Algebra worksheet for evaluating expressions with variable y.

To solve the given algebraic expressions when \( y = 2 \), we will substitute \( y = 2 \) into each expression and simplify step by step. Let's go through each problem:

---

1) \( 9y - 6 + 6y \)

Substitute \( y = 2 \):
\[
9(2) - 6 + 6(2)
\]

Simplify:
\[
18 - 6 + 12
\]

Combine terms:
\[
18 + 12 - 6 = 24
\]

Answer:
\[
\boxed{24}
\]

---

2) \( 9y + 3y + 4y \)

Combine like terms first:
\[
9y + 3y + 4y = 16y
\]

Substitute \( y = 2 \):
\[
16(2)
\]

Simplify:
\[
32
\]

Answer:
\[
\boxed{32}
\]

---

3) \( 6y - 1 + 4y \)

Combine like terms first:
\[
6y + 4y - 1 = 10y - 1
\]

Substitute \( y = 2 \):
\[
10(2) - 1
\]

Simplify:
\[
20 - 1 = 19
\]

Answer:
\[
\boxed{19}
\]

---

4) \( 4y + 4y + 5y \)

Combine like terms first:
\[
4y + 4y + 5y = 13y
\]

Substitute \( y = 2 \):
\[
13(2)
\]

Simplify:
\[
26
\]

Answer:
\[
\boxed{26}
\]

---

5) \( 4y + 7y - 3 \)

Combine like terms first:
\[
4y + 7y - 3 = 11y - 3
\]

Substitute \( y = 2 \):
\[
11(2) - 3
\]

Simplify:
\[
22 - 3 = 19
\]

Answer:
\[
\boxed{19}
\]

---

6) \( y + 5 + 5y \)

Combine like terms first:
\[
y + 5y + 5 = 6y + 5
\]

Substitute \( y = 2 \):
\[
6(2) + 5
\]

Simplify:
\[
12 + 5 = 17
\]

Answer:
\[
\boxed{17}
\]

---

7) \( y + 8 + 9y \)

Combine like terms first:
\[
y + 9y + 8 = 10y + 8
\]

Substitute \( y = 2 \):
\[
10(2) + 8
\]

Simplify:
\[
20 + 8 = 28
\]

Answer:
\[
\boxed{28}
\]

---

8) \( y + 3 - 2y \)

Combine like terms first:
\[
y - 2y + 3 = -y + 3
\]

Substitute \( y = 2 \):
\[
-(2) + 3
\]

Simplify:
\[
-2 + 3 = 1
\]

Answer:
\[
\boxed{1}
\]

---

9) \( 6y + 2y + 4y \)

Combine like terms first:
\[
6y + 2y + 4y = 12y
\]

Substitute \( y = 2 \):
\[
12(2)
\]

Simplify:
\[
24
\]

Answer:
\[
\boxed{24}
\]

---

10) \( y + 7 + 7y \)

Combine like terms first:
\[
y + 7y + 7 = 8y + 7
\]

Substitute \( y = 2 \):
\[
8(2) + 7
\]

Simplify:
\[
16 + 7 = 23
\]

Answer:
\[
\boxed{23}
\]

---

11) \( 9y + 6 - 9y \)

Combine like terms first:
\[
9y - 9y + 6 = 6
\]

Substitute \( y = 2 \) (though it doesn't affect the result since \( y \)-terms cancel out):
\[
6
\]

Answer:
\[
\boxed{6}
\]

---

12) \( y + 1 + 2y \)

Combine like terms first:
\[
y + 2y + 1 = 3y + 1
\]

Substitute \( y = 2 \):
\[
3(2) + 1
\]

Simplify:
\[
6 + 1 = 7
\]

Answer:
\[
\boxed{7}
\]

---

13) \( y + 3 - 3y \)

Combine like terms first:
\[
y - 3y + 3 = -2y + 3
\]

Substitute \( y = 2 \):
\[
-2(2) + 3
\]

Simplify:
\[
-4 + 3 = -1
\]

Answer:
\[
\boxed{-1}
\]

---

14) \( 5y + 4y - 3 \)

Combine like terms first:
\[
5y + 4y - 3 = 9y - 3
\]

Substitute \( y = 2 \):
\[
9(2) - 3
\]

Simplify:
\[
18 - 3 = 15
\]

Answer:
\[
\boxed{15}
\]

---

Final Answers:

1. \( \boxed{24} \)
2. \( \boxed{32} \)
3. \( \boxed{19} \)
4. \( \boxed{26} \)
5. \( \boxed{19} \)
6. \( \boxed{17} \)
7. \( \boxed{28} \)
8. \( \boxed{1} \)
9. \( \boxed{24} \)
10. \( \boxed{23} \)
11. \( \boxed{6} \)
12. \( \boxed{7} \)
13. \( \boxed{-1} \)
14. \( \boxed{15} \)

---

Thus, the final boxed answers are:
\[
\boxed{24, 32, 19, 26, 19, 17, 28, 1, 24, 23, 6, 7, -1, 15}
\]