Polynomial Multiplication Worksheet - Free Printable
Educational worksheet: Polynomial Multiplication Worksheet. Download and print for classroom or home learning activities.
JPG
585×595
44.9 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #1593180
⭐
Show Answer Key & Explanations
Step-by-step solution for: Polynomial Multiplication Worksheet
▼
Show Answer Key & Explanations
Step-by-step solution for: Polynomial Multiplication Worksheet
Let's solve each of these polynomial multiplication problems step by step. We'll use the distributive property (also known as the FOIL method for binomials) to expand each product.
---
Use distributive property:
$$
= 2r(7r) + 2r(7) + 3(7r) + 3(7)
= 14r^2 + 14r + 21r + 21
= 14r^2 + 35r + 21
$$
✔ Answer: $14r^2 + 35r + 21$
---
$$
= 8b(b) + 8b(-5) + 6(b) + 6(-5)
= 8b^2 - 40b + 6b - 30
= 8b^2 - 34b - 30
$$
✔ Answer: $8b^2 - 34b - 30$
---
$$
= 7n(4n) + 7n(6) + 5(4n) + 5(6)
= 28n^2 + 42n + 20n + 30
= 28n^2 + 62n + 30
$$
✔ Answer: $28n^2 + 62n + 30$
---
$$
= 5x(6x) + 5x(3) + 8(6x) + 8(3)
= 30x^2 + 15x + 48x + 24
= 30x^2 + 63x + 24
$$
✔ Answer: $30x^2 + 63x + 24$
---
$$
= a(2a) + a(2) + (-7)(2a) + (-7)(2)
= 2a^2 + 2a - 14a - 14
= 2a^2 - 12a - 14
$$
✔ Answer: $2a^2 - 12a - 14$
---
Distribute each term in the first polynomial:
First: $4v(8v^2) = 32v^3$
$4v(-3v) = -12v^2$
$4v(-4) = -16v$
Second: $8(8v^2) = 64v^2$
$8(-3v) = -24v$
$8(-4) = -32$
Now combine:
$$
32v^3 -12v^2 -16v + 64v^2 -24v -32
= 32v^3 + ( -12v^2 + 64v^2 ) + ( -16v -24v ) -32
= 32v^3 + 52v^2 - 40v - 32
$$
✔ Answer: $32v^3 + 52v^2 - 40v - 32$
---
Distribute:
$x(5x^2) = 5x^3$
$x(-3x) = -3x^2$
$x(-5) = -5x$
$-7(5x^2) = -35x^2$
$-7(-3x) = 21x$
$-7(-5) = 35$
Combine:
$$
5x^3 -3x^2 -5x -35x^2 +21x +35
= 5x^3 + (-3x^2 -35x^2) + (-5x +21x) +35
= 5x^3 -38x^2 +16x +35
$$
✔ Answer: $5x^3 - 38x^2 + 16x + 35$
---
Distribute:
$6x(7x^2) = 42x^3$
$6x(x) = 6x^2$
$6x(-4) = -24x$
$-4(7x^2) = -28x^2$
$-4(x) = -4x$
$-4(-4) = 16$
Combine:
$$
42x^3 + 6x^2 -24x -28x^2 -4x +16
= 42x^3 + (6x^2 -28x^2) + (-24x -4x) +16
= 42x^3 -22x^2 -28x +16
$$
✔ Answer: $42x^3 - 22x^2 - 28x + 16$
---
Distribute:
$3n(3n^2) = 9n^3$
$3n(-8n) = -24n^2$
$3n(-5) = -15n$
$-2(3n^2) = -6n^2$
$-2(-8n) = 16n$
$-2(-5) = 10$
Combine:
$$
9n^3 -24n^2 -15n -6n^2 +16n +10
= 9n^3 + (-24n^2 -6n^2) + (-15n +16n) +10
= 9n^3 -30n^2 + n +10
$$
✔ Answer: $9n^3 - 30n^2 + n + 10$
---
Factor out 5 from first binomial: $5(k - 1)$, but we’ll just distribute directly.
$5k(k^2) = 5k^3$
$5k(-4k) = -20k^2$
$5k(-5) = -25k$
$-5(k^2) = -5k^2$
$-5(-4k) = 20k$
$-5(-5) = 25$
Combine:
$$
5k^3 -20k^2 -25k -5k^2 +20k +25
= 5k^3 + (-20k^2 -5k^2) + (-25k +20k) +25
= 5k^3 -25k^2 -5k +25
$$
✔ Answer: $5k^3 - 25k^2 - 5k + 25$
---
This is more complex — multiply each term in the first by each in the second.
We can factor both if possible, but let’s just expand:
Let’s do it term by term:
#### First: $2x^2(2x^2) = 4x^4$
$2x^2(-6x) = -12x^3$
$2x^2(-3) = -6x^2$
#### Second: $6x(2x^2) = 12x^3$
$6x(-6x) = -36x^2$
$6x(-3) = -18x$
#### Third: $-8(2x^2) = -16x^2$
$-8(-6x) = 48x$
$-8(-3) = 24$
Now sum all terms:
- $x^4$: $4x^4$
- $x^3$: $-12x^3 + 12x^3 = 0$
- $x^2$: $-6x^2 -36x^2 -16x^2 = -58x^2$
- $x$: $-18x + 48x = 30x$
- Constant: $24$
So:
$$
4x^4 - 58x^2 + 30x + 24
$$
✔ Answer: $4x^4 - 58x^2 + 30x + 24$
---
Again, distribute each term:
Let’s go term by term.
#### $2p^2(2p^2) = 4p^4$
$2p^2(-5p) = -10p^3$
$2p^2(-3) = -6p^2$
#### $-7p(2p^2) = -14p^3$
$-7p(-5p) = 35p^2$
$-7p(-3) = 21p$
#### $8(2p^2) = 16p^2$
$8(-5p) = -40p$
$8(-3) = -24$
Now combine:
- $p^4$: $4p^4$
- $p^3$: $-10p^3 -14p^3 = -24p^3$
- $p^2$: $-6p^2 +35p^2 +16p^2 = 45p^2$
- $p$: $21p -40p = -19p$
- Constant: $-24$
✔ Answer: $4p^4 - 24p^3 + 45p^2 - 19p - 24$
---
Multiply term by term.
#### $5n^2(4n^2) = 20n^4$
$5n^2(-6n) = -30n^3$
$5n^2(-2) = -10n^2$
#### $3n(4n^2) = 12n^3$
$3n(-6n) = -18n^2$
$3n(-2) = -6n$
#### $-8(4n^2) = -32n^2$
$-8(-6n) = 48n$
$-8(-2) = 16$
Now combine:
- $n^4$: $20n^4$
- $n^3$: $-30n^3 + 12n^3 = -18n^3$
- $n^2$: $-10n^2 -18n^2 -32n^2 = -60n^2$
- $n$: $-6n + 48n = 42n$
- Constant: $16$
✔ Answer: $20n^4 - 18n^3 - 60n^2 + 42n + 16$
---
Distribute:
#### $8m^2(2m^2) = 16m^4$
$8m^2(8m) = 64m^3$
$8m^2(4) = 32m^2$
#### $8m(2m^2) = 16m^3$
$8m(8m) = 64m^2$
$8m(4) = 32m$
#### $3(2m^2) = 6m^2$
$3(8m) = 24m$
$3(4) = 12$
Now combine:
- $m^4$: $16m^4$
- $m^3$: $64m^3 + 16m^3 = 80m^3$
- $m^2$: $32m^2 + 64m^2 + 6m^2 = 102m^2$
- $m$: $32m + 24m = 56m$
- Constant: $12$
✔ Answer: $16m^4 + 80m^3 + 102m^2 + 56m + 12$
---
Distribute:
#### $4x^2(6x^2) = 24x^4$
$4x^2(x) = 4x^3$
$4x^2(-7) = -28x^2$
#### $-7x(6x^2) = -42x^3$
$-7x(x) = -7x^2$
$-7x(-7) = 49x$
#### $-1(6x^2) = -6x^2$
$-1(x) = -x$
$-1(-7) = 7$
Now combine:
- $x^4$: $24x^4$
- $x^3$: $4x^3 - 42x^3 = -38x^3$
- $x^2$: $-28x^2 -7x^2 -6x^2 = -41x^2$
- $x$: $49x - x = 48x$
- Constant: $7$
✔ Answer: $24x^4 - 38x^3 - 41x^2 + 48x + 7$
---
Distribute:
#### $2r^2(5r^2) = 10r^4$
$2r^2(2r) = 4r^3$
$2r^2(-8) = -16r^2$
#### $5r(5r^2) = 25r^3$
$5r(2r) = 10r^2$
$5r(-8) = -40r$
#### $-1(5r^2) = -5r^2$
$-1(2r) = -2r$
$-1(-8) = 8$
Now combine:
- $r^4$: $10r^4$
- $r^3$: $4r^3 + 25r^3 = 29r^3$
- $r^2$: $-16r^2 + 10r^2 -5r^2 = -11r^2$
- $r$: $-40r -2r = -42r$
- Constant: $8$
✔ Answer: $10r^4 + 29r^3 - 11r^2 - 42r + 8$
---
This is a square of a trinomial. Use:
$$
(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc
$$
Here: $a = b^2$, $b = -4b$, $c = 6$
So:
$$
= (b^2)^2 + (-4b)^2 + (6)^2 + 2(b^2)(-4b) + 2(b^2)(6) + 2(-4b)(6)
$$
Calculate:
- $b^4$
- $16b^2$
- $36$
- $2(b^2)(-4b) = -8b^3$
- $2(b^2)(6) = 12b^2$
- $2(-4b)(6) = -48b$
Now combine:
$$
b^4 -8b^3 + (16b^2 + 12b^2) -48b + 36
= b^4 -8b^3 + 28b^2 -48b + 36
$$
✔ Answer: $b^4 - 8b^3 + 28b^2 - 48b + 36$
---
Distribute:
#### $7n^2(7n^2) = 49n^4$
$7n^2(n) = 7n^3$
$7n^2(-5) = -35n^2$
#### $8n(7n^2) = 56n^3$
$8n(n) = 8n^2$
$8n(-5) = -40n$
#### $7(7n^2) = 49n^2$
$7(n) = 7n$
$7(-5) = -35$
Now combine:
- $n^4$: $49n^4$
- $n^3$: $7n^3 + 56n^3 = 63n^3$
- $n^2$: $-35n^2 + 8n^2 + 49n^2 = 22n^2$
- $n$: $-40n + 7n = -33n$
- Constant: $-35$
✔ Answer: $49n^4 + 63n^3 + 22n^2 - 33n - 35$
---
| Problem | Answer |
|--------|--------|
| 1 | $14r^2 + 35r + 21$ |
| 2 | $8b^2 - 34b - 30$ |
| 3 | $28n^2 + 62n + 30$ |
| 4 | $30x^2 + 63x + 24$ |
| 5 | $2a^2 - 12a - 14$ |
| 6 | $32v^3 + 52v^2 - 40v - 32$ |
| 7 | $5x^3 - 38x^2 + 16x + 35$ |
| 8 | $42x^3 - 22x^2 - 28x + 16$ |
| 9 | $9n^3 - 30n^2 + n + 10$ |
| 10 | $5k^3 - 25k^2 - 5k + 25$ |
| 11 | $4x^4 - 58x^2 + 30x + 24$ |
| 12 | $4p^4 - 24p^3 + 45p^2 - 19p - 24$ |
| 13 | $20n^4 - 18n^3 - 60n^2 + 42n + 16$ |
| 14 | $16m^4 + 80m^3 + 102m^2 + 56m + 12$ |
| 15 | $24x^4 - 38x^3 - 41x^2 + 48x + 7$ |
| 16 | $10r^4 + 29r^3 - 11r^2 - 42r + 8$ |
| 17 | $b^4 - 8b^3 + 28b^2 - 48b + 36$ |
| 18 | $49n^4 + 63n^3 + 22n^2 - 33n - 35$ |
Let me know if you'd like this formatted as a printable worksheet or want explanations for any specific problem!
---
1) $(2r + 3)(7r + 7)$
Use distributive property:
$$
= 2r(7r) + 2r(7) + 3(7r) + 3(7)
= 14r^2 + 14r + 21r + 21
= 14r^2 + 35r + 21
$$
✔ Answer: $14r^2 + 35r + 21$
---
2) $(8b + 6)(b - 5)$
$$
= 8b(b) + 8b(-5) + 6(b) + 6(-5)
= 8b^2 - 40b + 6b - 30
= 8b^2 - 34b - 30
$$
✔ Answer: $8b^2 - 34b - 30$
---
3) $(7n + 5)(4n + 6)$
$$
= 7n(4n) + 7n(6) + 5(4n) + 5(6)
= 28n^2 + 42n + 20n + 30
= 28n^2 + 62n + 30
$$
✔ Answer: $28n^2 + 62n + 30$
---
4) $(5x + 8)(6x + 3)$
$$
= 5x(6x) + 5x(3) + 8(6x) + 8(3)
= 30x^2 + 15x + 48x + 24
= 30x^2 + 63x + 24
$$
✔ Answer: $30x^2 + 63x + 24$
---
5) $(a - 7)(2a + 2)$
$$
= a(2a) + a(2) + (-7)(2a) + (-7)(2)
= 2a^2 + 2a - 14a - 14
= 2a^2 - 12a - 14
$$
✔ Answer: $2a^2 - 12a - 14$
---
6) $(4v + 8)(8v^2 - 3v - 4)$
Distribute each term in the first polynomial:
First: $4v(8v^2) = 32v^3$
$4v(-3v) = -12v^2$
$4v(-4) = -16v$
Second: $8(8v^2) = 64v^2$
$8(-3v) = -24v$
$8(-4) = -32$
Now combine:
$$
32v^3 -12v^2 -16v + 64v^2 -24v -32
= 32v^3 + ( -12v^2 + 64v^2 ) + ( -16v -24v ) -32
= 32v^3 + 52v^2 - 40v - 32
$$
✔ Answer: $32v^3 + 52v^2 - 40v - 32$
---
7) $(x - 7)(5x^2 - 3x - 5)$
Distribute:
$x(5x^2) = 5x^3$
$x(-3x) = -3x^2$
$x(-5) = -5x$
$-7(5x^2) = -35x^2$
$-7(-3x) = 21x$
$-7(-5) = 35$
Combine:
$$
5x^3 -3x^2 -5x -35x^2 +21x +35
= 5x^3 + (-3x^2 -35x^2) + (-5x +21x) +35
= 5x^3 -38x^2 +16x +35
$$
✔ Answer: $5x^3 - 38x^2 + 16x + 35$
---
8) $(6x - 4)(7x^2 + x - 4)$
Distribute:
$6x(7x^2) = 42x^3$
$6x(x) = 6x^2$
$6x(-4) = -24x$
$-4(7x^2) = -28x^2$
$-4(x) = -4x$
$-4(-4) = 16$
Combine:
$$
42x^3 + 6x^2 -24x -28x^2 -4x +16
= 42x^3 + (6x^2 -28x^2) + (-24x -4x) +16
= 42x^3 -22x^2 -28x +16
$$
✔ Answer: $42x^3 - 22x^2 - 28x + 16$
---
9) $(3n - 2)(3n^2 - 8n - 5)$
Distribute:
$3n(3n^2) = 9n^3$
$3n(-8n) = -24n^2$
$3n(-5) = -15n$
$-2(3n^2) = -6n^2$
$-2(-8n) = 16n$
$-2(-5) = 10$
Combine:
$$
9n^3 -24n^2 -15n -6n^2 +16n +10
= 9n^3 + (-24n^2 -6n^2) + (-15n +16n) +10
= 9n^3 -30n^2 + n +10
$$
✔ Answer: $9n^3 - 30n^2 + n + 10$
---
10) $(5k - 5)(k^2 - 4k - 5)$
Factor out 5 from first binomial: $5(k - 1)$, but we’ll just distribute directly.
$5k(k^2) = 5k^3$
$5k(-4k) = -20k^2$
$5k(-5) = -25k$
$-5(k^2) = -5k^2$
$-5(-4k) = 20k$
$-5(-5) = 25$
Combine:
$$
5k^3 -20k^2 -25k -5k^2 +20k +25
= 5k^3 + (-20k^2 -5k^2) + (-25k +20k) +25
= 5k^3 -25k^2 -5k +25
$$
✔ Answer: $5k^3 - 25k^2 - 5k + 25$
---
11) $(2x^2 + 6x - 8)(2x^2 - 6x - 3)$
This is more complex — multiply each term in the first by each in the second.
We can factor both if possible, but let’s just expand:
Let’s do it term by term:
#### First: $2x^2(2x^2) = 4x^4$
$2x^2(-6x) = -12x^3$
$2x^2(-3) = -6x^2$
#### Second: $6x(2x^2) = 12x^3$
$6x(-6x) = -36x^2$
$6x(-3) = -18x$
#### Third: $-8(2x^2) = -16x^2$
$-8(-6x) = 48x$
$-8(-3) = 24$
Now sum all terms:
- $x^4$: $4x^4$
- $x^3$: $-12x^3 + 12x^3 = 0$
- $x^2$: $-6x^2 -36x^2 -16x^2 = -58x^2$
- $x$: $-18x + 48x = 30x$
- Constant: $24$
So:
$$
4x^4 - 58x^2 + 30x + 24
$$
✔ Answer: $4x^4 - 58x^2 + 30x + 24$
---
12) $(2p^2 - 7p + 8)(2p^2 - 5p - 3)$
Again, distribute each term:
Let’s go term by term.
#### $2p^2(2p^2) = 4p^4$
$2p^2(-5p) = -10p^3$
$2p^2(-3) = -6p^2$
#### $-7p(2p^2) = -14p^3$
$-7p(-5p) = 35p^2$
$-7p(-3) = 21p$
#### $8(2p^2) = 16p^2$
$8(-5p) = -40p$
$8(-3) = -24$
Now combine:
- $p^4$: $4p^4$
- $p^3$: $-10p^3 -14p^3 = -24p^3$
- $p^2$: $-6p^2 +35p^2 +16p^2 = 45p^2$
- $p$: $21p -40p = -19p$
- Constant: $-24$
✔ Answer: $4p^4 - 24p^3 + 45p^2 - 19p - 24$
---
13) $(5n^2 + 3n - 8)(4n^2 - 6n - 2)$
Multiply term by term.
#### $5n^2(4n^2) = 20n^4$
$5n^2(-6n) = -30n^3$
$5n^2(-2) = -10n^2$
#### $3n(4n^2) = 12n^3$
$3n(-6n) = -18n^2$
$3n(-2) = -6n$
#### $-8(4n^2) = -32n^2$
$-8(-6n) = 48n$
$-8(-2) = 16$
Now combine:
- $n^4$: $20n^4$
- $n^3$: $-30n^3 + 12n^3 = -18n^3$
- $n^2$: $-10n^2 -18n^2 -32n^2 = -60n^2$
- $n$: $-6n + 48n = 42n$
- Constant: $16$
✔ Answer: $20n^4 - 18n^3 - 60n^2 + 42n + 16$
---
14) $(8m^2 + 8m + 3)(2m^2 + 8m + 4)$
Distribute:
#### $8m^2(2m^2) = 16m^4$
$8m^2(8m) = 64m^3$
$8m^2(4) = 32m^2$
#### $8m(2m^2) = 16m^3$
$8m(8m) = 64m^2$
$8m(4) = 32m$
#### $3(2m^2) = 6m^2$
$3(8m) = 24m$
$3(4) = 12$
Now combine:
- $m^4$: $16m^4$
- $m^3$: $64m^3 + 16m^3 = 80m^3$
- $m^2$: $32m^2 + 64m^2 + 6m^2 = 102m^2$
- $m$: $32m + 24m = 56m$
- Constant: $12$
✔ Answer: $16m^4 + 80m^3 + 102m^2 + 56m + 12$
---
15) $(4x^2 - 7x - 1)(6x^2 + x - 7)$
Distribute:
#### $4x^2(6x^2) = 24x^4$
$4x^2(x) = 4x^3$
$4x^2(-7) = -28x^2$
#### $-7x(6x^2) = -42x^3$
$-7x(x) = -7x^2$
$-7x(-7) = 49x$
#### $-1(6x^2) = -6x^2$
$-1(x) = -x$
$-1(-7) = 7$
Now combine:
- $x^4$: $24x^4$
- $x^3$: $4x^3 - 42x^3 = -38x^3$
- $x^2$: $-28x^2 -7x^2 -6x^2 = -41x^2$
- $x$: $49x - x = 48x$
- Constant: $7$
✔ Answer: $24x^4 - 38x^3 - 41x^2 + 48x + 7$
---
16) $(2r^2 + 5r - 1)(5r^2 + 2r - 8)$
Distribute:
#### $2r^2(5r^2) = 10r^4$
$2r^2(2r) = 4r^3$
$2r^2(-8) = -16r^2$
#### $5r(5r^2) = 25r^3$
$5r(2r) = 10r^2$
$5r(-8) = -40r$
#### $-1(5r^2) = -5r^2$
$-1(2r) = -2r$
$-1(-8) = 8$
Now combine:
- $r^4$: $10r^4$
- $r^3$: $4r^3 + 25r^3 = 29r^3$
- $r^2$: $-16r^2 + 10r^2 -5r^2 = -11r^2$
- $r$: $-40r -2r = -42r$
- Constant: $8$
✔ Answer: $10r^4 + 29r^3 - 11r^2 - 42r + 8$
---
17) $(b^2 - 4b + 6)^2$
This is a square of a trinomial. Use:
$$
(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc
$$
Here: $a = b^2$, $b = -4b$, $c = 6$
So:
$$
= (b^2)^2 + (-4b)^2 + (6)^2 + 2(b^2)(-4b) + 2(b^2)(6) + 2(-4b)(6)
$$
Calculate:
- $b^4$
- $16b^2$
- $36$
- $2(b^2)(-4b) = -8b^3$
- $2(b^2)(6) = 12b^2$
- $2(-4b)(6) = -48b$
Now combine:
$$
b^4 -8b^3 + (16b^2 + 12b^2) -48b + 36
= b^4 -8b^3 + 28b^2 -48b + 36
$$
✔ Answer: $b^4 - 8b^3 + 28b^2 - 48b + 36$
---
18) $(7n^2 + 8n + 7)(7n^2 + n - 5)$
Distribute:
#### $7n^2(7n^2) = 49n^4$
$7n^2(n) = 7n^3$
$7n^2(-5) = -35n^2$
#### $8n(7n^2) = 56n^3$
$8n(n) = 8n^2$
$8n(-5) = -40n$
#### $7(7n^2) = 49n^2$
$7(n) = 7n$
$7(-5) = -35$
Now combine:
- $n^4$: $49n^4$
- $n^3$: $7n^3 + 56n^3 = 63n^3$
- $n^2$: $-35n^2 + 8n^2 + 49n^2 = 22n^2$
- $n$: $-40n + 7n = -33n$
- Constant: $-35$
✔ Answer: $49n^4 + 63n^3 + 22n^2 - 33n - 35$
---
✔ Final Answers Summary:
| Problem | Answer |
|--------|--------|
| 1 | $14r^2 + 35r + 21$ |
| 2 | $8b^2 - 34b - 30$ |
| 3 | $28n^2 + 62n + 30$ |
| 4 | $30x^2 + 63x + 24$ |
| 5 | $2a^2 - 12a - 14$ |
| 6 | $32v^3 + 52v^2 - 40v - 32$ |
| 7 | $5x^3 - 38x^2 + 16x + 35$ |
| 8 | $42x^3 - 22x^2 - 28x + 16$ |
| 9 | $9n^3 - 30n^2 + n + 10$ |
| 10 | $5k^3 - 25k^2 - 5k + 25$ |
| 11 | $4x^4 - 58x^2 + 30x + 24$ |
| 12 | $4p^4 - 24p^3 + 45p^2 - 19p - 24$ |
| 13 | $20n^4 - 18n^3 - 60n^2 + 42n + 16$ |
| 14 | $16m^4 + 80m^3 + 102m^2 + 56m + 12$ |
| 15 | $24x^4 - 38x^3 - 41x^2 + 48x + 7$ |
| 16 | $10r^4 + 29r^3 - 11r^2 - 42r + 8$ |
| 17 | $b^4 - 8b^3 + 28b^2 - 48b + 36$ |
| 18 | $49n^4 + 63n^3 + 22n^2 - 33n - 35$ |
Let me know if you'd like this formatted as a printable worksheet or want explanations for any specific problem!
Parent Tip: Review the logic above to help your child master the concept of algebra multiplication worksheet.