
67. y = 6 & 68. y = 2 \\
69. y = 5 & 70. y = 5 \\
71. y = 4 & 72. y = 6 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of algebra math sheets.