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Polynomial Multiplication Worksheet - Free Printable

Polynomial Multiplication Worksheet

Educational worksheet: Polynomial Multiplication Worksheet. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Polynomial Multiplication Worksheet
Let's solve each of these polynomial multiplication problems step by step. We'll use the distributive property (also known as the FOIL method for binomials) to expand each product.

---

1) $(2r + 3)(7r + 7)$



Use distributive property:
$$
= 2r(7r) + 2r(7) + 3(7r) + 3(7)
= 14r^2 + 14r + 21r + 21
= 14r^2 + 35r + 21
$$

Answer: $14r^2 + 35r + 21$

---

2) $(8b + 6)(b - 5)$



$$
= 8b(b) + 8b(-5) + 6(b) + 6(-5)
= 8b^2 - 40b + 6b - 30
= 8b^2 - 34b - 30
$$

Answer: $8b^2 - 34b - 30$

---

3) $(7n + 5)(4n + 6)$



$$
= 7n(4n) + 7n(6) + 5(4n) + 5(6)
= 28n^2 + 42n + 20n + 30
= 28n^2 + 62n + 30
$$

Answer: $28n^2 + 62n + 30$

---

4) $(5x + 8)(6x + 3)$



$$
= 5x(6x) + 5x(3) + 8(6x) + 8(3)
= 30x^2 + 15x + 48x + 24
= 30x^2 + 63x + 24
$$

Answer: $30x^2 + 63x + 24$

---

5) $(a - 7)(2a + 2)$



$$
= a(2a) + a(2) + (-7)(2a) + (-7)(2)
= 2a^2 + 2a - 14a - 14
= 2a^2 - 12a - 14
$$

Answer: $2a^2 - 12a - 14$

---

6) $(4v + 8)(8v^2 - 3v - 4)$



Distribute each term in the first polynomial:

First: $4v(8v^2) = 32v^3$
$4v(-3v) = -12v^2$
$4v(-4) = -16v$

Second: $8(8v^2) = 64v^2$
$8(-3v) = -24v$
$8(-4) = -32$

Now combine:
$$
32v^3 -12v^2 -16v + 64v^2 -24v -32
= 32v^3 + ( -12v^2 + 64v^2 ) + ( -16v -24v ) -32
= 32v^3 + 52v^2 - 40v - 32
$$

Answer: $32v^3 + 52v^2 - 40v - 32$

---

7) $(x - 7)(5x^2 - 3x - 5)$



Distribute:

$x(5x^2) = 5x^3$
$x(-3x) = -3x^2$
$x(-5) = -5x$

$-7(5x^2) = -35x^2$
$-7(-3x) = 21x$
$-7(-5) = 35$

Combine:
$$
5x^3 -3x^2 -5x -35x^2 +21x +35
= 5x^3 + (-3x^2 -35x^2) + (-5x +21x) +35
= 5x^3 -38x^2 +16x +35
$$

Answer: $5x^3 - 38x^2 + 16x + 35$

---

8) $(6x - 4)(7x^2 + x - 4)$



Distribute:

$6x(7x^2) = 42x^3$
$6x(x) = 6x^2$
$6x(-4) = -24x$

$-4(7x^2) = -28x^2$
$-4(x) = -4x$
$-4(-4) = 16$

Combine:
$$
42x^3 + 6x^2 -24x -28x^2 -4x +16
= 42x^3 + (6x^2 -28x^2) + (-24x -4x) +16
= 42x^3 -22x^2 -28x +16
$$

Answer: $42x^3 - 22x^2 - 28x + 16$

---

9) $(3n - 2)(3n^2 - 8n - 5)$



Distribute:

$3n(3n^2) = 9n^3$
$3n(-8n) = -24n^2$
$3n(-5) = -15n$

$-2(3n^2) = -6n^2$
$-2(-8n) = 16n$
$-2(-5) = 10$

Combine:
$$
9n^3 -24n^2 -15n -6n^2 +16n +10
= 9n^3 + (-24n^2 -6n^2) + (-15n +16n) +10
= 9n^3 -30n^2 + n +10
$$

Answer: $9n^3 - 30n^2 + n + 10$

---

10) $(5k - 5)(k^2 - 4k - 5)$



Factor out 5 from first binomial: $5(k - 1)$, but we’ll just distribute directly.

$5k(k^2) = 5k^3$
$5k(-4k) = -20k^2$
$5k(-5) = -25k$

$-5(k^2) = -5k^2$
$-5(-4k) = 20k$
$-5(-5) = 25$

Combine:
$$
5k^3 -20k^2 -25k -5k^2 +20k +25
= 5k^3 + (-20k^2 -5k^2) + (-25k +20k) +25
= 5k^3 -25k^2 -5k +25
$$

Answer: $5k^3 - 25k^2 - 5k + 25$

---

11) $(2x^2 + 6x - 8)(2x^2 - 6x - 3)$



This is more complex — multiply each term in the first by each in the second.

We can factor both if possible, but let’s just expand:

Let’s do it term by term:

#### First: $2x^2(2x^2) = 4x^4$
$2x^2(-6x) = -12x^3$
$2x^2(-3) = -6x^2$

#### Second: $6x(2x^2) = 12x^3$
$6x(-6x) = -36x^2$
$6x(-3) = -18x$

#### Third: $-8(2x^2) = -16x^2$
$-8(-6x) = 48x$
$-8(-3) = 24$

Now sum all terms:

- $x^4$: $4x^4$
- $x^3$: $-12x^3 + 12x^3 = 0$
- $x^2$: $-6x^2 -36x^2 -16x^2 = -58x^2$
- $x$: $-18x + 48x = 30x$
- Constant: $24$

So:
$$
4x^4 - 58x^2 + 30x + 24
$$

Answer: $4x^4 - 58x^2 + 30x + 24$

---

12) $(2p^2 - 7p + 8)(2p^2 - 5p - 3)$



Again, distribute each term:

Let’s go term by term.

#### $2p^2(2p^2) = 4p^4$
$2p^2(-5p) = -10p^3$
$2p^2(-3) = -6p^2$

#### $-7p(2p^2) = -14p^3$
$-7p(-5p) = 35p^2$
$-7p(-3) = 21p$

#### $8(2p^2) = 16p^2$
$8(-5p) = -40p$
$8(-3) = -24$

Now combine:

- $p^4$: $4p^4$
- $p^3$: $-10p^3 -14p^3 = -24p^3$
- $p^2$: $-6p^2 +35p^2 +16p^2 = 45p^2$
- $p$: $21p -40p = -19p$
- Constant: $-24$

Answer: $4p^4 - 24p^3 + 45p^2 - 19p - 24$

---

13) $(5n^2 + 3n - 8)(4n^2 - 6n - 2)$



Multiply term by term.

#### $5n^2(4n^2) = 20n^4$
$5n^2(-6n) = -30n^3$
$5n^2(-2) = -10n^2$

#### $3n(4n^2) = 12n^3$
$3n(-6n) = -18n^2$
$3n(-2) = -6n$

#### $-8(4n^2) = -32n^2$
$-8(-6n) = 48n$
$-8(-2) = 16$

Now combine:

- $n^4$: $20n^4$
- $n^3$: $-30n^3 + 12n^3 = -18n^3$
- $n^2$: $-10n^2 -18n^2 -32n^2 = -60n^2$
- $n$: $-6n + 48n = 42n$
- Constant: $16$

Answer: $20n^4 - 18n^3 - 60n^2 + 42n + 16$

---

14) $(8m^2 + 8m + 3)(2m^2 + 8m + 4)$



Distribute:

#### $8m^2(2m^2) = 16m^4$
$8m^2(8m) = 64m^3$
$8m^2(4) = 32m^2$

#### $8m(2m^2) = 16m^3$
$8m(8m) = 64m^2$
$8m(4) = 32m$

#### $3(2m^2) = 6m^2$
$3(8m) = 24m$
$3(4) = 12$

Now combine:

- $m^4$: $16m^4$
- $m^3$: $64m^3 + 16m^3 = 80m^3$
- $m^2$: $32m^2 + 64m^2 + 6m^2 = 102m^2$
- $m$: $32m + 24m = 56m$
- Constant: $12$

Answer: $16m^4 + 80m^3 + 102m^2 + 56m + 12$

---

15) $(4x^2 - 7x - 1)(6x^2 + x - 7)$



Distribute:

#### $4x^2(6x^2) = 24x^4$
$4x^2(x) = 4x^3$
$4x^2(-7) = -28x^2$

#### $-7x(6x^2) = -42x^3$
$-7x(x) = -7x^2$
$-7x(-7) = 49x$

#### $-1(6x^2) = -6x^2$
$-1(x) = -x$
$-1(-7) = 7$

Now combine:

- $x^4$: $24x^4$
- $x^3$: $4x^3 - 42x^3 = -38x^3$
- $x^2$: $-28x^2 -7x^2 -6x^2 = -41x^2$
- $x$: $49x - x = 48x$
- Constant: $7$

Answer: $24x^4 - 38x^3 - 41x^2 + 48x + 7$

---

16) $(2r^2 + 5r - 1)(5r^2 + 2r - 8)$



Distribute:

#### $2r^2(5r^2) = 10r^4$
$2r^2(2r) = 4r^3$
$2r^2(-8) = -16r^2$

#### $5r(5r^2) = 25r^3$
$5r(2r) = 10r^2$
$5r(-8) = -40r$

#### $-1(5r^2) = -5r^2$
$-1(2r) = -2r$
$-1(-8) = 8$

Now combine:

- $r^4$: $10r^4$
- $r^3$: $4r^3 + 25r^3 = 29r^3$
- $r^2$: $-16r^2 + 10r^2 -5r^2 = -11r^2$
- $r$: $-40r -2r = -42r$
- Constant: $8$

Answer: $10r^4 + 29r^3 - 11r^2 - 42r + 8$

---

17) $(b^2 - 4b + 6)^2$



This is a square of a trinomial. Use:
$$
(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc
$$
Here: $a = b^2$, $b = -4b$, $c = 6$

So:
$$
= (b^2)^2 + (-4b)^2 + (6)^2 + 2(b^2)(-4b) + 2(b^2)(6) + 2(-4b)(6)
$$

Calculate:
- $b^4$
- $16b^2$
- $36$
- $2(b^2)(-4b) = -8b^3$
- $2(b^2)(6) = 12b^2$
- $2(-4b)(6) = -48b$

Now combine:
$$
b^4 -8b^3 + (16b^2 + 12b^2) -48b + 36
= b^4 -8b^3 + 28b^2 -48b + 36
$$

Answer: $b^4 - 8b^3 + 28b^2 - 48b + 36$

---

18) $(7n^2 + 8n + 7)(7n^2 + n - 5)$



Distribute:

#### $7n^2(7n^2) = 49n^4$
$7n^2(n) = 7n^3$
$7n^2(-5) = -35n^2$

#### $8n(7n^2) = 56n^3$
$8n(n) = 8n^2$
$8n(-5) = -40n$

#### $7(7n^2) = 49n^2$
$7(n) = 7n$
$7(-5) = -35$

Now combine:

- $n^4$: $49n^4$
- $n^3$: $7n^3 + 56n^3 = 63n^3$
- $n^2$: $-35n^2 + 8n^2 + 49n^2 = 22n^2$
- $n$: $-40n + 7n = -33n$
- Constant: $-35$

Answer: $49n^4 + 63n^3 + 22n^2 - 33n - 35$

---

Final Answers Summary:



| Problem | Answer |
|--------|--------|
| 1 | $14r^2 + 35r + 21$ |
| 2 | $8b^2 - 34b - 30$ |
| 3 | $28n^2 + 62n + 30$ |
| 4 | $30x^2 + 63x + 24$ |
| 5 | $2a^2 - 12a - 14$ |
| 6 | $32v^3 + 52v^2 - 40v - 32$ |
| 7 | $5x^3 - 38x^2 + 16x + 35$ |
| 8 | $42x^3 - 22x^2 - 28x + 16$ |
| 9 | $9n^3 - 30n^2 + n + 10$ |
| 10 | $5k^3 - 25k^2 - 5k + 25$ |
| 11 | $4x^4 - 58x^2 + 30x + 24$ |
| 12 | $4p^4 - 24p^3 + 45p^2 - 19p - 24$ |
| 13 | $20n^4 - 18n^3 - 60n^2 + 42n + 16$ |
| 14 | $16m^4 + 80m^3 + 102m^2 + 56m + 12$ |
| 15 | $24x^4 - 38x^3 - 41x^2 + 48x + 7$ |
| 16 | $10r^4 + 29r^3 - 11r^2 - 42r + 8$ |
| 17 | $b^4 - 8b^3 + 28b^2 - 48b + 36$ |
| 18 | $49n^4 + 63n^3 + 22n^2 - 33n - 35$ |

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